嗨，我是Kotlin世界的新手。我喜欢我目前所看到的，并开始考虑将我们在应用程序中使用的一些库从Java转换为Kotlin。
这些库充满了带有setter、getter和Builder类的pojo。现在我已经在谷歌上找到了在Kotlin中实现Builders的最佳方法，但没有成功。
第二次更新:问题是如何写一个建设者设计模式的一个简单的pojo与一些参数在Kotlin?下面的代码是我尝试编写java代码，然后使用eclipse-kotlin-plugin转换为Kotlin。
class Car private constructor(builder:Car.Builder) {
var model:String? = null
var year:Int = 0
init {
this.model = builder.model
this.year = builder.year
}
companion object Builder {
var model:String? = null
private set
var year:Int = 0
private set
fun model(model:String):Builder {
this.model = model
return this
}
fun year(year:Int):Builder {
this.year = year
return this
}
fun build():Car {
val car = Car(this)
return car
}
}
}
我在Kotlin中实现了一个基本的Builder模式，代码如下:
data class DialogMessage(
var title: String = "",
var message: String = ""
) {
class Builder( context: Context){
private var context: Context = context
private var title: String = ""
private var message: String = ""
fun title( title : String) = apply { this.title = title }
fun message( message : String ) = apply { this.message = message }
fun build() = KeyoDialogMessage(
title,
message
)
}
private lateinit var dialog : Dialog
fun show(){
this.dialog= Dialog(context)
.
.
.
dialog.show()
}
fun hide(){
if( this.dialog != null){
this.dialog.dismiss()
}
}
}
最后
Java:
new DialogMessage.Builder( context )
.title("Title")
.message("Message")
.build()
.show();
科特林：
DialogMessage.Builder( context )
.title("Title")
.message("")
.build()
.show()
我看到过许多将额外乐趣作为构建者的例子。我个人喜欢这种方法。节省编写构建程序的精力。
package android.zeroarst.lab.koltinlab
import kotlin.properties.Delegates
class Lab {
companion object {
@JvmStatic fun main(args: Array<String>) {
val roy = Person {
name = "Roy"
age = 33
height = 173
single = true
car {
brand = "Tesla"
model = "Model X"
year = 2017
}
car {
brand = "Tesla"
model = "Model S"
year = 2018
}
}
println(roy)
}
class Person() {
constructor(init: Person.() -> Unit) : this() {
this.init()
}
var name: String by Delegates.notNull()
var age: Int by Delegates.notNull()
var height: Int by Delegates.notNull()
var single: Boolean by Delegates.notNull()
val cars: MutableList<Car> by lazy { arrayListOf<Car>() }
override fun toString(): String {
return "name=$name, age=$age, " +
"height=$height, " +
"single=${when (single) {
true -> "looking for a girl friend T___T"
false -> "Happy!!"
}}\nCars: $cars"
}
}
class Car() {
var brand: String by Delegates.notNull()
var model: String by Delegates.notNull()
var year: Int by Delegates.notNull()
override fun toString(): String {
return "(brand=$brand, model=$model, year=$year)"
}
}
fun Person.car(init: Car.() -> Unit): Unit {
cars.add(Car().apply(init))
}
}
}
我还没有找到一种方法，可以强制在DSL中初始化一些字段，比如显示错误而不是抛出异常。如果有人知道就告诉我。
