my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

for item in my_list:
    if (item.find('abc')) != -1:
        print ('Found at ', item)

def find_dog(new_ls):
    splt = new_ls.split()
    if 'dog' in splt:
        print("True")
    else:
        print('False')


find_dog("Is there a dog here?")

要检查列表中任何字符串中是否存在“abc”，请执行以下操作：

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

if any("abc" in s for s in xs):
    ...

要获取包含“abc”的所有项目：

matching = [s for s in xs if "abc" in s]

只是抛出这个：如果你恰好需要匹配多个字符串，例如abc和def，你可以按如下方式组合两个理解：

matchers = ['abc','def']
matching = [s for s in my_list if any(xs in s for xs in matchers)]

输出：

['abc-123', 'def-456', 'abc-456']

使用筛选器获取具有“abc”的所有元素：

>>> xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
>>> list(filter(lambda x: 'abc' in x, xs))
['abc-123', 'abc-456']

还可以使用列表理解：

>>> [x for x in xs if 'abc' in x]

将nan添加到列表中，以下内容适用于我：

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456',np.nan]
any([i for i in [x for x in some_list if str(x) != 'nan'] if "abc" in i])