我们需要YouTube的频道名称的视频列表(使用API)。

我们可以通过下面的API获得一个频道列表(只有频道名):

https://gdata.youtube.com/feeds/api/channels?v=2&q=tendulkar

下面是频道的直接链接

https://www.youtube.com/channel/UCqAEtEr0A0Eo2IVcuWBfB9g

Or

WWW.YouTube.com/channel/HC-8jgBP-4rlI

现在,我们需要>> UCqAEtEr0A0Eo2IVcuWBfB9g或HC-8jgBP-4rlI频道的视频。

我们尝试

https://gdata.youtube.com/feeds/api/videos?v=2&uploader=partner&User=UC7Xayrf2k0NZiz3S04WuDNQ https://gdata.youtube.com/feeds/api/videos?v=2&uploader=partner&q=UC7Xayrf2k0NZiz3S04WuDNQ

但是,这并没有帮助。

我们需要把所有视频发到频道上。上传到一个频道的视频可以来自多个用户,因此我不认为提供用户参数会有帮助…


当前回答

下面是返回频道下所有视频id的代码

<?php 
    $baseUrl = 'https://www.googleapis.com/youtube/v3/';
    // https://developers.google.com/youtube/v3/getting-started
    $apiKey = 'API_KEY';
    // If you don't know the channel ID see below
    $channelId = 'CHANNEL_ID';

    $params = [
        'id'=> $channelId,
        'part'=> 'contentDetails',
        'key'=> $apiKey
    ];
    $url = $baseUrl . 'channels?' . http_build_query($params);
    $json = json_decode(file_get_contents($url), true);

    $playlist = $json['items'][0]['contentDetails']['relatedPlaylists']['uploads'];

    $params = [
        'part'=> 'snippet',
        'playlistId' => $playlist,
        'maxResults'=> '50',
        'key'=> $apiKey
    ];
    $url = $baseUrl . 'playlistItems?' . http_build_query($params);
    $json = json_decode(file_get_contents($url), true);

    $videos = [];
    foreach($json['items'] as $video)
        $videos[] = $video['snippet']['resourceId']['videoId'];

    while(isset($json['nextPageToken'])){
        $nextUrl = $url . '&pageToken=' . $json['nextPageToken'];
        $json = json_decode(file_get_contents($nextUrl), true);
        foreach($json['items'] as $video)
            $videos[] = $video['snippet']['resourceId']['videoId'];
    }
    print_r($videos);

注意:你可以在 登录https://www.youtube.com/account_advanced。

其他回答

只需三步:

订阅:list -> https://www.googleapis.com/youtube/v3/subscriptions?part=snippet&maxResults=50&mine=true&access_token= {oauth_token} 通道:list -> https://www.googleapis.com/youtube/v3/channels?part=contentDetails&id= {channel_id}关键= {YOUR_API_KEY} PlaylistItems: list -> https://www.googleapis.com/youtube/v3/playlistItems?part=snippet&playlistId= {playlist_id}关键= {YOUR_API_KEY}

从https://stackoverflow.com/a/65440501/2585501:

如果a)该频道有超过50个视频,或者b)希望将youtube视频id格式化为平面txt列表,则此方法特别有用:

Obtain a Youtube API v3 key (see https://stackoverflow.com/a/65440324/2585501) Obtain the Youtube Channel ID of the channel (see https://stackoverflow.com/a/16326307/2585501) Obtain the Uploads Playlist ID of the channel: https://www.googleapis.com/youtube/v3/channels?id={channel Id}&key={API key}&part=contentDetails (based on https://www.youtube.com/watch?v=RjUlmco7v2M) Install youtube-dl (e.g. pip3 install --upgrade youtube-dl or sudo apt-get install youtube-dl) Download the Uploads Playlist using youtube-dl: youtube-dl -j --flat-playlist "https://<yourYoutubePlaylist>" | jq -r '.id' | sed 's_^_https://youtu.be/_' > videoList.txt (see https://superuser.com/questions/1341684/youtube-dl-how-download-only-the-playlist-not-the-files-therein)

Python中的示例解决方案。从这个视频中得到帮助:视频 与许多其他答案一样,上传id首先从通道id中检索。

import urllib.request
import json

key = "YOUR_YOUTUBE_API_v3_BROWSER_KEY"

#List of channels : mention if you are pasting channel id or username - "id" or "forUsername"
ytids = [["bbcnews","forUsername"],["UCjq4pjKj9X4W9i7UnYShpVg","id"]]

newstitles = []
for ytid,ytparam in ytids:
    urld = "https://www.googleapis.com/youtube/v3/channels?part=contentDetails&"+ytparam+"="+ytid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())
    uploadsdet = datad['items']
    #get upload id from channel id
    uploadid = uploadsdet[0]['contentDetails']['relatedPlaylists']['uploads']

    #retrieve list
    urld = "https://www.googleapis.com/youtube/v3/playlistItems?part=snippet%2CcontentDetails&maxResults=50&playlistId="+uploadid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())

    for data in datad['items']:
        ntitle =  data['snippet']['title']
        nlink = data['contentDetails']['videoId']
        newstitles.append([nlink,ntitle])

for link,title in newstitles:
    print(link, title)

下面是一个来自谷歌开发者的视频,展示了如何在YouTube API的v3中列出一个频道中的所有视频。

有两个步骤:

查询Channels以获得“uploads”Id。例如https://www.googleapis.com/youtube/v3/channels?id={channel Id}&key={API key}&part=contentDetails 使用这个“uploads”Id查询PlaylistItems以获得视频列表。例如https://www.googleapis.com/youtube/v3/playlistItems?playlistId={"uploads" Id}&key={API key}&part=snippet&maxResults=50

下面是一个不需要任何特殊包的Python替代方案。通过提供频道id,它将返回该频道的视频链接列表。请注意,你需要一个API密钥为它工作。

import urllib
import json

def get_all_video_in_channel(channel_id):
    api_key = YOUR API KEY

    base_video_url = 'https://www.youtube.com/watch?v='
    base_search_url = 'https://www.googleapis.com/youtube/v3/search?'

    first_url = base_search_url+'key={}&channelId={}&part=snippet,id&order=date&maxResults=25'.format(api_key, channel_id)

    video_links = []
    url = first_url
    while True:
        inp = urllib.urlopen(url)
        resp = json.load(inp)

        for i in resp['items']:
            if i['id']['kind'] == "youtube#video":
                video_links.append(base_video_url + i['id']['videoId'])

        try:
            next_page_token = resp['nextPageToken']
            url = first_url + '&pageToken={}'.format(next_page_token)
        except:
            break
    return video_links