我得到这个警告在反应:

index.js:1 Warning: Cannot update a component (`ConnectFunction`) 
while rendering a different component (`Register`). To locate the 
bad setState() call inside `Register` 

我去了堆栈跟踪中指出的位置,并删除了所有设置状态,但警告仍然存在。这可能发生在redux调度?

我的代码:

register.js

class Register extends Component {
  render() {
    if( this.props.registerStatus === SUCCESS) { 
      // Reset register status to allow return to register page
      this.props.dispatch( resetRegisterStatus())  # THIS IS THE LINE THAT CAUSES THE ERROR ACCORDING TO THE STACK TRACE
      return <Redirect push to = {HOME}/>
    }
    return (
      <div style = {{paddingTop: "180px", background: 'radial-gradient(circle, rgba(106,103,103,1) 0%, rgba(36,36,36,1) 100%)', height: "100vh"}}>
        <RegistrationForm/>
      </div>
    );
  }
}

function mapStateToProps( state ) {
  return {
    registerStatus: state.userReducer.registerStatus
  }
}

export default connect ( mapStateToProps ) ( Register );

函数,该函数触发了由register.js调用的registerForm组件中的警告

handleSubmit = async () => {
    if( this.isValidForm() ) { 
      const details = {
        "username": this.state.username,
        "password": this.state.password,
        "email": this.state.email,
        "clearance": this.state.clearance
      }
      await this.props.dispatch( register(details) )
      if( this.props.registerStatus !== SUCCESS && this.mounted ) {
        this.setState( {errorMsg: this.props.registerError})
        this.handleShowError()
      }
    }
    else {
      if( this.mounted ) {
        this.setState( {errorMsg: "Error - registration credentials are invalid!"} )
        this.handleShowError()
      }
    }
  }

堆栈跟踪:


当前回答

最小复制示例

我有点困惑到底是什么引发了这个问题,有一个最小的立即可运行的例子帮助我更好地理解它:

index . html

<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<script src="https://unpkg.com/react@17/umd/react.development.js"></script>
<script src="https://unpkg.com/react-dom@17/umd/react-dom.development.js"></script>
<script src="https://unpkg.com/@babel/standalone@7.14.7/babel.min.js"></script>
</head>
<body>
<div id="root"></div>
<script type="text/babel">
function NotMain(props) {
  props.setN(1)
  return <div>NotMain</div>
}

function Main(props) {
  const [n, setN] = React.useState(0)
  return <>
    <NotMain setN={setN} />
    <div>Main {n}</div>
  </>
}

ReactDOM.render(
  <Main/>,
  document.getElementById('root')
);
</script>
</body>
</html>

错误失败:

react-dom.development.js:61警告:在呈现不同的组件(' NotMain ')时不能更新一个组件(' Main ')。要定位' NotMain '内部错误的setState()调用,请按照https://reactjs.org/link/setstate-in-render中描述的堆栈跟踪

后面跟着一个堆栈跟踪:

    at NotMain (<anonymous>:16:9)
    at Main (<anonymous>:21:31)

假定16:9是props.setN(1)被调用的确切行,但是由于Babel JSX翻译,行号有点混乱。

解决方案和其他答案一样,是这样做的:

function NotMain(props) {
  React.useEffect(() => { props.setN(1) }, [])
  return <div>NotMain</div>
}

直观地说,我认为这个错误发生的大致原因是:

你不应该从渲染方法中更新状态,否则会导致不同的结果,这取决于React如何渲染事物的内部顺序。

当使用功能组件时,方法是使用钩子。在我们的例子中,useEffect将在渲染完成后运行,所以我们可以从那里开始执行。

当使用类时,这一点变得更加清晰,例如:

在呈现中调用setState是不可避免的 从渲染方法调用React中的setState()

然而,当使用功能组件时,从概念上讲,事情有点复杂,因为组件函数既是呈现,也是设置回调的代码。

其他回答

使用React和材质UI (MUI) 我改变了我的代码:

<IconButton onClick={setOpenDeleteDialog(false)}>
        <Close />
      </IconButton>

To:

<IconButton onClick={() => setOpenDeleteDialog(false)}>
        <Close />
      </IconButton>

简单的修理

我的例子。

带有错误的代码:

