我有2-3个不同的列名，我想在整个数据库中查找，并列出所有具有这些列的表。有没有简单的脚本?
当前回答
SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE '%city_id%' AND TABLE_SCHEMA='database'
其他回答
更简单地用一行SQL语句完成:
SELECT * FROM information_schema.columns WHERE column_name = 'column_name';
SELECT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME LIKE '%wild%';
select distinct table_name
from information_schema.columns
where column_name in ('ColumnA')
and table_schema='YourDatabase';
and table_name in
(
select distinct table_name
from information_schema.columns
where column_name in ('ColumnB')
and table_schema='YourDatabase';
);
这^^将得到表的列na和ColumnB，而不是列na或ColumnB，就像接受的答案
使用这一行查询。将desired_column_name替换为列名。
SELECT TABLE_NAME FROM information_schema.columns WHERE column_name = 'desired_column_name';
对于那些与此相反的搜索，即寻找不包含特定列名的表，这里是查询…
SELECT DISTINCT TABLE_NAME FROM information_schema.columns WHERE
TABLE_SCHEMA = 'your_db_name' AND TABLE_NAME NOT IN (SELECT DISTINCT
TABLE_NAME FROM information_schema.columns WHERE column_name =
'column_name' AND TABLE_SCHEMA = 'your_db_name');
当我们开始缓慢地实现InnoDB特殊的ai_col列的使用，并需要找出200个表中哪些表还没有升级时，这真的很方便。
