我正在用PHP构建一个REST web服务客户端,目前我正在使用curl向服务发出请求。
我如何使用curl进行身份验证(http基本)请求?我必须自己添加标题吗?
我正在用PHP构建一个REST web服务客户端,目前我正在使用curl向服务发出请求。
我如何使用curl进行身份验证(http基本)请求?我必须自己添加标题吗?
当前回答
你只需要指定CURLOPT_HTTPAUTH和CURLOPT_USERPWD选项:
$curlHandler = curl_init();
$userName = 'postman';
$password = 'password';
curl_setopt_array($curlHandler, [
CURLOPT_URL => 'https://postman-echo.com/basic-auth',
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPAUTH => CURLAUTH_BASIC,
CURLOPT_USERPWD => $userName . ':' . $password,
]);
$response = curl_exec($curlHandler);
curl_close($curlHandler);
或者指定头文件:
$curlSecondHandler = curl_init();
curl_setopt_array($curlSecondHandler, [
CURLOPT_URL => 'https://postman-echo.com/basic-auth',
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPHEADER => [
'Authorization: Basic ' . base64_encode($userName . ':' . $password)
],
]);
$response = curl_exec($curlSecondHandler);
curl_close($curlSecondHandler);
狂饮的例子:
use GuzzleHttp\Client;
use GuzzleHttp\RequestOptions;
$userName = 'postman';
$password = 'password';
$httpClient = new Client();
$response = $httpClient->get(
'https://postman-echo.com/basic-auth',
[
RequestOptions::AUTH => [$userName, $password]
]
);
print_r($response->getBody()->getContents());
看到https://github.com/andriichuk/php-curl-cookbook基本认证
其他回答
如果授权类型是基本认证,并且发布的数据是json,那么这样做
<?php
$data = array("username" => "test"); // data u want to post
$data_string = json_encode($data);
$api_key = "your_api_key";
$password = "xxxxxx";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://xxxxxxxxxxxxxxxxxxxxxxx");
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 20);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERPWD, $api_key.':'.$password);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Accept: application/json',
'Content-Type: application/json')
);
if(curl_exec($ch) === false)
{
echo 'Curl error: ' . curl_error($ch);
}
$errors = curl_error($ch);
$result = curl_exec($ch);
$returnCode = (int)curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
echo $returnCode;
var_dump($errors);
print_r(json_decode($result, true));
CURLOPT_USERPWD基本上发送user:password字符串的base64,带有http头,如下所示:
Authorization: Basic dXNlcjpwYXNzd29yZA==
所以除了CURLOPT_USERPWD之外,你还可以使用HTTP-Request头选项,就像下面的其他头一样:
$headers = array(
'Content-Type:application/json',
'Authorization: Basic '. base64_encode("user:password") // <---
);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
Basic方法的另一种方法是:
$curl = curl_init();
$public_key = "public_key";
$private_key = "private_key";
curl_setopt_array($curl, array(
CURLOPT_URL => "https://url.endpoint.co/login",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 0,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "POST",
CURLOPT_HTTPHEADER => array(
"Content-Type: application/json",
"Authorization: Basic ".base64_encode($public_key.":".$private_key)
),
));
$response = curl_exec($curl);
curl_close($curl);
echo $response;
与SOAP不同,REST不是一个标准化的协议,因此拥有一个“REST客户端”有点困难。但是,由于大多数基于rest的服务使用HTTP作为其底层协议,因此您应该能够使用任何HTTP库。除了cURL, PHP还通过PEAR提供了以下功能:
HTTP_Request2
这所取代
HTTP_Request
一个他们如何做HTTP基本认证的例子
// This will set credentials for basic auth
$request = new HTTP_Request2('http://user:password@www.example.com/secret/');
也支持文摘认证
// This will set credentials for Digest auth
$request->setAuth('user', 'password', HTTP_Request2::AUTH_DIGEST);
对于那些不想使用curl的人:
//url
$url = 'some_url';
//Credentials
$client_id = "";
$client_pass= "";
//HTTP options
$opts = array('http' =>
array(
'method' => 'POST',
'header' => array ('Content-type: application/json', 'Authorization: Basic '.base64_encode("$client_id:$client_pass")),
'content' => "some_content"
)
);
//Do request
$context = stream_context_create($opts);
$json = file_get_contents($url, false, $context);
$result = json_decode($json, true);
if(json_last_error() != JSON_ERROR_NONE){
return null;
}
print_r($result);