Swift 5.2 & Xcode版本:11.3.1(11C504)

以下是我检查数据类型的解决方案:

 if let typeCheck = myResult as? [String : Any] {
        print("It's Dictionary.")
    } else { 
        print("It's not Dictionary.") 
    }

我希望它能帮助你。

为什么不使用专门为此任务构建的内置功能呢?

let myArray: [Any] = ["easy", "as", "that"]
let type = type(of: myArray)

Result: "Array<Any>"

斯威夫特3:

class Shape {}
class Circle : Shape {}
class Rectangle : Shape {}

if aShape.isKind(of: Circle.self) {
}

为什么不用这样的东西呢

fileprivate enum types {
    case typeString
    case typeInt
    case typeDouble
    case typeUnknown
}

fileprivate func typeOfAny(variable: Any) -> types {
    if variable is String {return types.typeString}
    if variable is Int {return types.typeInt}
    if variable is Double {return types.typeDouble}
    return types.typeUnknown
}

在Swift 3中。

let originalArray : [Any?] = ["Hello", "World", 111, 2, nil, 3.34]
let strings = originalArray.compactMap({ $0 as? String })

print(strings)
//printed: ["Hello", "World"]

请注意:

var string = "Hello" as NSString
var obj1:AnyObject = string
var obj2:NSObject = string

print(obj1 is NSString)
print(obj2 is NSString)
print(obj1 is String)
print(obj2 is String) 

最后四行都返回true，这是因为如果你输入

var r1:CGRect = CGRect()
print(r1 is String)

．.． 它打印“假”当然，但警告说，Cast从CGRect到字符串失败。因此有些类型是桥接的，'is'关键字调用隐式强制转换。

你最好使用其中的一个:

myObject.isKind(of: MyClass.self)) 
myObject.isMember(of: MyClass.self))