我已经创建了下一个字典:

var postJSON = [ids[0]:answersArray[0], ids[1]:answersArray[1], ids[2]:answersArray[2]] as Dictionary

得到:

[2: B, 1: A, 3: C]

那么,如何将其转换为JSON呢?


当前回答

 do{
        let dataDict = [ "level" :
                            [
                                ["column" : 0,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
                                ["column" : 1,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
                                ["column" : 2,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
                                ["column" : 0,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0],
                                ["column" : 1,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0],
                                ["column" : 2,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0]
                            ]
        ]
        var jsonData = try JSONSerialization.data(withJSONObject: dataDict, options: JSONSerialization.WritingOptions.prettyPrinted)
        let jsonStringData =  NSString(data: jsonData as Data, encoding: NSUTF8StringEncoding)! as String
        print(jsonStringData)
    }catch{
        print(error.localizedDescription)
    }

其他回答

这是一个简单的扩展来做到这一点:

https://gist.github.com/stevenojo/0cb8afcba721838b8dcb115b846727c3

extension Dictionary {
    func jsonString() -> NSString? {
        let jsonData = try? JSONSerialization.data(withJSONObject: self, options: [])
        guard jsonData != nil else {return nil}
        let jsonString = String(data: jsonData!, encoding: .utf8)
        guard jsonString != nil else {return nil}
        return jsonString! as NSString
    }

}
 do{
        let dataDict = [ "level" :
                            [
                                ["column" : 0,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
                                ["column" : 1,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
                                ["column" : 2,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
                                ["column" : 0,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0],
                                ["column" : 1,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0],
                                ["column" : 2,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0]
                            ]
        ]
        var jsonData = try JSONSerialization.data(withJSONObject: dataDict, options: JSONSerialization.WritingOptions.prettyPrinted)
        let jsonStringData =  NSString(data: jsonData as Data, encoding: NSUTF8StringEncoding)! as String
        print(jsonStringData)
    }catch{
        print(error.localizedDescription)
    }

你问题的答案如下:

斯威夫特2.1

     do {
          if let postData : NSData = try NSJSONSerialization.dataWithJSONObject(dictDataToBeConverted, options: NSJSONWritingOptions.PrettyPrinted){

          let json = NSString(data: postData, encoding: NSUTF8StringEncoding)! as String
          print(json)}

        }
        catch {
           print(error)
        }

在Swift 5.4中

extension Dictionary {
    var jsonData: Data? {
        return try? JSONSerialization.data(withJSONObject: self, options: [.prettyPrinted])
    }
    
    func toJSONString() -> String? {
        if let jsonData = jsonData {
            let jsonString = String(data: jsonData, encoding: .utf8)
            return jsonString
        }
        
        return nil
    }
}

把它作为变量的想法是,这样你就可以像这样重用它:

extension Dictionary {
    func decode<T:Codable>() throws -> T {
        return try JSONDecoder().decode(T.self, from: jsonData ?? Data())
    }
}

Swift 4字典扩展。

extension Dictionary {
    var jsonStringRepresentation: String? {
        guard let theJSONData = try? JSONSerialization.data(withJSONObject: self,
                                                            options: [.prettyPrinted]) else {
            return nil
        }

        return String(data: theJSONData, encoding: .ascii)
    }
}