select distinct table_name 
from information_schema.columns 
where column_name in ('ColumnA') 
    and table_schema='YourDatabase';
    and table_name in 
    (
        select distinct table_name 
        from information_schema.columns 
        where column_name in ('ColumnB')
              and table_schema='YourDatabase';
    );

这^^将得到表的列na和ColumnB，而不是列na或ColumnB，就像接受的答案

select distinct table_name 
from information_schema.columns 
where column_name in ('ColumnA') 
    and table_schema='YourDatabase';
    and table_name in 
    (
        select distinct table_name 
        from information_schema.columns 
        where column_name in ('ColumnB')
              and table_schema='YourDatabase';
    );

这^^将得到表的列na和ColumnB，而不是列na或ColumnB，就像接受的答案

一个简单的方法:

SELECT *
FROM information_schema.columns
WHERE column_name = 'column_name';

information_schema的问题是它可能非常慢。使用SHOW命令速度更快。

选择数据库后，首先发送查询SHOW TABLES。然后对每个表执行SHOW COLUMNS。

在PHP中是这样的

    $res = mysqli_query("SHOW TABLES");
    while($row = mysqli_fetch_array($res))
    {   $rs2 = mysqli_query("SHOW COLUMNS FROM ".$row[0]);
        while($rw2 = mysqli_fetch_array($rs2))
        {   if($rw2[0] == $target)
               ....
        }
    }

对于那些与此相反的搜索，即寻找不包含特定列名的表，这里是查询…

SELECT DISTINCT TABLE_NAME FROM information_schema.columns WHERE 
TABLE_SCHEMA = 'your_db_name' AND TABLE_NAME NOT IN (SELECT DISTINCT 
TABLE_NAME FROM information_schema.columns WHERE column_name = 
'column_name' AND TABLE_SCHEMA = 'your_db_name');

当我们开始缓慢地实现InnoDB特殊的ai_col列的使用，并需要找出200个表中哪些表还没有升级时，这真的很方便。

如果你想“只获取所有的表”，那么使用这个查询:

SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME like '%'
and TABLE_SCHEMA = 'tresbu_lk'

如果你想“获取所有带列的表”，那么使用这个查询:

SELECT DISTINCT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name LIKE '%'
AND TABLE_SCHEMA='tresbu_lk'