在Debian和Red Hat上都可以工作的解决方案。依赖于perl，使用sha-512散列:

cat userpassadd
    #!/usr/bin/env bash

    salt=$(cat /dev/urandom | tr -dc A-Za-z0-9/_- | head -c16)
    useradd -p $(perl -e "print crypt('$2', '\$6\$' . '$salt' . '\$')") $1

用法:

userpassadd jim jimslongpassword

它可以有效地作为一行程序使用，但你必须自己在正确的地方指定密码、盐和用户名:

useradd -p $(perl -e "print crypt('pass', '\$6\$$salt\$')") username

这里有一个脚本，将为您.....

如果你愿意，你可以添加一个用户列表(或者只是一个用户)，一次完成，每个用户都有不同的密码。作为奖励，脚本的末尾会显示每个用户的密码. ....如果您愿意，您可以添加一些用户维护选项

如:

chage -m 18 $user
chage -M 28 $user

到将设置密码年龄等的脚本。

= = = = = = =

#!/bin/bash

# Checks if you have the right privileges
if [ "$USER" = "root" ]
then

# CHANGE THIS PARAMETERS FOR A PARTICULAR USE
PERS_HOME="/home/"
PERS_SH="/bin/bash"

   # Checks if there is an argument
   [ $# -eq 0 ] && { echo >&2 ERROR: You may enter as an argument a text file containing users, one per line. ; exit 1; }
   # checks if there a regular file
   [ -f "$1" ] || { echo >&2 ERROR: The input file does not exists. ; exit 1; }
   TMPIN=$(mktemp)
   # Remove blank lines and delete duplicates 
   sed '/^$/d' "$1"| sort -g | uniq > "$TMPIN"

   NOW=$(date +"%Y-%m-%d-%X")
   LOGFILE="AMU-log-$NOW.log"

   for user in $(more "$TMPIN"); do
      # Checks if the user already exists.
      cut -d: -f1 /etc/passwd | grep "$user" > /dev/null
      OUT=$?
      if [ $OUT -eq 0 ];then
         echo >&2 "ERROR: User account: \"$user\" already exists."
         echo >&2 "ERROR: User account: \"$user\" already exists." >> "$LOGFILE"
      else
         # Create a new user
         /usr/sbin/useradd -d "$PERS_HOME""$user" -s "$PERS_SH" -m "$user"
         # passwdgen must be installed
         pass=$(passwdgen -paq --length 8)
         echo $pass | passwd --stdin $user
         # save user and password in a file
         echo -e $user"\t"$pass >> "$LOGFILE"
         echo "The user \"$user\" has been created and has the password: $pass"
      fi
   done
   rm -f "$TMPIN"
   exit 0
else
   echo >&2 "ERROR: You must be a root user to execute this script."
   exit 1
fi

===========

希望这能有所帮助。

欢呼, 卡路

我也问过自己同样的问题，但不想依赖Python脚本。

这是在一个bash行中添加一个具有已定义密码的用户的行:

useradd -p $(openssl passwd -crypt $PASS) $USER

我在自己的shell脚本中进行了测试。

$new_username表示新创建的用户 $new_password表示新密码

是被久远

echo "$new_password" | passwd --stdin "$new_username"

对于 Debian/Ubuntu

echo "$new_username:$new_password" | chpasswd

对于 OpenSUSE

echo -e "$new_password\n$new_password" | passwd "$new_username"

我喜欢Tralemonkey的方法echo thePassword | passwd theUsername—stdin，虽然它不太适合我写的。然而，这对我来说很有效。

echo -e "$password\n$password\n" | sudo passwd $user

-e是将\n识别为新行。

sudo是Ubuntu的根权限。

双引号用于识别$并展开变量。

上面的命令两次将密码和新行传递给passwd，这是passwd所需要的。

如果不使用变量，我认为这可能可行。

echo -e 'password\npassword\n' | sudo passwd username

单引号在这里就足够了。

请使用sudo权限运行以下脚本，通过脚本创建用户。

注意:此脚本支持所有linux操作系统，如Redhat, Centos, Ubuntu, suse, kali, Arch, Bitname, BSD....等

#!/bin/bash
#author: bablish jaiswal
#purpos: Linux user creation with a storng password
clear
#echo "Hi, I am a function to create sudo user with strong password. Kindly share following information"
echo -e "\n\n\n"
printf "\e[6;33mHi, I am a function to create sudo user with a strong password. Kindly share following information\e[0m";echo
read -p "user name:- " name #input name
read -p "complete path for $name home directory? example: /home/$name :- " home #user home path
( useradd  -m -d $home $name -s /bin/bash ) > /dev/null 2>&1
pass=$(cat /dev/urandom |tr -dc "[[:graph:]]" |head -c16)
(echo -e "$pass\n$pass" | passwd $name ) > /dev/null 2>&1
echo " "
printf "\e[6;33m-----------------------------Copy below credentials-------------------------\e[0m";echo
echo -e "User:- $name\nHomeDir:- $home\npassword:- $pass"
#svalue=$(cat /etc/sudoers |grep -i root |grep -i all|tail -n1 |awk '{$1=""}1')
svalue=$(cat /etc/sudoers |grep -i root |grep -i all|tail -n1 |awk '{print $2}')
echo "${name} ${svalue} NOPASSWD:ALL" >> /etc/sudoers && echo “Remark:- User $name is a sudo user”