我想达到这样的效果:

def foo():
   try:
       raise IOError('Stuff ')
   except:
       raise

def bar(arg1):
    try:
       foo()
    except Exception as e:
       e.message = e.message + 'happens at %s' % arg1
       raise

bar('arg1')
Traceback...
  IOError('Stuff Happens at arg1')

但我得到的是:

Traceback..
  IOError('Stuff')

关于如何实现这一点,有什么线索吗?如何在Python 2和3中都做到这一点?


当前回答

在PEP 678中,本机支持向异常添加注释:

try:
  raise TypeError('bad type')
except Exception as e:
  e.add_note('Add some information')
  raise

呈现为:

Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
TypeError: bad type
Add some information

我跳它可以取代史蒂夫霍华德的解决方案,不幸的是,它不给用户任何控制如何格式化最终的异常(例如,不能在异常之前添加一个注释,如:'错误在fn: {original_exc}')

如果想要对回溯进行更多控制,可以使用https://github.com/google/etils:

from etils import epy

with epy.maybe_reraise('Error in fn: '):
  fn()

Or:

try:
  fn()
except Exception as e:
  epy.reraise(e, suffix='. Did you mean y ?')

其他回答

我会这样做,这样在foo()中改变它的类型就不需要在bar()中也改变它。

def foo():
    try:
        raise IOError('Stuff')
    except:
        raise

def bar(arg1):
    try:
        foo()
    except Exception as e:
        raise type(e)(e.message + ' happens at %s' % arg1)

bar('arg1')

Traceback (most recent call last):
  File "test.py", line 13, in <module>
    bar('arg1')
  File "test.py", line 11, in bar
    raise type(e)(e.message + ' happens at %s' % arg1)
IOError: Stuff happens at arg1

更新1

这里有一个轻微的修改,保留了原始的回溯:

...
def bar(arg1):
    try:
        foo()
    except Exception as e:
        import sys
        raise type(e), type(e)(e.message +
                               ' happens at %s' % arg1), sys.exc_info()[2]

bar('arg1')

Traceback (most recent call last):
  File "test.py", line 16, in <module>
    bar('arg1')
  File "test.py", line 11, in bar
    foo()
  File "test.py", line 5, in foo
    raise IOError('Stuff')
IOError: Stuff happens at arg1

更新2

对于Python 3。在2012-05-16对PEP 352的修改中(我的第一次更新发布于2012-03-12),我的第一次更新中的代码在语法上是错误的,加上在BaseException上有消息属性的想法被撤销了。因此,目前在Python 3.5.2中,您需要按照这些行做一些事情来保留回溯,而不是在函数栏()中硬编码异常的类型。还要注意,会有这样一行:

During handling of the above exception, another exception occurred:

在显示的回溯消息中。

# for Python 3.x
...
def bar(arg1):
    try:
        foo()
    except Exception as e:
        import sys
        raise type(e)(str(e) +
                      ' happens at %s' % arg1).with_traceback(sys.exc_info()[2])

bar('arg1')

更新3

一位评论者询问是否有一种方法可以同时在Python 2和3中工作。尽管由于语法差异,答案似乎是“否”,但有一种解决方法,即使用six外接组件模块中的rerraise()等帮助函数。因此,如果您出于某种原因不想使用这个库,下面是一个简化的独立版本。

还要注意,由于异常是在rerraise()函数中重新引发的,因此无论引发什么跟踪,都会出现异常,但最终结果是您想要的结果。

import sys

if sys.version_info.major < 3:  # Python 2?
    # Using exec avoids a SyntaxError in Python 3.
    exec("""def reraise(exc_type, exc_value, exc_traceback=None):
                raise exc_type, exc_value, exc_traceback""")
else:
    def reraise(exc_type, exc_value, exc_traceback=None):
        if exc_value is None:
            exc_value = exc_type()
        if exc_value.__traceback__ is not exc_traceback:
            raise exc_value.with_traceback(exc_traceback)
        raise exc_value

def foo():
    try:
        raise IOError('Stuff')
    except:
        raise

def bar(arg1):
    try:
       foo()
    except Exception as e:
        reraise(type(e), type(e)(str(e) +
                                 ' happens at %s' % arg1), sys.exc_info()[2])

bar('arg1')

