我就是这么做的，效果很好。

User.find({name:'Thava'}, null, {sort: { name : 1 }})

// Ascending with updatedAt field
Post.find().sort('updatedAt').exec((err, post) => {...});

// Descending with updatedAt field
Post.find().sort('-updatedAt').exec((err, post) => {...});

参考网址:https://mongoosejs.com/docs/queries.html

在Mongoose 4中使用查询生成器接口进行链接。

// Build up a query using chaining syntax. Since no callback is passed this will create an instance of Query.
var query = Person.
    find({ occupation: /host/ }).
    where('name.last').equals('Ghost'). // find each Person with a last name matching 'Ghost'
    where('age').gt(17).lt(66).
    where('likes').in(['vaporizing', 'talking']).
    limit(10).
    sort('-occupation'). // sort by occupation in decreasing order
    select('name occupation'); // selecting the `name` and `occupation` fields


// Excute the query at a later time.
query.exec(function (err, person) {
    if (err) return handleError(err);
    console.log('%s %s is a %s.', person.name.first, person.name.last, person.occupation) // Space Ghost is a talk show host
})

有关查询的更多信息，请参阅文档。

更新:

Post.find().sort({'updatedAt': -1}).all((posts) => {
  // do something with the array of posts
});

Try:

Post.find().sort([['updatedAt', 'descending']]).all((posts) => {
  // do something with the array of posts
});

这就是我如何在mongoose.js 2.0.4中获得sort工作

var query = EmailModel.find({domain:"gmail.com"});
query.sort('priority', 1);
query.exec(function(error, docs){
  //...
});

在Mongoose中，排序可以通过以下任何一种方式完成:

    Post.find({}).sort('test').exec(function(err, docs) { ... });
    Post.find({}).sort([['date', -1]]).exec(function(err, docs) { ... });
    Post.find({}).sort({test: 1}).exec(function(err, docs) { ... });
    Post.find({}, null, {sort: {date: 1}}, function(err, docs) { ... });