获取频道列表:

通过forUserName获取频道列表:

https://www.googleapis.com/youtube/v3/channels?part=snippet,contentDetails,statistics&forUsername=Apple&key=

按频道id获取频道列表:

https://www.googleapis.com/youtube/v3/channels/?part=snippet,contentDetails,statistics&id=UCE_M8A5yxnLfW0KghEeajjw&key=

获取通道部分:

https://www.googleapis.com/youtube/v3/channelSections?part=snippet,contentDetails&channelId=UCE_M8A5yxnLfW0KghEeajjw&key=

获取播放列表:

按频道ID获取播放列表:

https://www.googleapis.com/youtube/v3/playlists?part=snippet,contentDetails&channelId=UCq-Fj5jknLsUf-MWSy4_brA&maxResults=50&key=

使用pageToken通过频道ID获取播放列表:

https://www.googleapis.com/youtube/v3/playlists?part=snippet,contentDetails&channelId=UCq-Fj5jknLsUf-MWSy4_brA&maxResults=50&key=&pageToken=CDIQAA

获取PlaylistItems:

通过PlayListId获取PlaylistItems列表:

https://www.googleapis.com/youtube/v3/playlistItems?part=snippet,contentDetails&maxResults=25&playlistId=PLHFlHpPjgk70Yv3kxQvkDEO5n5tMQia5I&key=

获取视频:

通过视频id获取视频列表:

https://www.googleapis.com/youtube/v3/videos?part=snippet,contentDetails,statistics&id=YxLCwfA1cLw&key=

通过多个视频id获取视频列表:

https://www.googleapis.com/youtube/v3/videos?part=snippet,contentDetails,statistics&id=YxLCwfA1cLw,Qgy6LaO3SB0,7yPJXGO2Dcw&key=

获取评论列表

按视频ID获取评论列表:

https://www.googleapis.com/youtube/v3/commentThreads?part=snippet replies&videoId = el * * * * kQak&key = ********** k

按频道ID获取评论列表:

https://www.googleapis.com/youtube/v3/commentThreads?part=snippet replies&channelId = U * * * * * q键= AI * * * * * * * * k

通过allThreadsRelatedToChannelId获取评论列表:

https://www.googleapis.com/youtube/v3/commentThreads?part=snippet replies&allThreadsRelatedToChannelId =加州大学* * * * * ntcQ&key = AI * * * * * k

这里所有的api都是Get方法。

基于频道id，我们不能直接得到所有的视频，这是这里的重点。

对于集成https://developers.google.com/youtube/v3/quickstart/ios?ver=swift

Python中的示例解决方案。从这个视频中得到帮助:视频 与许多其他答案一样，上传id首先从通道id中检索。

import urllib.request
import json

key = "YOUR_YOUTUBE_API_v3_BROWSER_KEY"

#List of channels : mention if you are pasting channel id or username - "id" or "forUsername"
ytids = [["bbcnews","forUsername"],["UCjq4pjKj9X4W9i7UnYShpVg","id"]]

newstitles = []
for ytid,ytparam in ytids:
    urld = "https://www.googleapis.com/youtube/v3/channels?part=contentDetails&"+ytparam+"="+ytid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())
    uploadsdet = datad['items']
    #get upload id from channel id
    uploadid = uploadsdet[0]['contentDetails']['relatedPlaylists']['uploads']

    #retrieve list
    urld = "https://www.googleapis.com/youtube/v3/playlistItems?part=snippet%2CcontentDetails&maxResults=50&playlistId="+uploadid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())

    for data in datad['items']:
        ntitle =  data['snippet']['title']
        nlink = data['contentDetails']['videoId']
        newstitles.append([nlink,ntitle])

for link,title in newstitles:
    print(link, title)

最近，我不得不从一个频道检索所有视频，根据YouTube开发者文档: https://developers.google.com/youtube/v3/docs/playlistItems/list

function playlistItemsListByPlaylistId($service, $part, $params) {
    $params = array_filter($params);
    $response = $service->playlistItems->listPlaylistItems(
        $part,
        $params
    );

    print_r($response);
}

playlistItemsListByPlaylistId($service,
    'snippet,contentDetails',
    array('maxResults' => 25, 'playlistId' => 'id of "uploads" playlist'));

$service是Google_Service_YouTube对象。

因此，您必须从频道获取信息以检索“uploads”播放列表，该列表实际上包含该频道上传的所有视频:https://developers.google.com/youtube/v3/docs/channels/list