以下是我在个人项目中使用的方法(我相信有足够的理由不在产品代码中这样做):

try:
    #something hazardous
except Exception as e:
    insightful_message = "shouldn't have done that"
    amended_args = tuple([f'{e.args[0]}\n{insightful_message}', *e.args[1:]])
    e.args = amended_args
    raise

代码(1)拦截错误;(2)创建错误的.args属性的副本,这是一个元组,假定在索引0处包含一个错误消息,使用列表理解实现;(3)在错误消息后追加换行符和自定义消息;(4)使用。args附加到副本的任何附加项 拆包;(5)将副本转换为元组;最后(6)用修改后的副本替换。args。

这些操作大多是为了避免.args元组的不可变性。

也许

except Exception as e:
    raise IOError(e.message + 'happens at %s'%arg1)

到目前为止,我对所有给出的答案都不满意。他们还是太啰嗦了。在代码和消息输出中。

所有我想要的是stacktrace指向源异常,没有异常之间的东西,所以没有创建新的异常,只是重新提升原始与所有相关的堆栈帧状态在它,导致那里。

史蒂夫·霍华德给出了一个很好的答案,我想扩展一下,不,是简化一下……仅适用于python 3。

except Exception as e:
    e.args = ("Some failure state", *e.args)
    raise

唯一的新东西是参数展开/解包,这使得它对我来说足够小和容易使用。

试一试:

foo = None

try:
    try:
        state = "bar"
        foo.append(state)

    except Exception as e:
        e.args = ("Appending '"+state+"' failed", *e.args)
        raise

    print(foo[0]) # would raise too

except Exception as e:
    e.args = ("print(foo) failed: " + str(foo), *e.args)
    raise

这将给你:

Traceback (most recent call last):
  File "test.py", line 6, in <module>
    foo.append(state)
AttributeError: ('print(foo) failed: None', "Appending 'bar' failed", "'NoneType' object has no attribute 'append'")

简单的漂亮图案可以是这样的

print("\n".join( "-"*i+" "+j for i,j in enumerate(e.args)))

这是我的实现,使用它作为上下文管理器,并可选地添加额外的消息异常:

from typing import Optional, Type
from types import TracebackType

class _addInfoOnException():
    def __init__(self, info: str = ""):
        self.info = info

    def __enter__(self):
        return

    def __exit__(self,
                 exc_type: Optional[Type[BaseException]],
                 exc_val: BaseException,  # Optional, but not None if exc_type is not None
                 exc_tb: TracebackType):  # Optional, but not None if exc_type is not None
        if exc_type:
            if self.info:
                newMsg = f"{self.info}\n\tLow level error: "
                if len(exc_val.args) == 0:
                    exc_val.args = (self.info, )
                elif len(exc_val.args) == 1:
                    exc_val.args = (f"{newMsg}{exc_val.args[0]}", )
                elif len(exc_val.args) > 0:
                    exc_val.args = (f"{newMsg}{exc_val.args[0]}", exc_val.args[1:])
            raise

用法:

def main():
    try:
        raise Exception("Example exception msg")
    except Exception:
        traceback.print_exc()
        print("\n\n")

    try:
        with _addInfoOnException():
            raise Exception("Example exception msg, no extra info")
    except Exception:
        traceback.print_exc()
        print("\n\n")

    try:
        with _addInfoOnException("Some extra info!"):
            raise Exception("Example exception msg")
    except Exception:
        traceback.print_exc()
        print("\n\n")


if __name__ == "__main__":
    main()

这将在这样的跟踪中解决:

Traceback (most recent call last):
  File "<...>\VSCodeDevWorkspace\testis.py", line 40, in main
    raise Exception("Example exception msg")
Exception: Example exception msg



Traceback (most recent call last):
  File "<...>\VSCodeDevWorkspace\testis.py", line 47, in main
    raise Exception("Example exception msg, no extra info")
  File "<...>\VSCodeDevWorkspace\testis.py", line 47, in main
    raise Exception("Example exception msg, no extra info")
Exception: Example exception msg, no extra info



Traceback (most recent call last):
  File "<...>\VSCodeDevWorkspace\testis.py", line 54, in main
    raise Exception("Example exception msg")
  File "<...>\VSCodeDevWorkspace\testis.py", line 54, in main
    raise Exception("Example exception msg")
Exception: Some extra info!
        Low level error: Example exception msg