我得到这个警告在反应:

index.js:1 Warning: Cannot update a component (`ConnectFunction`) 
while rendering a different component (`Register`). To locate the 
bad setState() call inside `Register` 

我去了堆栈跟踪中指出的位置,并删除了所有设置状态,但警告仍然存在。这可能发生在redux调度?

我的代码:

register.js

class Register extends Component {
  render() {
    if( this.props.registerStatus === SUCCESS) { 
      // Reset register status to allow return to register page
      this.props.dispatch( resetRegisterStatus())  # THIS IS THE LINE THAT CAUSES THE ERROR ACCORDING TO THE STACK TRACE
      return <Redirect push to = {HOME}/>
    }
    return (
      <div style = {{paddingTop: "180px", background: 'radial-gradient(circle, rgba(106,103,103,1) 0%, rgba(36,36,36,1) 100%)', height: "100vh"}}>
        <RegistrationForm/>
      </div>
    );
  }
}

function mapStateToProps( state ) {
  return {
    registerStatus: state.userReducer.registerStatus
  }
}

export default connect ( mapStateToProps ) ( Register );

函数,该函数触发了由register.js调用的registerForm组件中的警告

handleSubmit = async () => {
    if( this.isValidForm() ) { 
      const details = {
        "username": this.state.username,
        "password": this.state.password,
        "email": this.state.email,
        "clearance": this.state.clearance
      }
      await this.props.dispatch( register(details) )
      if( this.props.registerStatus !== SUCCESS && this.mounted ) {
        this.setState( {errorMsg: this.props.registerError})
        this.handleShowError()
      }
    }
    else {
      if( this.mounted ) {
        this.setState( {errorMsg: "Error - registration credentials are invalid!"} )
        this.handleShowError()
      }
    }
  }

堆栈跟踪:


当前回答

我的例子。

带有错误的代码:

<Form
    initialValues={{ ...kgFormValues, dataflow: dataflows.length > 0 ? dataflows[0].df_tpl_key : "" }}
    onSubmit={() => {}}
    render={({values, dirtyFields }: any) => {
      
      const kgFormValuesUpdated = {
        proj_key: projectKey,
        name: values.name,
        description: values.description,
        public: values.public,
        dataflow: values.dataflow,
        flavours: flavoursSelected,
        skipOCR: values.skipOCR
      };

      if (!_.isEqual(kgFormValues, kgFormValuesUpdated)) {
        setNewKgFormValues(kgFormValuesUpdated);
      }

工作代码:

 <Form
    initialValues={{ ...kgFormValues, dataflow: dataflows.length > 0 ? dataflows[0].df_tpl_key : "" }}
    onSubmit={() => {}}
    render={({ values, dirtyFields }: any) => {
      useEffect(() => {
        const kgFormValuesUpdated = {
          proj_key: projectKey,
          name: values.name,
          description: values.description,
          public: values.public,
          dataflow: values.dataflow,
          flavours: flavoursSelected,
          skipOCR: values.skipOCR
        };

        if (!_.isEqual(kgFormValues, kgFormValuesUpdated)) {
          setNewKgFormValues(kgFormValuesUpdated);
        }
      }, [values]);

      return (

其他回答

使用上面的一些答案,我摆脱了以下错误:

from

if (value === "newest") {
  dispatch(sortArticlesNewest());
} else {
  dispatch(sortArticlesOldest());
}

这段代码位于我的组件顶层

to

    const SelectSorting = () => {
  const dispatch = useAppDispatch();

  const {value, onChange} = useSelect();

  useEffect(() => {
    if (value === "newest") {
      dispatch(sortArticlesNewest());
    } else {
      dispatch(sortArticlesOldest());
    }
  }, [dispatch, value]);

请仔细阅读错误消息,我的是指向签入组件有一个坏的setState。当我检查时,我有一个不是箭头函数的onpress。

是这样的:

onPress={navigation.navigate("Home", { screen: "HomeScreen" })}

我把它改成了这样:

onPress={() => navigation.navigate("Home", { screen: "HomeScreen" }) }

我的错误信息是:

警告:不能更新组件 (ForwardRef(BaseNavigationContainer)),同时呈现一个不同的 组件(SignIn)。来定位内部错误的setState()调用 中所描述的堆栈跟踪 https://reactjs.org/link/setstate-in-render in SignIn(在SignInScreen.tsx:20)

我也有同样的问题。我设置了一些存储函数的状态,像这样:

// my state definition
const [onConfirm, setOnConfirm] = useState<() => void>();

// then I used this piece of code to update the state
function show(onConfirm: () => void) {
    setOnConfirm(onConfirm);
}

问题来自setOnConfirm。在React中,setState可以接受新值,也可以接受返回新值的函数。在这种情况下,React希望通过调用onConfirm来获得新的状态,这是不正确的。

改成这个解决了我的问题:

setOnConfirm(() => onConfirm);

使用React和材质UI (MUI) 我改变了我的代码:

<IconButton onClick={setOpenDeleteDialog(false)}>
        <Close />
      </IconButton>

To:

<IconButton onClick={() => setOpenDeleteDialog(false)}>
        <Close />
      </IconButton>

简单的修理

如果你使用React导航并且你正在使用setParams或setOptions,你必须把这些放在类组件的componentDidMount()方法中或函数组件的useEffects()钩子中。