如果这个API是新的，我强烈建议将代码样例从默认代码片段转换为完整的样例。

因此，从一个频道检索所有视频的基本代码可以是:

class YouTube
{
    const       DEV_KEY = 'YOUR_DEVELOPPER_KEY';
    private     $client;
    private     $youtube;
    private     $lastChannel;

    public function __construct()
    {
        $this->client = new Google_Client();
        $this->client->setDeveloperKey(self::DEV_KEY);
        $this->youtube = new Google_Service_YouTube($this->client);
        $this->lastChannel = false;
    }

    public function getChannelInfoFromName($channel_name)
    {
        if ($this->lastChannel && $this->lastChannel['modelData']['items'][0]['snippet']['title'] == $channel_name)
        {
            return $this->lastChannel;
        }
        $this->lastChannel = $this->youtube->channels->listChannels('snippet, contentDetails, statistics', array(
            'forUsername' => $channel_name,
        ));
        return ($this->lastChannel);
    }

    public function getVideosFromChannelName($channel_name, $max_result = 5)
    {
        $this->getChannelInfoFromName($channel_name);
        $params = [
            'playlistId' => $this->lastChannel['modelData']['items'][0]['contentDetails']['relatedPlaylists']['uploads'],
            'maxResults'=> $max_result,
        ];
        return ($this->youtube->playlistItems->listPlaylistItems('snippet,contentDetails', $params));
    }
}

$yt = new YouTube();
echo '<pre>' . print_r($yt->getVideosFromChannelName('CHANNEL_NAME'), true) . '</pre>';

使用gapi JavaScript API可以做到这一点

<script src="https://apis.google.com/js/api.js"></script>

const start = () => {
  gapi.client
    .init({
      apiKey: "your_youtubeApiKey",
      discoveryDocs: ["https://www.googleapis.com/discovery/v1/apis/youtube/v3/rest"],
      scope: "https://www.googleapis.com/auth/youtube.readonly",
    })
    .then(() => {
      console.log("gapi.client initiated");
    })
    .then(() =>
      gapi.client.youtube.channels.list({
        part: "snippet,contentDetails,statistics",
        id: "youtube_channelId",
        // forUsername: 'Bankless',
      })
    )
    .then(
      (res) =>
        // get the youtube related playlist id
        res.result.items[0].contentDetails.relatedPlaylists.uploads
    )
    .then((playlistId) =>
      gapi.client.youtube.playlistItems.list({
        part: "snippet",
        playlistId,
        maxResults: 50,
      })
    )
    .then((res) =>
      // get youtube videos snippets
      res.result.items.map((item) => item.snippet)
    )
    .then((snippets) =>
      snippets.map((snippet) => {
        const { title, description, resourceId } = snippet;
        const { videoId } = resourceId;
        return { title, description, videoId };
      })
    )
    .then((videos) => {
      console.log(videos);
    })
    .catch((err) => console.error(err));
};
gapi.load("client", start);

文档:

https://github.com/google/google-api-javascript-client https://developers.google.com/youtube/v3/guides/auth/client-side-web-apps#callinganapi

从https://stackoverflow.com/a/65440501/2585501:

如果a)该频道有超过50个视频，或者b)希望将youtube视频id格式化为平面txt列表，则此方法特别有用:

Obtain a Youtube API v3 key (see https://stackoverflow.com/a/65440324/2585501) Obtain the Youtube Channel ID of the channel (see https://stackoverflow.com/a/16326307/2585501) Obtain the Uploads Playlist ID of the channel: https://www.googleapis.com/youtube/v3/channels?id={channel Id}&key={API key}&part=contentDetails (based on https://www.youtube.com/watch?v=RjUlmco7v2M) Install youtube-dl (e.g. pip3 install --upgrade youtube-dl or sudo apt-get install youtube-dl) Download the Uploads Playlist using youtube-dl: youtube-dl -j --flat-playlist "https://<yourYoutubePlaylist>" | jq -r '.id' | sed 's_^_https://youtu.be/_' > videoList.txt (see https://superuser.com/questions/1341684/youtube-dl-how-download-only-the-playlist-not-the-files-therein)

简短的回答:

这里有一个叫做scrapetube的库，可以帮你解决这个问题。

PIP安装刮刀管

import scrapetube

videos = scrapetube.get_channel("UC9-y-6csu5WGm29I7JiwpnA")

for video in videos:
    print(video['videoId'])

长一点的回答:

上面提到的模块是由我创建的，因为没有任何其他解决方案。以下是我的尝试:

硒。它很有效，但有三个大缺点:它需要安装网络浏览器和驱动程序。2. 对CPU和内存的需求很大。3.不能处理大频道。 使用youtube-dl。是这样的:

import youtube_dl
    youtube_dl_options = {
        'skip_download': True,
        'ignoreerrors': True
    }
    with youtube_dl.YoutubeDL(youtube_dl_options) as ydl:
        videos = ydl.extract_info(f'https://www.youtube.com/channel/{channel_id}/videos')

这也适用于小的频道，但对于更大的频道，我会被youtube屏蔽，因为在这么短的时间内发出这么多的请求(因为youtube-dl下载了更多的信息，每个视频在频道)。

所以我做了图书馆scrapetube使用web API来获得所有的视频。