AngularJS在为当前页面的链接设置一个活动类方面有任何帮助吗?

我想一定有什么神奇的方法可以做到,但我似乎找不到。

我的菜单是这样的:

 <ul>
   <li><a class="active" href="/tasks">Tasks</a>
   <li><a href="/actions">Tasks</a>
 </ul>

我在我的路由中为它们每个都有控制器:TasksController和ActionsController。

但是我想不出一种方法将a链接上的“活动”类绑定到控制器。

有提示吗?


当前回答

对于AngularUI路由器用户:

<a ui-sref-active="active" ui-sref="app">

这将在选中的对象上放置一个活动类。

其他回答

使用指令(因为我们在这里做的是DOM操作),下面可能是最接近“angular方式”的方法:

$scope.timeFilters = [
  {'value':3600,'label':'1 hour'},
  {'value':10800,'label':'3 hours'},
  {'value':21600,'label':'6 hours'},
  {'value':43200,'label':'12 hours'},
  {'value':86400,'label':'24 hours'},
  {'value':604800,'label':'1 week'}
]

angular.module('whatever', []).directive('filter',function(){
return{
    restrict: 'A',
    template: '<li ng-repeat="time in timeFilters" class="filterItem"><a ng-click="changeTimeFilter(time)">{{time.label}}</a></li>',
    link: function linkFn(scope, lElement, attrs){

        var menuContext = attrs.filter;

        scope.changeTimeFilter = function(newTime){
          scope.selectedtimefilter = newTime;

        }

        lElement.bind('click', function(cevent){
            var currentSelection = angular.element(cevent.srcElement).parent();
            var previousSelection = scope[menuContext];

            if(previousSelection !== currentSelection){
                if(previousSelection){
                    angular.element(previousSelection).removeClass('active')
                }
                scope[menuContext] = currentSelection;

                scope.$apply(function(){
                    currentSelection.addClass('active');
                })
            }
        })
    }
}
})

然后你的HTML看起来像这样:

<ul class="dropdown-menu" filter="times"></ul>

Here is the solution that I came up with after reading some of the excellent suggestions above. In my particular situation, I was trying to use Bootstrap tabs component as my menu, but didn't want to use the Angular-UI version of this because I want the tabs to act as a menu, where each tab is bookmark-able, rather than the tabs acting as navigation for a single page. (See http://angular-ui.github.io/bootstrap/#/tabs if you're interested in what the Angular-UI version of bootstrap tabs looks like).

I really liked kfis's answer about creating your own directive to handle this, however it seemed cumbersome to have a directive that needed to be placed on every single link. So I've created my own Angular directive which is placed instead once on the ul. Just in case any one else is trying to do the same thing, I thought I'd post it here, though as I said, many of the above solutions work as well. This is a slightly more complex solution as far as the javascript goes, but it creates a reusable component with minimal markup.

下面是指令的javascript和ng:view的路由提供程序:

var app = angular.module('plunker', ['ui.bootstrap']).
  config(['$routeProvider', function($routeProvider) {
    $routeProvider.
        when('/One', {templateUrl: 'one.html'}).
        when('/Two', {templateUrl: 'two.html'}).
        when('/Three', {templateUrl: 'three.html'}).
        otherwise({redirectTo: '/One'});
  }]).
  directive('navTabs', ['$location', function(location) {
    return {
        restrict: 'A',
        link: function(scope, element) {
            var $ul = $(element);
            $ul.addClass("nav nav-tabs");

            var $tabs = $ul.children();
            var tabMap = {};
            $tabs.each(function() {
              var $li = $(this);
              //Substring 1 to remove the # at the beginning (because location.path() below does not return the #)
              tabMap[$li.find('a').attr('href').substring(1)] = $li;
            });

            scope.location = location;
            scope.$watch('location.path()', function(newPath) {
                $tabs.removeClass("active");
                tabMap[newPath].addClass("active");
            });
        }

    };

 }]);

然后在你的html中你只需:

