这是一个简单的扩展来做到这一点:

https://gist.github.com/stevenojo/0cb8afcba721838b8dcb115b846727c3

extension Dictionary {
    func jsonString() -> NSString? {
        let jsonData = try? JSONSerialization.data(withJSONObject: self, options: [])
        guard jsonData != nil else {return nil}
        let jsonString = String(data: jsonData!, encoding: .utf8)
        guard jsonString != nil else {return nil}
        return jsonString! as NSString
    }

}

斯威夫特3.0

在Swift 3中，NSJSONSerialization的名字和它的方法已经改变了，根据Swift API设计指南。

let dic = ["2": "B", "1": "A", "3": "C"]

do {
    let jsonData = try JSONSerialization.data(withJSONObject: dic, options: .prettyPrinted)
    // here "jsonData" is the dictionary encoded in JSON data

    let decoded = try JSONSerialization.jsonObject(with: jsonData, options: [])
    // here "decoded" is of type `Any`, decoded from JSON data

    // you can now cast it with the right type        
    if let dictFromJSON = decoded as? [String:String] {
        // use dictFromJSON
    }
} catch {
    print(error.localizedDescription)
}

快2.倍

do {
    let jsonData = try NSJSONSerialization.dataWithJSONObject(dic, options: NSJSONWritingOptions.PrettyPrinted)
    // here "jsonData" is the dictionary encoded in JSON data

    let decoded = try NSJSONSerialization.JSONObjectWithData(jsonData, options: [])
    // here "decoded" is of type `AnyObject`, decoded from JSON data

    // you can now cast it with the right type 
    if let dictFromJSON = decoded as? [String:String] {
        // use dictFromJSON
    }
} catch let error as NSError {
    print(error)
}

斯威夫特1

var error: NSError?
if let jsonData = NSJSONSerialization.dataWithJSONObject(dic, options: NSJSONWritingOptions.PrettyPrinted, error: &error) {
    if error != nil {
        println(error)
    } else {
        // here "jsonData" is the dictionary encoded in JSON data
    }
}

if let decoded = NSJSONSerialization.JSONObjectWithData(jsonData, options: nil, error: &error) as? [String:String] {
    if error != nil {
        println(error)
    } else {
        // here "decoded" is the dictionary decoded from JSON data
    }
}

在Swift 5.4中

extension Dictionary {
    var jsonData: Data? {
        return try? JSONSerialization.data(withJSONObject: self, options: [.prettyPrinted])
    }
    
    func toJSONString() -> String? {
        if let jsonData = jsonData {
            let jsonString = String(data: jsonData, encoding: .utf8)
            return jsonString
        }
        
        return nil
    }
}

把它作为变量的想法是，这样你就可以像这样重用它:

extension Dictionary {
    func decode<T:Codable>() throws -> T {
        return try JSONDecoder().decode(T.self, from: jsonData ?? Data())
    }
}

你问题的答案如下:

斯威夫特2.1

     do {
          if let postData : NSData = try NSJSONSerialization.dataWithJSONObject(dictDataToBeConverted, options: NSJSONWritingOptions.PrettyPrinted){

          let json = NSString(data: postData, encoding: NSUTF8StringEncoding)! as String
          print(json)}

        }
        catch {
           print(error)
        }

你的假设是错误的。只是因为调试器/Playground用方括号显示你的字典(这是Cocoa显示字典的方式)，这并不意味着这是JSON输出格式化的方式。

下面是将字符串字典转换为JSON的示例代码:

Swift 3版本:

import Foundation

let dictionary = ["aKey": "aValue", "anotherKey": "anotherValue"]
if let theJSONData = try? JSONSerialization.data(
    withJSONObject: dictionary,
    options: []) {
    let theJSONText = String(data: theJSONData,
                               encoding: .ascii)
    print("JSON string = \(theJSONText!)")
}

要以“漂亮打印”的格式显示上面的内容，你可以将选项行更改为:

    options: [.prettyPrinted]

或者在Swift 2语法中:

import Foundation
 
let dictionary = ["aKey": "aValue", "anotherKey": "anotherValue"]
let theJSONData = NSJSONSerialization.dataWithJSONObject(
  dictionary ,
  options: NSJSONWritingOptions(0),
  error: nil)
let theJSONText = NSString(data: theJSONData!,
  encoding: NSASCIIStringEncoding)
println("JSON string = \(theJSONText!)")

它的输出是

"JSON string = {"anotherKey":"anotherValue","aKey":"aValue"}"

或者用漂亮的格式:

{
  "anotherKey" : "anotherValue",
  "aKey" : "aValue"
}

正如您所期望的那样，在JSON输出中，字典用花括号括起来。

编辑:

在Swift 3/4语法中，上面的代码看起来像这样:

  let dictionary = ["aKey": "aValue", "anotherKey": "anotherValue"]
    if let theJSONData = try?  JSONSerialization.data(
      withJSONObject: dictionary,
      options: .prettyPrinted
      ),
      let theJSONText = String(data: theJSONData,
                               encoding: String.Encoding.ascii) {
          print("JSON string = \n\(theJSONText)")
    }
  }

斯威夫特5:

let dic = ["2": "B", "1": "A", "3": "C"]
let encoder = JSONEncoder()
if let jsonData = try? encoder.encode(dic) {
    if let jsonString = String(data: jsonData, encoding: .utf8) {
        print(jsonString)
    }
}

注意键和值必须实现Codable。字符串、整型和双精度(以及更多)已经是可编码的。参见编码和解码自定义类型。

还要注意，Any不符合Codable。这可能仍然是一个很好的方法来调整你的数据成为可编码的，这样你就可以使用Swift类型(特别是在你也要解码任何编码的json的情况下)，这样你就可以更声明你的编码的结果。