我有两种方法:

if let thisShape = aShape as? Square 

Or:

aShape.isKindOfClass(Square)

下面是一个详细的例子:

class Shape { }
class Square: Shape { } 
class Circle: Shape { }

var aShape = Shape()
aShape = Square()

if let thisShape = aShape as? Square {
    println("Its a square")
} else {
    println("Its not a square")
}

if aShape.isKindOfClass(Square) {
    println("Its a square")
} else {
    println("Its not a square")
}

编辑:3现在:

let myShape = Shape()
if myShape is Shape {
    print("yes it is")
}

为什么不使用专门为此任务构建的内置功能呢?

let myArray: [Any] = ["easy", "as", "that"]
let type = type(of: myArray)

Result: "Array<Any>"

swift4:

if obj is MyClass{
    // then object type is MyClass Type
}

myObject一样吗?如果myObject不是String, String返回nil。否则，它返回一个字符串?，所以你可以使用myObject访问字符串本身!，或者使用myObject强制转换它!作为字符串安全。

let originalArray : [Any?] = ["Hello", "World", 111, 2, nil, 3.34]
let strings = originalArray.compactMap({ $0 as? String })

print(strings)
//printed: ["Hello", "World"]

假设drawTriangle是UIView的一个实例。检查drawTriangle是否为UITableView类型:

在Swift 3中，

if drawTriangle is UITableView{
    // in deed drawTriangle is UIView
    // do something here...
} else{
    // do something here...
}

这也可以用于你自己定义的类。你可以用它来检查视图的子视图。