如何在以下列表中搜索包含字符串“abc”的项目?

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:

if 'abc' in xs:

当前回答

只是抛出这个:如果你恰好需要匹配多个字符串,例如abc和def,你可以按如下方式组合两个理解:

matchers = ['abc','def']
matching = [s for s in my_list if any(xs in s for xs in matchers)]

输出:

['abc-123', 'def-456', 'abc-456']

其他回答

def find_dog(new_ls):
    splt = new_ls.split()
    if 'dog' in splt:
        print("True")
    else:
        print('False')


find_dog("Is there a dog here?")

我是Python新手。我得到了下面的代码,使其易于理解:

my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
    if 'abc' in item:
       print(item)

将nan添加到列表中,以下内容适用于我:

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456',np.nan]
any([i for i in [x for x in some_list if str(x) != 'nan'] if "abc" in i])
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

for item in my_list:
    if (item.find('abc')) != -1:
        print ('Found at ', item)

我需要与以下匹配项对应的列表索引:

lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']

[n for n, x in enumerate(lst) if 'abc' in x]

输出

[0, 3]