有人知道在Go中漂亮打印JSON输出的简单方法吗?
我想漂亮地打印json的结果。Marshal,以及格式化现有的JSON字符串,以便更容易阅读。
有人知道在Go中漂亮打印JSON输出的简单方法吗?
我想漂亮地打印json的结果。Marshal,以及格式化现有的JSON字符串,以便更容易阅读。
当前回答
这是我用的。如果它不能漂亮地打印JSON,它只返回原始字符串。用于打印应该包含JSON的HTTP响应。
import (
"encoding/json"
"bytes"
)
func jsonPrettyPrint(in string) string {
var out bytes.Buffer
err := json.Indent(&out, []byte(in), "", "\t")
if err != nil {
return in
}
return out.String()
}
其他回答
我是一个新手,但这是我目前为止收集到的:
package srf
import (
"bytes"
"encoding/json"
"os"
)
func WriteDataToFileAsJSON(data interface{}, filedir string) (int, error) {
//write data as buffer to json encoder
buffer := new(bytes.Buffer)
encoder := json.NewEncoder(buffer)
encoder.SetIndent("", "\t")
err := encoder.Encode(data)
if err != nil {
return 0, err
}
file, err := os.OpenFile(filedir, os.O_RDWR|os.O_CREATE, 0755)
if err != nil {
return 0, err
}
n, err := file.Write(buffer.Bytes())
if err != nil {
return 0, err
}
return n, nil
}
这是函数的执行,而且是标准的
b, _ := json.MarshalIndent(SomeType, "", "\t")
代码:
package main
import (
"encoding/json"
"fmt"
"io/ioutil"
"log"
minerals "./minerals"
srf "./srf"
)
func main() {
//array of Test struct
var SomeType [10]minerals.Test
//Create 10 units of some random data to write
for a := 0; a < 10; a++ {
SomeType[a] = minerals.Test{
Name: "Rand",
Id: 123,
A: "desc",
Num: 999,
Link: "somelink",
People: []string{"John Doe", "Aby Daby"},
}
}
//writes aditional data to existing file, or creates a new file
n, err := srf.WriteDataToFileAsJSON(SomeType, "test2.json")
if err != nil {
log.Fatal(err)
}
fmt.Println("srf printed ", n, " bytes to ", "test2.json")
//overrides previous file
b, _ := json.MarshalIndent(SomeType, "", "\t")
ioutil.WriteFile("test.json", b, 0644)
}
MarshalIndent将允许您输出带有缩进和间距的JSON。例如:
{
"data": 1234
}
缩进参数指定要缩进的字符序列。因此,json。MarshalIndent(data, "", "")将使用四个空格进行缩进。
package cube
import (
"encoding/json"
"fmt"
"github.com/magiconair/properties/assert"
"k8s.io/api/rbac/v1beta1"
v1 "k8s.io/apimachinery/pkg/apis/meta/v1"
"testing"
)
func TestRole(t *testing.T) {
clusterRoleBind := &v1beta1.ClusterRoleBinding{
ObjectMeta: v1.ObjectMeta{
Name: "serviceaccounts-cluster-admin",
},
RoleRef: v1beta1.RoleRef{
APIGroup: "rbac.authorization.k8s.io",
Kind: "ClusterRole",
Name: "cluster-admin",
},
Subjects: []v1beta1.Subject{{
Kind: "Group",
APIGroup: "rbac.authorization.k8s.io",
Name: "system:serviceaccounts",
},
},
}
b, err := json.MarshalIndent(clusterRoleBind, "", " ")
assert.Equal(t, nil, err)
fmt.Println(string(b))
}
如果您想将一个对象转换为JSON,那么接受的答案是非常好的。这个问题还提到了漂亮打印任何JSON字符串,这就是我试图做的。我只是想从POST请求(特别是CSP违反报告)漂亮地记录一些JSON。
要使用MarshalIndent,必须将其解编组到一个对象中。如果你需要,那就去吧,但我不需要。如果你只是需要漂亮地打印一个字节数组,普通缩进是你的朋友。
这是我最后得出的结论:
import (
"bytes"
"encoding/json"
"log"
"net/http"
)
func HandleCSPViolationRequest(w http.ResponseWriter, req *http.Request) {
body := App.MustReadBody(req, w)
if body == nil {
return
}
var prettyJSON bytes.Buffer
error := json.Indent(&prettyJSON, body, "", "\t")
if error != nil {
log.Println("JSON parse error: ", error)
App.BadRequest(w)
return
}
log.Println("CSP Violation:", string(prettyJSON.Bytes()))
}
responsewriter的另一个例子。
import (
"encoding/json"
"net/http"
)
func main() {
var w http.ResponseWriter
type About struct {
ProgName string
Version string
}
goObj := About{ProgName: "demo", Version: "0.0.0"}
beautifulJsonByte, err := json.MarshalIndent(goObj, "", " ")
if err != nil {
panic(err)
}
_, _ = w.Write(beautifulJsonByte)
}
输出
{
"ProgName": "demo",
"Version": "0.0.0"
}