我有2-3个不同的列名，我想在整个数据库中查找，并列出所有具有这些列的表。有没有简单的脚本?
当前回答
information_schema的问题是它可能非常慢。使用SHOW命令速度更快。
选择数据库后，首先发送查询SHOW TABLES。然后对每个表执行SHOW COLUMNS。
在PHP中是这样的
$res = mysqli_query("SHOW TABLES");
while($row = mysqli_fetch_array($res))
{ $rs2 = mysqli_query("SHOW COLUMNS FROM ".$row[0]);
while($rw2 = mysqli_fetch_array($rs2))
{ if($rw2[0] == $target)
....
}
}
其他回答
SELECT DISTINCT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name LIKE 'employee%'
AND TABLE_SCHEMA='YourDatabase'
SELECT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME LIKE '%wild%';
select distinct table_name
from information_schema.columns
where column_name in ('ColumnA')
and table_schema='YourDatabase';
and table_name in
(
select distinct table_name
from information_schema.columns
where column_name in ('ColumnB')
and table_schema='YourDatabase';
);
这^^将得到表的列na和ColumnB，而不是列na或ColumnB，就像接受的答案
获取数据库YourDatabase中所有列为columnna或ColumnB的表:
SELECT DISTINCT TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME IN ('columnA','ColumnB')
AND TABLE_SCHEMA='YourDatabase';
一个简单的方法:
SELECT *
FROM information_schema.columns
WHERE column_name = 'column_name';
