information_schema的问题是它可能非常慢。使用SHOW命令速度更快。

选择数据库后，首先发送查询SHOW TABLES。然后对每个表执行SHOW COLUMNS。

在PHP中是这样的

    $res = mysqli_query("SHOW TABLES");
    while($row = mysqli_fetch_array($res))
    {   $rs2 = mysqli_query("SHOW COLUMNS FROM ".$row[0]);
        while($rw2 = mysqli_fetch_array($rs2))
        {   if($rw2[0] == $target)
               ....
        }
    }

SELECT DISTINCT TABLE_NAME, COLUMN_NAME  
FROM INFORMATION_SCHEMA.COLUMNS  
WHERE column_name LIKE 'employee%'  
AND TABLE_SCHEMA='YourDatabase'

如果你想“只获取所有的表”，那么使用这个查询:

SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME like '%'
and TABLE_SCHEMA = 'tresbu_lk'

如果你想“获取所有带列的表”，那么使用这个查询:

SELECT DISTINCT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name LIKE '%'
AND TABLE_SCHEMA='tresbu_lk'

更简单地用一行SQL语句完成:

SELECT * FROM information_schema.columns WHERE column_name = 'column_name';

使用这一行查询。将desired_column_name替换为列名。

SELECT TABLE_NAME FROM information_schema.columns WHERE column_name = 'desired_column_name';

select distinct table_name 
from information_schema.columns 
where column_name in ('ColumnA') 
    and table_schema='YourDatabase';
    and table_name in 
    (
        select distinct table_name 
        from information_schema.columns 
        where column_name in ('ColumnB')
              and table_schema='YourDatabase';
    );

这^^将得到表的列na和ColumnB，而不是列na或ColumnB，就像接受的答案