有人知道在Go中漂亮打印JSON输出的简单方法吗?

我想漂亮地打印json的结果。Marshal,以及格式化现有的JSON字符串,以便更容易阅读。


当前回答

//You can do it with json.MarshalIndent(data, "", "  ")

package main

import(
  "fmt"
  "encoding/json" //Import package
)

//Create struct
type Users struct {
    ID   int
    NAME string
}

//Asign struct
var user []Users
func main() {
 //Append data to variable user
 user = append(user, Users{1, "Saturn Rings"})
 //Use json package the blank spaces are for the indent
 data, _ := json.MarshalIndent(user, "", "  ")
 //Print json formatted
 fmt.Println(string(data))
}

其他回答

MarshalIndent将允许您输出带有缩进和间距的JSON。例如:

{
    "data": 1234
}

缩进参数指定要缩进的字符序列。因此,json。MarshalIndent(data, "", "")将使用四个空格进行缩进。

回头看,这是非惯用的围棋。像这样的小助手函数增加了额外的复杂性。一般来说,围棋哲学倾向于包含3条简单的线,而不是1条棘手的线。


正如@robyoder提到的,json。缩进才是正确的选择。我想添加这个小的prettyprint函数:

package main

import (
    "bytes"
    "encoding/json"
    "fmt"
)

//dont do this, see above edit
func prettyprint(b []byte) ([]byte, error) {
    var out bytes.Buffer
    err := json.Indent(&out, b, "", "  ")
    return out.Bytes(), err
}

func main() {
    b := []byte(`{"hello": "123"}`)
    b, _ = prettyprint(b)
    fmt.Printf("%s", b)
}

https://go-sandbox.com/#/R4LWpkkHIN或http://play.golang.org/p/R4LWpkkHIN

使用json。带字符串的MarshalIndent

这个easyPrint函数接受参数数据(任何类型的数据),并将其打印成预期的(漂亮的)JSON格式。

import (
  "encoding/json"
  "log"
)

func easyPrint(data interface{}) {
  manifestJson, _ := json.MarshalIndent(data, "", "  ")

  log.Println(string(manifestJson))
}

使用name参数。

TODO:使参数名可选。

func easyPrint(data interface{}, name string) {
  manifestJson, _ := json.MarshalIndent(data, "", "  ")

  log.Println(name + " ->", string(manifestJson))
}
package cube

import (
    "encoding/json"
    "fmt"
    "github.com/magiconair/properties/assert"
    "k8s.io/api/rbac/v1beta1"
    v1 "k8s.io/apimachinery/pkg/apis/meta/v1"
    "testing"
)

func TestRole(t *testing.T)  {
    clusterRoleBind := &v1beta1.ClusterRoleBinding{
        ObjectMeta: v1.ObjectMeta{
            Name: "serviceaccounts-cluster-admin",
        },
        RoleRef: v1beta1.RoleRef{
            APIGroup: "rbac.authorization.k8s.io",
            Kind:     "ClusterRole",
            Name:     "cluster-admin",
        },
        Subjects: []v1beta1.Subject{{
            Kind:     "Group",
            APIGroup: "rbac.authorization.k8s.io",
            Name:     "system:serviceaccounts",
        },
        },
    }
    b, err := json.MarshalIndent(clusterRoleBind, "", "  ")
    assert.Equal(t, nil, err)
    fmt.Println(string(b))
}

这是我用的。如果它不能漂亮地打印JSON,它只返回原始字符串。用于打印应该包含JSON的HTTP响应。

import (
    "encoding/json"
    "bytes"
)

func jsonPrettyPrint(in string) string {
    var out bytes.Buffer
    err := json.Indent(&out, []byte(in), "", "\t")
    if err != nil {
        return in
    }
    return out.String()
}