<Form
    initialValues={{ ...kgFormValues, dataflow: dataflows.length > 0 ? dataflows[0].df_tpl_key : "" }}
    onSubmit={() => {}}
    render={({values, dirtyFields }: any) => {
      
      const kgFormValuesUpdated = {
        proj_key: projectKey,
        name: values.name,
        description: values.description,
        public: values.public,
        dataflow: values.dataflow,
        flavours: flavoursSelected,
        skipOCR: values.skipOCR
      };

      if (!_.isEqual(kgFormValues, kgFormValuesUpdated)) {
        setNewKgFormValues(kgFormValuesUpdated);
      }

工作代码:

 <Form
    initialValues={{ ...kgFormValues, dataflow: dataflows.length > 0 ? dataflows[0].df_tpl_key : "" }}
    onSubmit={() => {}}
    render={({ values, dirtyFields }: any) => {
      useEffect(() => {
        const kgFormValuesUpdated = {
          proj_key: projectKey,
          name: values.name,
          description: values.description,
          public: values.public,
          dataflow: values.dataflow,
          flavours: flavoursSelected,
          skipOCR: values.skipOCR
        };

        if (!_.isEqual(kgFormValues, kgFormValuesUpdated)) {
          setNewKgFormValues(kgFormValuesUpdated);
        }
      }, [values]);

      return (

在GitHub中遇到类似的问题后,我能够解决这个问题,这让我看到了这条评论,展示了如何精确定位文件中导致错误的确切行。我不知道堆栈跟踪在那里。希望这能帮助到一些人!

请看下面我的解决方案。我只是将函数转换为使用回调。

旧的代码

function TopMenuItems() {
  const dispatch = useDispatch();

  function mountProjectListToReduxStore(projects) {
    const projectDropdown = projects.map((project) => ({
      id: project.id,
      name: project.name,
      organizationId: project.organizationId,
      createdOn: project.createdOn,
      lastModifiedOn: project.lastModifiedOn,
      isComplete: project.isComplete,
    }));
    projectDropdown.sort((a, b) => a.name.localeCompare(b.name));
    dispatch(loadProjectsList(projectDropdown));
    dispatch(setCurrentOrganizationId(projectDropdown[0].organizationId));
  }
};

新代码

function TopMenuItems() {
  const dispatch = useDispatch();

  const mountProjectListToReduxStore = useCallback((projects) => {
    const projectDropdown = projects.map((project) => ({
      id: project.id,
      name: project.name,
      organizationId: project.organizationId,
      createdOn: project.createdOn,
      lastModifiedOn: project.lastModifiedOn,
      isComplete: project.isComplete,
    }));
    projectDropdown.sort((a, b) => a.name.localeCompare(b.name));
    dispatch(loadProjectsList(projectDropdown));
    dispatch(setCurrentOrganizationId(projectDropdown[0].organizationId));
  }, [dispatch]);
};

当我愚蠢地调用调用调度的函数,而不是传递一个引用给按钮上的onClick时,我得到了这个。

  const quantityChangeHandler = (direction) => {
    dispatch(cartActions.changeItemQuantity({title, quantityChange: direction}));
  }
...
          <button onClick={() => quantityChangeHandler(-1)}>-</button>
          <button onClick={() => quantityChangeHandler(1)}>+</button>

一开始,我直接打电话给你,没有那个大箭头包装。

如果useEffect不能在您的情况下使用或如果错误不是由于Redux

我使用setTimeout将两个useState变量中的一个重定向到回调队列。

我有一个父组件和一个子组件,每个组件中都有useState变量。解决方案是使用setTimeout来包装useState变量:

setTimeout(() => SetFilterData(data), 0);

在下面的例子

父组件

import ExpenseFilter from '../ExpensesFilter'
    
function ExpensesView(props) {
    
    const [filterData, SetFilterData] = useState('')
    
    const GetFilterData = (data) => {
       // SetFilterData(data);

       //*****WRAP useState VARIABLE INSIDE setTimeout WITH 0 TIME AS BELOW.*****
       setTimeout(() => SetFilterData(data), 0);
    
    }
    
    const filteredArray = props.expense.filter(expenseFiltered => 
      expenseFiltered.dateSpent.getFullYear().toString() === filterData);
    
    
    return (
    <Window>
      <div>
        <ExpenseFilter FilterYear = {GetFilterData}></ExpenseFilter>

子组件

const ExpensesFilter = (props) => {
    
    const [filterYear, SetFilterYear] = useState('2022')
    
    const FilterYearListener = (event) => {
        event.preventDefault()
        SetFilterYear(event.target.value)
    }
    
    props.FilterYear(filterYear)
    
    return (