假设你有一些对象,它们有几个字段可以比较:

public class Person {

    private String firstName;
    private String lastName;
    private String age;

    /* Constructors */

    /* Methods */

}

所以在这个例子中,当你问if:

a.compareTo(b) > 0

你可能会问a的姓是不是在b的姓之前,或者a的年龄是不是比b大,等等……

在不增加不必要的混乱或开销的情况下,在这些类型的对象之间进行多重比较的最干净的方法是什么?

comparable接口只允许通过一个字段进行比较 在我看来,添加大量的比较方法(如compareByFirstName(), compareByAge()等)是混乱的。

那么最好的解决办法是什么呢?


当前回答

对于那些能够使用Java 8流API的人来说,这里有一个更整洁的方法: lambda和排序

我正在寻找相当于c# LINQ:

.ThenBy(...)

我在Comparator上找到了Java 8的机制:

.thenComparing(...)

下面是演示算法的代码片段。

    Comparator<Person> comparator = Comparator.comparing(person -> person.name);
    comparator = comparator.thenComparing(Comparator.comparing(person -> person.age));

请查看上面的链接,以获得更简洁的方法,并解释Java的类型推断如何使其与LINQ相比定义起来更笨拙。

下面是完整的单元测试供参考:

@Test
public void testChainedSorting()
{
    // Create the collection of people:
    ArrayList<Person> people = new ArrayList<>();
    people.add(new Person("Dan", 4));
    people.add(new Person("Andi", 2));
    people.add(new Person("Bob", 42));
    people.add(new Person("Debby", 3));
    people.add(new Person("Bob", 72));
    people.add(new Person("Barry", 20));
    people.add(new Person("Cathy", 40));
    people.add(new Person("Bob", 40));
    people.add(new Person("Barry", 50));

    // Define chained comparators:
    // Great article explaining this and how to make it even neater:
    // http://blog.jooq.org/2014/01/31/java-8-friday-goodies-lambdas-and-sorting/
    Comparator<Person> comparator = Comparator.comparing(person -> person.name);
    comparator = comparator.thenComparing(Comparator.comparing(person -> person.age));

    // Sort the stream:
    Stream<Person> personStream = people.stream().sorted(comparator);

    // Make sure that the output is as expected:
    List<Person> sortedPeople = personStream.collect(Collectors.toList());
    Assert.assertEquals("Andi",  sortedPeople.get(0).name); Assert.assertEquals(2,  sortedPeople.get(0).age);
    Assert.assertEquals("Barry", sortedPeople.get(1).name); Assert.assertEquals(20, sortedPeople.get(1).age);
    Assert.assertEquals("Barry", sortedPeople.get(2).name); Assert.assertEquals(50, sortedPeople.get(2).age);
    Assert.assertEquals("Bob",   sortedPeople.get(3).name); Assert.assertEquals(40, sortedPeople.get(3).age);
    Assert.assertEquals("Bob",   sortedPeople.get(4).name); Assert.assertEquals(42, sortedPeople.get(4).age);
    Assert.assertEquals("Bob",   sortedPeople.get(5).name); Assert.assertEquals(72, sortedPeople.get(5).age);
    Assert.assertEquals("Cathy", sortedPeople.get(6).name); Assert.assertEquals(40, sortedPeople.get(6).age);
    Assert.assertEquals("Dan",   sortedPeople.get(7).name); Assert.assertEquals(4,  sortedPeople.get(7).age);
    Assert.assertEquals("Debby", sortedPeople.get(8).name); Assert.assertEquals(3,  sortedPeople.get(8).age);
    // Andi     : 2
    // Barry    : 20
    // Barry    : 50
    // Bob      : 40
    // Bob      : 42
    // Bob      : 72
    // Cathy    : 40
    // Dan      : 4
    // Debby    : 3
}

/**
 * A person in our system.
 */
public static class Person
{
    /**
     * Creates a new person.
     * @param name The name of the person.
     * @param age The age of the person.
     */
    public Person(String name, int age)
    {
        this.age = age;
        this.name = name;
    }

    /**
     * The name of the person.
     */
    public String name;

    /**
     * The age of the person.
     */
    public int age;

    @Override
    public String toString()
    {
        if (name == null) return super.toString();
        else return String.format("%s : %d", this.name, this.age);
    }
}

其他回答

Java 8通过lambda方式我们可以通过方法引用进行比较。 学生POJO

public class Student {
int id;
String firstName;
String lastName;
String subject;

public Student(int id, String firstName, String lastName, String subject) {
    this.id = id;
    this.firstName = firstName;
    this.lastName = lastName;
    this.subject = subject;
}
enter code here

现在我们可以根据

1. id - > FirstName - > LastName - > 2。主题- > id - > FirstName - > LastName

我们将在数组Stream中使用Comparator

public class TestComprator {
public static void main(String[] args) {
    Student s1= new Student(108, "James", "Testo", "Physics");
    Student s2= new Student(101, "Fundu", "Barito", "Chem");
    Student s3= new Student(105, "Sindhu", "Sharan", "Math");
    Student s4= new Student(98, "Rechel", "Stephen", "Physics");
    System.out.printf("----------id->FirstName->LastName->Subject-------------");
    Arrays.asList(s1,s2,s3,s4).stream()
            .sorted(Comparator.comparing(Student::getId)
                    .thenComparing(Student::getFirstName)
                .thenComparing(Student::getLastName)
                .thenComparing(Student::getSubject))
            .forEach(System.out::println);