<ul nav-tabs>
  <li><a href="#/One">One</a></li>
  <li><a href="#/Two">Two</a></li>
  <li><a href="#/Three">Three</a></li>
</ul>
<ng:view><!-- Content will appear here --></ng:view>

这里是它的活塞:http://plnkr.co/edit/xwGtGqrT7kWoCKnGDHYN?p=preview。

使用Angular Version 6和Bootstrap 4.1

我能够做到如下所示。

在下面的例子中,当URL看到'/contact'时,引导活动就会被添加到html标记中。当URL改变时,它就会被删除。

<ul>
<li class="nav-item" routerLink="/contact" routerLinkActive="active">
    <a class="nav-link" href="/contact">Contact</a>
</li>
</ul>

这个指令允许你在链接的时候给元素添加一个CSS类 路由激活。

在Angular网站上阅读更多信息

这是我的意见,这很好。

注意:这与子页不匹配(这是我需要的)。

观点:

<a ng-class="{active: isCurrentLocation('/my-path')}"  href="/my-path" >
  Some link
</a>

控制器:

// make sure you inject $location as a dependency

$scope.isCurrentLocation = function(path){
    return path === $location.path()
}

这里是另一个突出显示活动链接的指令。

主要特点:

适用于包含动态角度表达式的href 兼容散列导航 与Bootstrap兼容,其中活动类应该应用到父li而不是链接本身 允许使链接活动,如果任何嵌套的路径是活动的 允许禁用make链接,如果它不是活动的

代码:

.directive('activeLink', ['$location', 
function($location) {
    return {
        restrict: 'A',
        link: function(scope, elem, attrs) {
            var path = attrs.activeLink ? 'activeLink' : 'href';
            var target = angular.isDefined(attrs.activeLinkParent) ? elem.parent() : elem;
            var disabled = angular.isDefined(attrs.activeLinkDisabled) ? true : false;
            var nested = angular.isDefined(attrs.activeLinkNested) ? true : false;

            function inPath(needle, haystack) {
                var current = (haystack == needle);
                if (nested) {
                    current |= (haystack.indexOf(needle + '/') == 0);
                }

                return current;
            }

            function toggleClass(linkPath, locationPath) {
                // remove hash prefix and trailing slashes
                linkPath = linkPath ? linkPath.replace(/^#!/, '').replace(/\/+$/, '') : '';
                locationPath = locationPath.replace(/\/+$/, '');

                if (linkPath && inPath(linkPath, locationPath)) {
                    target.addClass('active');
                    if (disabled) {
                        target.removeClass('disabled');
                    }
                } else {
                    target.removeClass('active');
                    if (disabled) {
                        target.addClass('disabled');
                    }
                }
            }

            // watch if attribute value changes / evaluated
            attrs.$observe(path, function(linkPath) {
                toggleClass(linkPath, $location.path());
            });

            // watch if location changes
            scope.$watch(
                function() {
                    return $location.path(); 
                }, 
                function(newPath) {
                    toggleClass(attrs[path], newPath);
                }
            );
        }
    };
}
]);

用法:

angular表达式的简单例子,让我们输入$scope。Var = 2,那么链接将是活跃的,如果位置是/url/2:

<a href="#!/url/{{var}}" active-link>

Bootstrap示例,parent li将获得活动类:

<li>
    <a href="#!/url" active-link active-link-parent>
</li>

以嵌套url为例,如果任何嵌套url是活动的,链接将是活动的(即/url/1, /url/2, url/1/2/…)

<a href="#!/url" active-link active-link-nested>

复杂的例子,链接指向一个url (/url1),但如果选择另一个url (/url2)将是活动的:

<a href="#!/url1" active-link="#!/url2" active-link-nested>

以禁用链接为例,如果它不是活动的,它将有'disabled'类:

<a href="#!/url" active-link active-link-disabled>

所有active-link-*属性都可以在任何组合中使用,因此可以实现非常复杂的条件。