以上解决方案都很好，但对我来说，我发现这段代码简单可行。 只需要创建一个临时文件。如果创建了该文件，则该文件的平均用户具有写权限。

        public static bool HasWritePermission(string tempfilepath)
        {
            try
            {
                System.IO.File.Create(tempfilepath + "temp.txt").Close();
                System.IO.File.Delete(tempfilepath + "temp.txt");
            }
            catch (System.UnauthorizedAccessException ex)
            {

                return false;
            }

            return true;
        }

Here is a modified version of CsabaS's answer, which accounts for explicit deny access rules. The function goes through all FileSystemAccessRules for a directory, and checks if the current user is in a role which has access to a directory. If no such roles are found or the user is in a role with denied access, the function returns false. To check read rights, pass FileSystemRights.Read to the function; for write rights, pass FileSystemRights.Write. If you want to check an arbitrary user's rights and not the current one's, substitute the currentUser WindowsIdentity for the desired WindowsIdentity. I would also advise against relying on functions like this to determine if the user can safely use the directory. This answer perfectly explains why.

    public static bool UserHasDirectoryAccessRights(string path, FileSystemRights accessRights)
    {
        var isInRoleWithAccess = false;

        try
        {
            var di = new DirectoryInfo(path);
            var acl = di.GetAccessControl();
            var rules = acl.GetAccessRules(true, true, typeof(NTAccount));

            var currentUser = WindowsIdentity.GetCurrent();
            var principal = new WindowsPrincipal(currentUser);
            foreach (AuthorizationRule rule in rules)
            {
                var fsAccessRule = rule as FileSystemAccessRule;
                if (fsAccessRule == null)
                    continue;

                if ((fsAccessRule.FileSystemRights & accessRights) > 0)
                {
                    var ntAccount = rule.IdentityReference as NTAccount;
                    if (ntAccount == null)
                        continue;

                    if (principal.IsInRole(ntAccount.Value))
                    {
                        if (fsAccessRule.AccessControlType == AccessControlType.Deny)
                            return false;
                        isInRoleWithAccess = true;
                    }
                }
            }
        }
        catch (UnauthorizedAccessException)
        {
            return false;
        }
        return isInRoleWithAccess;
    }

我无法让GetAccessControl()在Windows 7上抛出一个异常，就像接受的答案中建议的那样。

我最终使用了sdds的答案的变体:

        try
        {
            bool writeable = false;
            WindowsPrincipal principal = new WindowsPrincipal(WindowsIdentity.GetCurrent());
            DirectorySecurity security = Directory.GetAccessControl(pstrPath);
            AuthorizationRuleCollection authRules = security.GetAccessRules(true, true, typeof(SecurityIdentifier));

            foreach (FileSystemAccessRule accessRule in authRules)
            {

                if (principal.IsInRole(accessRule.IdentityReference as SecurityIdentifier))
                {
                    if ((FileSystemRights.WriteData & accessRule.FileSystemRights) == FileSystemRights.WriteData)
                    {
                        if (accessRule.AccessControlType == AccessControlType.Allow)
                        {
                            writeable = true;
                        }
                        else if (accessRule.AccessControlType == AccessControlType.Deny)
                        {
                            //Deny usually overrides any Allow
                            return false;
                        }

                    } 
                }
            }
            return writeable;
        }
        catch (UnauthorizedAccessException)
        {
            return false;
        }

希望这能有所帮助。

以我之见，唯一100%可靠的测试是否可以写入目录的方法是实际写入并最终捕获异常。

仅仅尝试访问有问题的文件是不够的。测试将在运行程序的用户的权限下运行——这并不一定是您想要测试的用户权限。

这是在c#中检查文件夹访问的一种非常有效的方法。它唯一可能失败的地方是，如果您需要在一个紧凑的循环中调用它，其中异常的开销可能是一个问题。

之前也有人问过类似的问题。