如何让Selenium 2.0等待页面加载?


当前回答

您可以尝试这段代码,让页面完全加载,直到找到元素为止。

public void waitForBrowserToLoadCompletely() {
    String state = null;
    String oldstate = null;
    try {
        System.out.print("Waiting for browser loading to complete");

        int i = 0;
        while (i < 5) {
            Thread.sleep(1000);
            state = ((JavascriptExecutor) driver).executeScript("return document.readyState;").toString();
            System.out.print("." + Character.toUpperCase(state.charAt(0)) + ".");
            if (state.equals("interactive") || state.equals("loading"))
                break;
            /*
             * If browser in 'complete' state since last X seconds. Return.
             */

            if (i == 1 && state.equals("complete")) {
                System.out.println();
                return;
            }
            i++;
        }
        i = 0;
        oldstate = null;
        Thread.sleep(2000);

        /*
         * Now wait for state to become complete
         */
        while (true) {
            state = ((JavascriptExecutor) driver).executeScript("return document.readyState;").toString();
            System.out.print("." + state.charAt(0) + ".");
            if (state.equals("complete"))
                break;

            if (state.equals(oldstate))
                i++;
            else
                i = 0;
            /*
             * If browser state is same (loading/interactive) since last 60
             * secs. Refresh the page.
             */
            if (i == 15 && state.equals("loading")) {
                System.out.println("\nBrowser in " + state + " state since last 60 secs. So refreshing browser.");
                driver.navigate().refresh();
                System.out.print("Waiting for browser loading to complete");
                i = 0;
            } else if (i == 6 && state.equals("interactive")) {
                System.out.println(
                        "\nBrowser in " + state + " state since last 30 secs. So starting with execution.");
                return;
            }

            Thread.sleep(4000);
            oldstate = state;

        }
        System.out.println();

    } catch (InterruptedException ie) {
        ie.printStackTrace();
    }
}

其他回答

使用这个函数

public void waitForPageLoad(ChromeDriver d){
        String s="";
        while(!s.equals("complete")){
        s=(String) d.executeScript("return document.readyState");
        try {
            Thread.sleep(1000);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        }

    }

我不认为含蓄的等待是你想要的。试试这个:

.timeouts driver.manage()()。TimeUnit.SECONDS pageLoadTimeout(10日);

更多信息请参见文档

一般来说,使用Selenium 2.0时,web驱动程序应该只在确定页面已加载后才将控制权返回给调用代码。如果没有,您可以调用waitforeleement,它循环调用findelement,直到找到它或超时(可以设置超时)。

public static int counter = 0;

public void stepGeneralWait() {

    boolean breakIt = true;

    while (true) {
        breakIt = true;
        try {

            do{
                // here put e.g. your spinner ID
                Controller.driver.findElement(By.xpath("//*[@id='static']/div[8]/img")).click();
                Thread.sleep(10000);

                counter++;

                if (counter > 3){
                    breakIt = false;

                }
            }
            while (breakIt);



        } catch (Exception e) {
            if (e.getMessage().contains("element is not attached")) {
                breakIt = false;
            }
        }
        if (breakIt) {
            break;
        }

    }

    try {
        Thread.sleep(12000);
    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

}

如何让Selenium在单击后等待页面加载提供了以下有趣的方法:

存储旧页面中对WebElement的引用。 点击链接。 继续调用WebElement上的操作,直到抛出StaleElementReferenceException。

示例代码:

WebElement link = ...;
link.click();
new WebDriverWait(webDriver, timeout).until((org.openqa.selenium.WebDriver input) ->
{
    try
    {
        link.isDisplayed();
        return false;
    }
    catch (StaleElementReferenceException unused)
    {
        return true;
    }
});