实际上,我想读取搜索查询之后的内容,当它完成时。问题是URL只接受POST方法,它不采取任何行动与GET方法…

我必须在domdocument或file_get_contents()的帮助下读取所有内容。有没有什么方法可以让我用POST方法发送参数,然后通过PHP读取内容?


当前回答

这里有这样的代码:

<?php
$postdata = http_build_query(
    array(
        'name' => 'Robert',
        'id' => '1'
    )
);
$opts = array('http' =>
    array(
        'method' => 'POST',
        'header' => 'Content-type: application/x-www-form-urlencoded',
        'content' => $postdata
    )
);
$context = stream_context_create($opts);
$result = file_get_contents('http://localhost:8000/api/test', false, $context);
echo $result;?>

其他回答

上面的答案对我不起作用。这是第一个完美运行的解决方案:

$sPD = "name=Jacob&bench=150"; // The POST Data
$aHTTP = array(
  'http' => // The wrapper to be used
    array(
    'method'  => 'POST', // Request Method
    // Request Headers Below
    'header'  => 'Content-type: application/x-www-form-urlencoded',
    'content' => $sPD
  )
);
$context = stream_context_create($aHTTP);
$contents = file_get_contents($sURL, false, $context);

echo $contents;

PHP5的无卷曲方法:

$url = 'http://server.com/path';
$data = array('key1' => 'value1', 'key2' => 'value2');

// use key 'http' even if you send the request to https://...
$options = array(
    'http' => array(
        'header'  => "Content-type: application/x-www-form-urlencoded\r\n",
        'method'  => 'POST',
        'content' => http_build_query($data)
    )
);
$context  = stream_context_create($options);
$result = file_get_contents($url, false, $context);
if ($result === FALSE) { /* Handle error */ }

var_dump($result);

有关该方法和如何添加头的更多信息,请参阅PHP手册,例如:

stream_context_create: http://php.net/manual/en/function.stream-context-create.php

上面的无卷曲方法的另一种替代方法是使用本机流函数:

stream_context_create (): 创建并返回带有options预置中提供的任何选项的流上下文。 stream_get_contents (): 与file_get_contents()相同,不同之处在于stream_get_contents()操作的是已经打开的流资源,并以字符串形式返回剩余内容,最大长度为maxlength字节,从指定的偏移量开始。

具有这些功能的POST函数可以简单地像这样:

<?php

function post_request($url, array $params) {
  $query_content = http_build_query($params);
  $fp = fopen($url, 'r', FALSE, // do not use_include_path
    stream_context_create([
    'http' => [
      'header'  => [ // header array does not need '\r\n'
        'Content-type: application/x-www-form-urlencoded',
        'Content-Length: ' . strlen($query_content)
      ],
      'method'  => 'POST',
      'content' => $query_content
    ]
  ]));
  if ($fp === FALSE) {
    return json_encode(['error' => 'Failed to get contents...']);
  }
  $result = stream_get_contents($fp); // no maxlength/offset
  fclose($fp);
  return $result;
}

你可以使用cURL:

<?php
//The url you wish to send the POST request to
$url = $file_name;

//The data you want to send via POST
$fields = [
    '__VIEWSTATE '      => $state,
    '__EVENTVALIDATION' => $valid,
    'btnSubmit'         => 'Submit'
];

//url-ify the data for the POST
$fields_string = http_build_query($fields);

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, true);
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);

//So that curl_exec returns the contents of the cURL; rather than echoing it
curl_setopt($ch,CURLOPT_RETURNTRANSFER, true); 

//execute post
$result = curl_exec($ch);
echo $result;
?>

这里只使用了一个没有cURL的命令。超级简单。

echo file_get_contents('https://www.server.com', false, stream_context_create([
    'http' => [
        'method' => 'POST',
        'header'  => "Content-type: application/x-www-form-urlencoded",
        'content' => http_build_query([
            'key1' => 'Hello world!', 'key2' => 'second value'
        ])
    ]
]));