我怎么能看到当前的urlpatterns“反向”正在寻找?
我在一个视图中调用了逆向,我认为这个论证应该成立,但实际上并不成立。有什么办法能让我知道为什么我的图案没有?
我怎么能看到当前的urlpatterns“反向”正在寻找?
我在一个视图中调用了逆向,我认为这个论证应该成立,但实际上并不成立。有什么办法能让我知道为什么我的图案没有?
当前回答
def get_resolved_urls(url_patterns):
url_patterns_resolved = []
for entry in url_patterns:
if hasattr(entry, 'url_patterns'):
url_patterns_resolved += get_resolved_urls(
entry.url_patterns)
else:
url_patterns_resolved.append(entry)
return url_patterns_resolved
在python中manage.py shell
import urls
get_resolved_urls(urls.urlpatterns)
其他回答
import subprocces
res = subprocess.run(
'python manage.py show_urls',
capture_output=True,
shell=True,
)
url_list = [
line.split('\t')[0]
for line in res.stdout.decode().split('\n')
]
有一个activestate的配方
import urls
def show_urls(urllist, depth=0):
for entry in urllist:
print(" " * depth, entry.regex.pattern)
if hasattr(entry, 'url_patterns'):
show_urls(entry.url_patterns, depth + 1)
show_urls(urls.url_patterns)
如果你正在使用DRF,你可以通过从router.get_urls()(在你的Django应用的urls.py文件中)打印特定路由器的urlpatterns来打印所有的URL模式。
打开你的apps urls.py,并在文件底部添加打印语句,这样整个文件看起来就像这样:
import pprint
from django.urls import include, path
from rest_framework import routers
from . import views
router = routers.DefaultRouter()
router.register(r"users", views.UserViewSet, basename="User")
router.register(r"auth", views.AuthenticationView, basename="Auth")
router.register(r"dummy", views.DummyViewSet, basename="Dummy")
router.register("surveys", views.SurveyViewSet, basename="survey")
urlpatterns = [
path("", include(router.urls)),
]
pprint.pprint(router.get_urls())
然后,这些图案会像这样打印出来:
[<URLPattern '^users/$' [name='User-list']>,
<URLPattern '^users\.(?P<format>[a-z0-9]+)/?$' [name='User-list']>,
<URLPattern '^users/admins/$' [name='User-admins']>,
<URLPattern '^users/admins\.(?P<format>[a-z0-9]+)/?$' [name='User-admins']>,
<URLPattern '^users/current/$' [name='User-current']>,
<URLPattern '^users/current\.(?P<format>[a-z0-9]+)/?$' [name='User-current']>,
<URLPattern '^users/(?P<pk>[^/.]+)/$' [name='User-detail']>,
<URLPattern '^users/(?P<pk>[^/.]+)\.(?P<format>[a-z0-9]+)/?$' [name='User-detail']>,
<URLPattern '^auth/login/$' [name='Auth-login']>,
...
]
只要输入一个你知道不存在的url,服务器就会返回一个错误消息,其中包含一个url模式列表。
例如,如果你在http://localhost:8000/something上运行一个网站
输入
http://localhost:8000/something/blahNonsense,您的服务器将返回url搜索列表并在浏览器中显示它
Django >= 2.0列表解决方案
领养自@CesarCanassa
from django.conf import settings
from django.urls import URLPattern, URLResolver
URLCONF = __import__(settings.ROOT_URLCONF, {}, {}, [''])
def list_urls(patterns, path=None):
""" recursive """
if not path:
path = []
result = []
for pattern in patterns:
if isinstance(pattern, URLPattern):
result.append(''.join(path) + str(pattern.pattern))
elif isinstance(pattern, URLResolver):
result += list_urls(pattern.url_patterns, path + [str(pattern.pattern)])
return result