我正在用PHP构建一个REST web服务客户端,目前我正在使用curl向服务发出请求。
我如何使用curl进行身份验证(http基本)请求?我必须自己添加标题吗?
我正在用PHP构建一个REST web服务客户端,目前我正在使用curl向服务发出请求。
我如何使用curl进行身份验证(http基本)请求?我必须自己添加标题吗?
当前回答
对于那些不想使用curl的人:
//url
$url = 'some_url';
//Credentials
$client_id = "";
$client_pass= "";
//HTTP options
$opts = array('http' =>
array(
'method' => 'POST',
'header' => array ('Content-type: application/json', 'Authorization: Basic '.base64_encode("$client_id:$client_pass")),
'content' => "some_content"
)
);
//Do request
$context = stream_context_create($opts);
$json = file_get_contents($url, false, $context);
$result = json_decode($json, true);
if(json_last_error() != JSON_ERROR_NONE){
return null;
}
print_r($result);
其他回答
Michael Dowling的《Guzzle》便是一个不错的选择。除了优雅的接口、异步调用和符合PSR,它还使REST调用的身份验证头非常简单:
// Create a client with a base URL
$client = new GuzzleHttp\Client(['base_url' => 'http://myservices.io']);
// Send a request to http://myservices.io/status with basic authentication
$response = $client->get('/status', ['auth' => ['username', 'password']]);
去看医生。
如果授权类型是基本认证,并且发布的数据是json,那么这样做
<?php
$data = array("username" => "test"); // data u want to post
$data_string = json_encode($data);
$api_key = "your_api_key";
$password = "xxxxxx";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://xxxxxxxxxxxxxxxxxxxxxxx");
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 20);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERPWD, $api_key.':'.$password);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Accept: application/json',
'Content-Type: application/json')
);
if(curl_exec($ch) === false)
{
echo 'Curl error: ' . curl_error($ch);
}
$errors = curl_error($ch);
$result = curl_exec($ch);
$returnCode = (int)curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
echo $returnCode;
var_dump($errors);
print_r(json_decode($result, true));
你只需要指定CURLOPT_HTTPAUTH和CURLOPT_USERPWD选项:
$curlHandler = curl_init();
$userName = 'postman';
$password = 'password';
curl_setopt_array($curlHandler, [
CURLOPT_URL => 'https://postman-echo.com/basic-auth',
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPAUTH => CURLAUTH_BASIC,
CURLOPT_USERPWD => $userName . ':' . $password,
]);
$response = curl_exec($curlHandler);
curl_close($curlHandler);
或者指定头文件:
$curlSecondHandler = curl_init();
curl_setopt_array($curlSecondHandler, [
CURLOPT_URL => 'https://postman-echo.com/basic-auth',
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPHEADER => [
'Authorization: Basic ' . base64_encode($userName . ':' . $password)
],
]);
$response = curl_exec($curlSecondHandler);
curl_close($curlSecondHandler);
狂饮的例子:
use GuzzleHttp\Client;
use GuzzleHttp\RequestOptions;
$userName = 'postman';
$password = 'password';
$httpClient = new Client();
$response = $httpClient->get(
'https://postman-echo.com/basic-auth',
[
RequestOptions::AUTH => [$userName, $password]
]
);
print_r($response->getBody()->getContents());
看到https://github.com/andriichuk/php-curl-cookbook基本认证
最简单、最自然的方法是直接使用CURL。
这对我来说很管用:
<?php
$login = 'login';
$password = 'password';
$url = 'http://your.url';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_USERPWD, "$login:$password");
$result = curl_exec($ch);
curl_close($ch);
echo($result);
Yahoo有一个使用PHP调用REST服务的教程:
让雅虎!使用PHP调用Web服务REST
我自己没有使用过,但雅虎就是雅虎,至少应该保证一定程度的质量。但是,它们似乎不包括PUT和DELETE请求。
另外,用户对curl_exec()和其他的贡献注释包含了很多好的信息。