我有2-3个不同的列名,我想在整个数据库中查找,并列出所有具有这些列的表。有没有简单的脚本?
当前回答
对于那些与此相反的搜索,即寻找不包含特定列名的表,这里是查询…
SELECT DISTINCT TABLE_NAME FROM information_schema.columns WHERE
TABLE_SCHEMA = 'your_db_name' AND TABLE_NAME NOT IN (SELECT DISTINCT
TABLE_NAME FROM information_schema.columns WHERE column_name =
'column_name' AND TABLE_SCHEMA = 'your_db_name');
当我们开始缓慢地实现InnoDB特殊的ai_col列的使用,并需要找出200个表中哪些表还没有升级时,这真的很方便。
其他回答
更简单地用一行SQL语句完成:
SELECT * FROM information_schema.columns WHERE column_name = 'column_name';
如果你想“只获取所有的表”,那么使用这个查询:
SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME like '%'
and TABLE_SCHEMA = 'tresbu_lk'
如果你想“获取所有带列的表”,那么使用这个查询:
SELECT DISTINCT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name LIKE '%'
AND TABLE_SCHEMA='tresbu_lk'
SELECT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME LIKE '%wild%';
select distinct table_name
from information_schema.columns
where column_name in ('ColumnA')
and table_schema='YourDatabase';
and table_name in
(
select distinct table_name
from information_schema.columns
where column_name in ('ColumnB')
and table_schema='YourDatabase';
);
这^^将得到表的列na和ColumnB,而不是列na或ColumnB,就像接受的答案
SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE '%city_id%' AND TABLE_SCHEMA='database'