我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
当前回答
首先连接两个数组,然后只过滤出唯一的项:
变量a=[1,2,3],b=[101,2,1,10]var c=交流电(b)var d=c.filter((项目,位置)=>c.indexOf(项目)===位置)console.log(d)//d为[1,2,3,101,10]
Edit
正如所建议的,一个更具性能的解决方案是在与a连接之前过滤掉b中的唯一项:
变量a=[1,2,3],b=[101,2,1,10]var c=a.oncat(b.filter((项)=>a.indexOf(项)<0))console.log(c)//c为[1,2,3,101,10]
其他回答
带过滤器的最简单解决方案:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
var mergedArrayWithoutDuplicates = array1.concat(
array2.filter(seccondArrayItem => !array1.includes(seccondArrayItem))
);
合并无限数量的数组或非数组并保持其唯一性:
function flatMerge() {
return Array.prototype.reduce.call(arguments, function (result, current) {
if (!(current instanceof Array)) {
if (result.indexOf(current) === -1) {
result.push(current);
}
} else {
current.forEach(function (value) {
console.log(value);
if (result.indexOf(value) === -1) {
result.push(value);
}
});
}
return result;
}, []);
}
flatMerge([1,2,3], 4, 4, [3, 2, 1, 5], [7, 6, 8, 9], 5, [4], 2, [3, 2, 5]);
// [1, 2, 3, 4, 5, 7, 6, 8, 9]
flatMerge([1,2,3], [3, 2, 1, 5], [7, 6, 8, 9]);
// [1, 2, 3, 5, 7, 6, 8, 9]
flatMerge(1, 3, 5, 7);
// [1, 3, 5, 7]
Array.prototype.pushUnique = function(values)
{
for (var i=0; i < values.length; i++)
if (this.indexOf(values[i]) == -1)
this.push(values[i]);
};
Try:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
array1.pushUnique(array2);
alert(array1.toString()); // Output: Vijendra,Singh,Shakya
新解决方案(使用Array.prototype.indexOf和Array.prototype.cocat):
Array.prototype.uniqueMerge = function( a ) {
for ( var nonDuplicates = [], i = 0, l = a.length; i<l; ++i ) {
if ( this.indexOf( a[i] ) === -1 ) {
nonDuplicates.push( a[i] );
}
}
return this.concat( nonDuplicates )
};
用法:
>>> ['Vijendra', 'Singh'].uniqueMerge(['Singh', 'Shakya'])
["Vijendra", "Singh", "Shakya"]
Array.prototype.indexOf(用于internet explorer):
Array.prototype.indexOf = Array.prototype.indexOf || function(elt)
{
var len = this.length >>> 0;
var from = Number(arguments[1]) || 0;
from = (from < 0) ? Math.ceil(from): Math.floor(from);
if (from < 0)from += len;
for (; from < len; from++)
{
if (from in this && this[from] === elt)return from;
}
return -1;
};
仅合并阵列(不删除重复项)
ES5版本使用Array.concat:
var array1=[“Vijendra”,“Singh”];var array2=[“Singh”,“Shakya”];array1=array1.concat(array2);console.log(array1);
ES6版本使用销毁
const array1 = ["Vijendra","Singh"];
const array2 = ["Singh", "Shakya"];
const array3 = [...array1, ...array2];
由于没有“内置”的方法来删除重复项(ECMA-262实际上有Array.forEach,这将非常好),因此我们必须手动执行:
Array.prototype.unique = function() {
var a = this.concat();
for(var i=0; i<a.length; ++i) {
for(var j=i+1; j<a.length; ++j) {
if(a[i] === a[j])
a.splice(j--, 1);
}
}
return a;
};
然后,要使用它:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
// Merges both arrays and gets unique items
var array3 = array1.concat(array2).unique();
这也将保持阵列的顺序(即,不需要排序)。
由于许多人对Array.prototype的原型扩充和in循环感到恼火,这里有一种不太侵入性的方法来使用它:
function arrayUnique(array) {
var a = array.concat();
for(var i=0; i<a.length; ++i) {
for(var j=i+1; j<a.length; ++j) {
if(a[i] === a[j])
a.splice(j--, 1);
}
}
return a;
}
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
// Merges both arrays and gets unique items
var array3 = arrayUnique(array1.concat(array2));
对于那些有幸使用ES5可用的浏览器的人,可以像这样使用Object.defineProperty:
Object.defineProperty(Array.prototype, 'unique', {
enumerable: false,
configurable: false,
writable: false,
value: function() {
var a = this.concat();
for(var i=0; i<a.length; ++i) {
for(var j=i+1; j<a.length; ++j) {
if(a[i] === a[j])
a.splice(j--, 1);
}
}
return a;
}
});