我在一个Kotlin项目中工作，该项目公开了一个由Java客户机使用的API (Java客户机不能利用Kotlin语言结构)。我们必须添加构建器以使它们在Java中可用，因此我创建了@Builder注释:https://github.com/ThinkingLogic/kotlin-builder-annotation 它基本上是Kotlin的Lombok @Builder注释的替代品。

因为我使用Jackson库从JSON解析对象，我需要一个空构造函数，我不能有可选字段。而且所有字段都必须是可变的。然后我可以使用这个漂亮的语法，它做的事情与生成器模式相同:

val car = Car().apply{ model = "Ford"; year = 2000 }

class Person(
    val name:String,
    val family:String,
    val age:Int,
    val nationalCode: String?,
    val email: String?,
    val phoneNumber: String?
) {

    // Private constructor
    private constructor(builder: Builder) : this (
        builder.name,
        builder.family,
        builder.age,
        builder.nationalCode,
        builder.email,
        builder.phoneNumber
    )

    // Builder class

    // 1 Necessary parameters in Builder class : name , family
    class Builder(val name :String,val family :String) {

        // 2 Optional parameters in Builder class :
        var age: Int = 0
            private set
        var nationalCode: String? = null
            private set
        var email: String? = null
            private set
        var phoneNumber: String? = null
            private set

        fun age(age: Int) = apply { this.age = age }
        fun nationalCode(nationalCode: String) =
            apply { this.nationalCode = nationalCode }
        fun email(email: String) = apply { this.email = email }
        fun phoneNumber(phoneNumber: String) =
            apply { this.phoneNumber = phoneNumber }

        // 3 Create
        fun create() = Person(this)

    }
}

存取资料:

val firstPerson = Person.Builder(
    name = "Adnan",
    family = "Abdollah Zaki")
    .age(32)
    .email("Adnan9011@gmail.com")
    .phoneNumber("+989333030XXX")
    .nationalCode("04400XXXXX")
    .create()

val secondPerson = Person.Builder(
    name = "Foroogh",
    family = "Varmazyar")
    .create()

首先，在大多数情况下，您不需要在Kotlin中使用构建器，因为我们有默认参数和命名参数。这使你能够写作

class Car(val model: String? = null, val year: Int = 0)

像这样使用它:

val car = Car(model = "X")

如果你绝对想要使用构建器，你可以这样做:

将Builder作为伴生对象没有意义，因为对象是单例对象。相反，将其声明为一个嵌套类(在Kotlin中默认是静态的)。

将属性移动到构造函数中，这样对象也可以以常规方式实例化(如果不应该，则将构造函数设置为私有)，并使用接受构造函数并将其委托给主构造函数的辅助构造函数。代码如下所示:

class Car( //add private constructor if necessary
        val model: String?,
        val year: Int
) {

    private constructor(builder: Builder) : this(builder.model, builder.year)

    class Builder {
        var model: String? = null
            private set

        var year: Int = 0
            private set

        fun model(model: String) = apply { this.model = model }

        fun year(year: Int) = apply { this.year = year }

        fun build() = Car(this)
    }
}

用法:val car = car . builder ().model("X").build()

这段代码可以通过使用构建器DSL进一步缩短:

class Car (
        val model: String?,
        val year: Int
) {

    private constructor(builder: Builder) : this(builder.model, builder.year)

    companion object {
        inline fun build(block: Builder.() -> Unit) = Builder().apply(block).build()
    }

    class Builder {
        var model: String? = null
        var year: Int = 0

        fun build() = Car(this)
    }
}

用法:val car = car。建立{模型= "X"}

如果某些值是必需的，并且没有默认值，你需要将它们放在构建器的构造函数中，也需要放在我们刚刚定义的构建方法中:

class Car (
        val model: String?,
        val year: Int,
        val required: String
) {

    private constructor(builder: Builder) : this(builder.model, builder.year, builder.required)

    companion object {
        inline fun build(required: String, block: Builder.() -> Unit) = Builder(required).apply(block).build()
    }

    class Builder(
            val required: String
    ) {
        var model: String? = null
        var year: Int = 0

        fun build() = Car(this)
    }
}

用法:val car = car。build(required = "requiredValue") {model = "X"}

我看到过许多将额外乐趣作为构建者的例子。我个人喜欢这种方法。节省编写构建程序的精力。

package android.zeroarst.lab.koltinlab

import kotlin.properties.Delegates

class Lab {
    companion object {
        @JvmStatic fun main(args: Array<String>) {

            val roy = Person {
                name = "Roy"
                age = 33
                height = 173
                single = true
                car {
                    brand = "Tesla"
                    model = "Model X"
                    year = 2017
                }
                car {
                    brand = "Tesla"
                    model = "Model S"
                    year = 2018
                }
            }

            println(roy)
        }

        class Person() {
            constructor(init: Person.() -> Unit) : this() {
                this.init()
            }

            var name: String by Delegates.notNull()
            var age: Int by Delegates.notNull()
            var height: Int by Delegates.notNull()
            var single: Boolean by Delegates.notNull()
            val cars: MutableList<Car> by lazy { arrayListOf<Car>() }

            override fun toString(): String {
                return "name=$name, age=$age, " +
                        "height=$height, " +
                        "single=${when (single) {
                            true -> "looking for a girl friend T___T"
                            false -> "Happy!!"
                        }}\nCars: $cars"
            }
        }

        class Car() {

            var brand: String by Delegates.notNull()
            var model: String by Delegates.notNull()
            var year: Int by Delegates.notNull()

            override fun toString(): String {
                return "(brand=$brand, model=$model, year=$year)"
            }
        }

        fun Person.car(init: Car.() -> Unit): Unit {
            cars.add(Car().apply(init))
        }

    }
}

我还没有找到一种方法，可以强制在DSL中初始化一些字段，比如显示错误而不是抛出异常。如果有人知道就告诉我。

在kotlin中可以使用可选参数 例子:

fun myFunc(p1: String, p2: Int = -1, p3: Long = -1, p4: String = "default") {
    System.out.printf("parameter %s %d %d %s\n", p1, p2, p3, p4)
}

然后

myFunc("a")
myFunc("a", 1)
myFunc("a", 1, 2)
myFunc("a", 1, 2, "b")