我想达到这样的效果:
def foo():
try:
raise IOError('Stuff ')
except:
raise
def bar(arg1):
try:
foo()
except Exception as e:
e.message = e.message + 'happens at %s' % arg1
raise
bar('arg1')
Traceback...
IOError('Stuff Happens at arg1')
但我得到的是:
Traceback..
IOError('Stuff')
关于如何实现这一点，有什么线索吗?如何在Python 2和3中都做到这一点?
当前回答
到目前为止，我对所有给出的答案都不满意。他们还是太啰嗦了。在代码和消息输出中。
所有我想要的是stacktrace指向源异常，没有异常之间的东西，所以没有创建新的异常，只是重新提升原始与所有相关的堆栈帧状态在它，导致那里。
史蒂夫·霍华德给出了一个很好的答案，我想扩展一下，不，是简化一下……仅适用于python 3。
except Exception as e:
e.args = ("Some failure state", *e.args)
raise
唯一的新东西是参数展开/解包，这使得它对我来说足够小和容易使用。
试一试:
foo = None
try:
try:
state = "bar"
foo.append(state)
except Exception as e:
e.args = ("Appending '"+state+"' failed", *e.args)
raise
print(foo[0]) # would raise too
except Exception as e:
e.args = ("print(foo) failed: " + str(foo), *e.args)
raise
这将给你:
Traceback (most recent call last):
File "test.py", line 6, in <module>
foo.append(state)
AttributeError: ('print(foo) failed: None', "Appending 'bar' failed", "'NoneType' object has no attribute 'append'")
简单的漂亮图案可以是这样的
print("\n".join( "-"*i+" "+j for i,j in enumerate(e.args)))
其他回答
假设你不想或不能修改foo()，你可以这样做:
try:
raise IOError('stuff')
except Exception as e:
if len(e.args) >= 1:
e.args = (e.args[0] + ' happens',) + e.args[1:]
raise
这确实是在Python 3中解决问题的唯一解决方案，而不会出现丑陋而令人困惑的“在处理上述异常期间，发生了另一个异常”消息。
如果要将重新提升的行添加到堆栈跟踪中，则应该写入raise e而不是raise。
到目前为止，我对所有给出的答案都不满意。他们还是太啰嗦了。在代码和消息输出中。
所有我想要的是stacktrace指向源异常，没有异常之间的东西，所以没有创建新的异常，只是重新提升原始与所有相关的堆栈帧状态在它，导致那里。
史蒂夫·霍华德给出了一个很好的答案，我想扩展一下，不，是简化一下……仅适用于python 3。
except Exception as e:
e.args = ("Some failure state", *e.args)
raise
唯一的新东西是参数展开/解包，这使得它对我来说足够小和容易使用。
试一试:
foo = None
try:
try:
state = "bar"
foo.append(state)
except Exception as e:
e.args = ("Appending '"+state+"' failed", *e.args)
raise
print(foo[0]) # would raise too
except Exception as e:
e.args = ("print(foo) failed: " + str(foo), *e.args)
raise
这将给你:
Traceback (most recent call last):
File "test.py", line 6, in <module>
foo.append(state)
AttributeError: ('print(foo) failed: None', "Appending 'bar' failed", "'NoneType' object has no attribute 'append'")
简单的漂亮图案可以是这样的
print("\n".join( "-"*i+" "+j for i,j in enumerate(e.args)))
以下是我在个人项目中使用的方法(我相信有足够的理由不在产品代码中这样做):
try:
#something hazardous
except Exception as e:
insightful_message = "shouldn't have done that"
amended_args = tuple([f'{e.args[0]}\n{insightful_message}', *e.args[1:]])
e.args = amended_args
raise
代码(1)拦截错误;(2)创建错误的.args属性的副本，这是一个元组，假定在索引0处包含一个错误消息，使用列表理解实现;(3)在错误消息后追加换行符和自定义消息;(4)使用。args附加到副本的任何附加项 拆包;(5)将副本转换为元组;最后(6)用修改后的副本替换。args。
这些操作大多是为了避免.args元组的不可变性。
我在代码中使用:
try:
a=1
b=0
c=a/b
except:
raise Exception(f"can't divide {a} with {b}")
输出:
---------------------------------------------------------------------------
ZeroDivisionError Traceback (most recent call last)
~\AppData\Local\Temp/ipykernel_11708/1469673756.py in <module>
3 b=0
----> 4 c=a/b
5
ZeroDivisionError: division by zero
During handling of the above exception, another exception occurred:
Exception Traceback (most recent call last)
~\AppData\Local\Temp/ipykernel_11708/1469673756.py in <module>
5
6 except Exception:
----> 7 raise Exception(f"can't divide {a} with {b}")
Exception: can't divide 1 with 0
这是我的实现，使用它作为上下文管理器，并可选地添加额外的消息异常:
from typing import Optional, Type
from types import TracebackType
class _addInfoOnException():
def __init__(self, info: str = ""):
self.info = info
def __enter__(self):
return
def __exit__(self,
exc_type: Optional[Type[BaseException]],
exc_val: BaseException, # Optional, but not None if exc_type is not None
exc_tb: TracebackType): # Optional, but not None if exc_type is not None
if exc_type:
if self.info:
newMsg = f"{self.info}\n\tLow level error: "
if len(exc_val.args) == 0:
exc_val.args = (self.info, )
elif len(exc_val.args) == 1:
exc_val.args = (f"{newMsg}{exc_val.args[0]}", )
elif len(exc_val.args) > 0:
exc_val.args = (f"{newMsg}{exc_val.args[0]}", exc_val.args[1:])
raise
用法:
def main():
try:
raise Exception("Example exception msg")
except Exception:
traceback.print_exc()
print("\n\n")
try:
with _addInfoOnException():
raise Exception("Example exception msg, no extra info")
except Exception:
traceback.print_exc()
print("\n\n")
try:
with _addInfoOnException("Some extra info!"):
raise Exception("Example exception msg")
except Exception:
traceback.print_exc()
print("\n\n")
if __name__ == "__main__":
main()
这将在这样的跟踪中解决:
Traceback (most recent call last):
File "<...>\VSCodeDevWorkspace\testis.py", line 40, in main
raise Exception("Example exception msg")
Exception: Example exception msg
Traceback (most recent call last):
File "<...>\VSCodeDevWorkspace\testis.py", line 47, in main
raise Exception("Example exception msg, no extra info")
File "<...>\VSCodeDevWorkspace\testis.py", line 47, in main
raise Exception("Example exception msg, no extra info")
Exception: Example exception msg, no extra info
Traceback (most recent call last):
File "<...>\VSCodeDevWorkspace\testis.py", line 54, in main
raise Exception("Example exception msg")
File "<...>\VSCodeDevWorkspace\testis.py", line 54, in main
raise Exception("Example exception msg")
Exception: Some extra info!
Low level error: Example exception msg
