如何让Selenium 2.0等待页面加载?


当前回答

您可以尝试这段代码,让页面完全加载,直到找到元素为止。

public void waitForBrowserToLoadCompletely() {
    String state = null;
    String oldstate = null;
    try {
        System.out.print("Waiting for browser loading to complete");

        int i = 0;
        while (i < 5) {
            Thread.sleep(1000);
            state = ((JavascriptExecutor) driver).executeScript("return document.readyState;").toString();
            System.out.print("." + Character.toUpperCase(state.charAt(0)) + ".");
            if (state.equals("interactive") || state.equals("loading"))
                break;
            /*
             * If browser in 'complete' state since last X seconds. Return.
             */

            if (i == 1 && state.equals("complete")) {
                System.out.println();
                return;
            }
            i++;
        }
        i = 0;
        oldstate = null;
        Thread.sleep(2000);

        /*
         * Now wait for state to become complete
         */
        while (true) {
            state = ((JavascriptExecutor) driver).executeScript("return document.readyState;").toString();
            System.out.print("." + state.charAt(0) + ".");
            if (state.equals("complete"))
                break;

            if (state.equals(oldstate))
                i++;
            else
                i = 0;
            /*
             * If browser state is same (loading/interactive) since last 60
             * secs. Refresh the page.
             */
            if (i == 15 && state.equals("loading")) {
                System.out.println("\nBrowser in " + state + " state since last 60 secs. So refreshing browser.");
                driver.navigate().refresh();
                System.out.print("Waiting for browser loading to complete");
                i = 0;
            } else if (i == 6 && state.equals("interactive")) {
                System.out.println(
                        "\nBrowser in " + state + " state since last 30 secs. So starting with execution.");
                return;
            }

            Thread.sleep(4000);
            oldstate = state;

        }
        System.out.println();

    } catch (InterruptedException ie) {
        ie.printStackTrace();
    }
}

其他回答

Ruby实现:

wait = Selenium::WebDriver::Wait.new(:timeout => 10)
wait.until {
    @driver.execute_script("return document.readyState;") == "complete" 
}

一般来说,使用Selenium 2.0时,web驱动程序应该只在确定页面已加载后才将控制权返回给调用代码。如果没有,您可以调用waitforeleement,它循环调用findelement,直到找到它或超时(可以设置超时)。

如果你想等待一个特定的元素加载,你可以在RenderedWebElement上使用isdisplay()方法:

// Sleep until the div we want is visible or 5 seconds is over
long end = System.currentTimeMillis() + 5000;
while (System.currentTimeMillis() < end) {
    // Browsers which render content (such as Firefox and IE) return "RenderedWebElements"
    RenderedWebElement resultsDiv = (RenderedWebElement) driver.findElement(By.className("gac_m"));

    // If results have been returned, the results are displayed in a drop down.
    if (resultsDiv.isDisplayed()) {
      break;
    }
}

(例子来自《5分钟入门指南》)

我不认为含蓄的等待是你想要的。试试这个:

.timeouts driver.manage()()。TimeUnit.SECONDS pageLoadTimeout(10日);

更多信息请参见文档

隐式和显式的等待更好。

但是如果你在Java中处理一个异常,那么你可以使用这个来等待页面重新加载:

Thead.sleep(1000);