我已经创建了下一个字典:

var postJSON = [ids[0]:answersArray[0], ids[1]:answersArray[1], ids[2]:answersArray[2]] as Dictionary

得到:

[2: B, 1: A, 3: C]

那么,如何将其转换为JSON呢?


当前回答

斯威夫特3:

let jsonData = try? JSONSerialization.data(withJSONObject: dict, options: [])
let jsonString = String(data: jsonData!, encoding: .utf8)!
print(jsonString)

其他回答

我对你的问题的回答如下

let dict = ["0": "ArrayObjectOne", "1": "ArrayObjecttwo", "2": "ArrayObjectThree"]

var error : NSError?

let jsonData = try! NSJSONSerialization.dataWithJSONObject(dict, options: NSJSONWritingOptions.PrettyPrinted)

let jsonString = NSString(data: jsonData, encoding: String.Encoding.utf8.rawValue)! as String

print(jsonString)

答案是

{
  "0" : "ArrayObjectOne",
  "1" : "ArrayObjecttwo",
  "2" : "ArrayObjectThree"
}

你问题的答案如下:

斯威夫特2.1

     do {
          if let postData : NSData = try NSJSONSerialization.dataWithJSONObject(dictDataToBeConverted, options: NSJSONWritingOptions.PrettyPrinted){

          let json = NSString(data: postData, encoding: NSUTF8StringEncoding)! as String
          print(json)}

        }
        catch {
           print(error)
        }

有时为了调试目的,有必要打印出服务器的响应。下面是我使用的函数:

extension Dictionary {

    var json: String {
        let invalidJson = "Not a valid JSON"
        do {
            let jsonData = try JSONSerialization.data(withJSONObject: self, options: .prettyPrinted)
            return String(bytes: jsonData, encoding: String.Encoding.utf8) ?? invalidJson
        } catch {
            return invalidJson
        }
    }

    func printJson() {
        print(json)
    }

}

使用示例:

(lldb) po dictionary.printJson()
{
  "InviteId" : 2,
  "EventId" : 13591,
  "Messages" : [
    {
      "SenderUserId" : 9514,
      "MessageText" : "test",
      "RecipientUserId" : 9470
    },
    {
      "SenderUserId" : 9514,
      "MessageText" : "test",
      "RecipientUserId" : 9470
    }
  ],
  "TargetUserId" : 9470,
  "InvitedUsers" : [
    9470
  ],
  "InvitingUserId" : 9514,
  "WillGo" : true,
  "DateCreated" : "2016-08-24 14:01:08 +00:00"
}

你的假设是错误的。只是因为调试器/Playground用方括号显示你的字典(这是Cocoa显示字典的方式),这并不意味着这是JSON输出格式化的方式。

下面是将字符串字典转换为JSON的示例代码:

Swift 3版本:

import Foundation

let dictionary = ["aKey": "aValue", "anotherKey": "anotherValue"]
if let theJSONData = try? JSONSerialization.data(
    withJSONObject: dictionary,
    options: []) {
    let theJSONText = String(data: theJSONData,
                               encoding: .ascii)
    print("JSON string = \(theJSONText!)")
}

要以“漂亮打印”的格式显示上面的内容,你可以将选项行更改为:

    options: [.prettyPrinted]

或者在Swift 2语法中:

import Foundation
 
let dictionary = ["aKey": "aValue", "anotherKey": "anotherValue"]
let theJSONData = NSJSONSerialization.dataWithJSONObject(
  dictionary ,
  options: NSJSONWritingOptions(0),
  error: nil)
let theJSONText = NSString(data: theJSONData!,
  encoding: NSASCIIStringEncoding)
println("JSON string = \(theJSONText!)")

它的输出是

"JSON string = {"anotherKey":"anotherValue","aKey":"aValue"}"

或者用漂亮的格式:

{
  "anotherKey" : "anotherValue",
  "aKey" : "aValue"
}

正如您所期望的那样,在JSON输出中,字典用花括号括起来。

编辑:

在Swift 3/4语法中,上面的代码看起来像这样:

  let dictionary = ["aKey": "aValue", "anotherKey": "anotherValue"]
    if let theJSONData = try?  JSONSerialization.data(
      withJSONObject: dictionary,
      options: .prettyPrinted
      ),
      let theJSONText = String(data: theJSONData,
                               encoding: String.Encoding.ascii) {
          print("JSON string = \n\(theJSONText)")
    }
  }
private func convertDictToJson(dict : NSDictionary) -> NSDictionary?
{
    var jsonDict : NSDictionary!

    do {
        let jsonData = try JSONSerialization.data(withJSONObject:dict, options:[])
        let jsonDataString = String(data: jsonData, encoding: String.Encoding.utf8)!
        print("Post Request Params : \(jsonDataString)")
        jsonDict = [ParameterKey : jsonDataString]
        return jsonDict
    } catch {
        print("JSON serialization failed:  \(error)")
        jsonDict = nil
    }
    return jsonDict
}