    System.out.printf("----Subject->id->FirstName->LastName ------\n");
    Arrays.asList(s1,s2,s3,s4).stream()
            .sorted(Comparator. comparing(Student::getSubject)
                    .thenComparing(Student::getId)
                    .thenComparing(Student::getFirstName)
                    .thenComparing(Student::getLastName)
                   )
            .forEach(System.out::println);
}

}

输出:

`----------id->FirstName->LastName->Subject-------------
Student{id=98, firstName='Rechel', lastName='Stephen', subject='Physics'}
Student{id=101, firstName='Fundu', lastName='Barito', subject='Chem'}
Student{id=105, firstName='Sindhu', lastName='Sharan', subject='Math'}
Student{id=108, firstName='James', lastName='Testo', subject='Physics'}
 ----Subject->id->FirstName->LastName ------
Student{id=101, firstName='Fundu', lastName='Barito', subject='Chem'}
Student{id=105, firstName='Sindhu', lastName='Sharan', subject='Math'}
Student{id=98, firstName='Rechel', lastName='Stephen', subject='Physics'}
Student{id=108, firstName='James', lastName='Testo', subject='Physics'}

如果用户有多种方式对人排序,你也可以在某个地方设置多个comparator常量。大多数排序操作和排序集合都以比较器作为参数。

//Following is the example in jdk 1.8
package com;
import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;

class User {
    private String firstName;
    private String lastName;
    private Integer age;

    public Integer getAge() {
        return age;
    }

    public User setAge(Integer age) {
        this.age = age;
        return this;
    }

    public String getFirstName() {
        return firstName;
    }

    public User setFirstName(String firstName) {
        this.firstName = firstName;
        return this;
    }

    public String getLastName() {
        return lastName;
    }

    public User setLastName(String lastName) {
        this.lastName = lastName;
        return this;
    }

}

public class MultiFieldsComparision {

    public static void main(String[] args) {
        List<User> users = new ArrayList<User>();

        User u1 = new User().setFirstName("Pawan").setLastName("Singh").setAge(38);
        User u2 = new User().setFirstName("Pawan").setLastName("Payal").setAge(37);
        User u3 = new User().setFirstName("Anuj").setLastName("Kumar").setAge(60);
        User u4 = new User().setFirstName("Anuj").setLastName("Kumar").setAge(43);
        User u5 = new User().setFirstName("Pawan").setLastName("Chamoli").setAge(44);
        User u6 = new User().setFirstName("Pawan").setLastName("Singh").setAge(5);

        users.add(u1);
        users.add(u2);
        users.add(u3);
        users.add(u4);
        users.add(u5);
        users.add(u6);

        System.out.println("****** Before Sorting ******");

        users.forEach(user -> {
            System.out.println(user.getFirstName() + " , " + user.getLastName() + " , " + user.getAge());
        });

        System.out.println("****** Aftre Sorting ******");

        users.sort(
                Comparator.comparing(User::getFirstName).thenComparing(User::getLastName).thenComparing(User::getAge));

        users.forEach(user -> {
            System.out.println(user.getFirstName() + " , " + user.getLastName() + " , " + user.getAge());
        });

    }

}

另一个可以考虑的选项是Apache Commons。它提供了很多选项。

import org.apache.commons.lang3.builder.CompareToBuilder;

Ex:

public int compare(Person a, Person b){

   return new CompareToBuilder()
     .append(a.getName(), b.getName())
     .append(a.getAddress(), b.getAddress())
     .toComparison();
}

如果我们必须基于多个字段对Person对象进行排序,则相同的代码实现在这里。

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;

public class Person {

private String firstName;
private String lastName;
private int age;

public String getFirstName() {
    return firstName;
}

public void setFirstName(String firstName) {
    this.firstName = firstName;
}

public String getLastName() {
    return lastName;
}

public void setLastName(String lastName) {
    this.lastName = lastName;
}

public int getAge() {
    return age;
}

public void setAge(int age) {
    this.age = age;
}

public Person(String firstName, String lastName, int age) {
    this.firstName = firstName;
    this.lastName = lastName;
    this.age = age;
}


static class PersonSortingComparator implements Comparator<Person> {

    @Override
    public int compare(Person person1, Person person2) {

        // for first name comparison
        int firstNameCompare = person1.getFirstName().compareTo(person2.getFirstName());

        // for last name comparison
        int lastNameCompare = person1.getLastName().compareTo(person2.getLastName());

        // for last name comparison
        int ageCompare = person1.getAge() - person2.getAge();

        // Now comparing
        if (firstNameCompare == 0) {
            if (lastNameCompare == 0) {
                return ageCompare;
            }
            return lastNameCompare;
        }
        return firstNameCompare;
    }
}

public static void main(String[] args) {
    Person person1 = new Person("Ajay", "Kumar", 27);
    Person person2 = new Person("Ajay","Gupta", 23);
    Person person3 = new Person("Ajay","Kumar", 22);


    ArrayList<Person> persons = new ArrayList<>();
    persons.add(person1);
    persons.add(person2);
    persons.add(person3);


    System.out.println("Before Sorting:\n");
    for (Person person : persons) {
        System.out.println(person.firstName + " " + person.lastName + " " + person.age);
    }

    Collections.sort(persons, new PersonSortingComparator());

    System.out.println("After Sorting:\n");
    for (Person person : persons) {
        System.out.println(person.firstName + " " + person.lastName + " " + person.age);
    }
}

}