实际上,我想读取搜索查询之后的内容,当它完成时。问题是URL只接受POST方法,它不采取任何行动与GET方法…

我必须在domdocument或file_get_contents()的帮助下读取所有内容。有没有什么方法可以让我用POST方法发送参数,然后通过PHP读取内容?


当前回答

[编辑]:请忽略,现在在php中不可用。

还有一个你可以用的

<?php
$fields = array(
    'name' => 'mike',
    'pass' => 'se_ret'
);
$files = array(
    array(
        'name' => 'uimg',
        'type' => 'image/jpeg',
        'file' => './profile.jpg',
    )
);

$response = http_post_fields("http://www.example.com/", $fields, $files);
?>

详情请按此处

其他回答

我做了一个函数来请求一个使用JSON的帖子:

const FORMAT_CONTENT_LENGTH = 'Content-Length: %d';
const FORMAT_CONTENT_TYPE = 'Content-Type: %s';

const CONTENT_TYPE_JSON = 'application/json';
/**
 * @description Make a HTTP-POST JSON call
 * @param string $url
 * @param array $params
 * @return bool|string HTTP-Response body or an empty string if the request fails or is empty
 */
function HTTPJSONPost(string $url, array $params)
{
    $content = json_encode($params);
    $response = file_get_contents($url, false, // do not use_include_path
        stream_context_create([
            'http' => [
                'method' => 'POST',
                'header' => [ // header array does not need '\r\n'
                    sprintf(FORMAT_CONTENT_TYPE, CONTENT_TYPE_JSON),
                    sprintf(FORMAT_CONTENT_LENGTH, strlen($content)),
                ],
                'content' => $content
            ]
        ])); // no maxlength/offset
    if ($response === false) {
        return json_encode(['error' => 'Failed to get contents...']);
    }

    return $response;
}

用PHP发送GET或POST请求的更好方法如下:

<?php
    $r = new HttpRequest('http://example.com/form.php', HttpRequest::METH_POST);
    $r->setOptions(array('cookies' => array('lang' => 'de')));
    $r->addPostFields(array('user' => 'mike', 'pass' => 's3c|r3t'));

    try {
        echo $r->send()->getBody();
    } catch (HttpException $ex) {
        echo $ex;
    }
?>

代码摘自官方文档http://docs.php.net/manual/da/httprequest.send.php

我更喜欢这个:

function curlPost($url, $data = NULL, $headers = []) {
    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36');
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
    curl_setopt($ch, CURLOPT_TIMEOUT, 5); //timeout in seconds
    curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
    curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
    curl_setopt($ch, CURLOPT_ENCODING, 'identity');

    
    if (!empty($data)) {
        curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
    }

    if (!empty($headers)) {
        curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
    }

    $response = curl_exec($ch);
    if (curl_error($ch)) {
        trigger_error('Curl Error:' . curl_error($ch));
    }

    curl_close($ch);
    return $response;
}

使用的例子:

$response=curlPost("http://my.url.com", ["myField1"=>"myValue1"], ["myFitstHeaderName"=>"myFirstHeaderValue"]);

你可以使用cURL:

<?php
//The url you wish to send the POST request to
$url = $file_name;

//The data you want to send via POST
$fields = [
    '__VIEWSTATE '      => $state,
    '__EVENTVALIDATION' => $valid,
    'btnSubmit'         => 'Submit'
];

//url-ify the data for the POST
$fields_string = http_build_query($fields);

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, true);
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);

//So that curl_exec returns the contents of the cURL; rather than echoing it
curl_setopt($ch,CURLOPT_RETURNTRANSFER, true); 

//execute post
$result = curl_exec($ch);
echo $result;
?>

这里有这样的代码:

<?php
$postdata = http_build_query(
    array(
        'name' => 'Robert',
        'id' => '1'
    )
);
$opts = array('http' =>
    array(
        'method' => 'POST',
        'header' => 'Content-type: application/x-www-form-urlencoded',
        'content' => $postdata
    )
);
$context = stream_context_create($opts);
$result = file_get_contents('http://localhost:8000/api/test', false, $context);
echo $result;?>