就像这样:

var mylist = $('#myUL');
var listitems = mylist.children('li').get();
listitems.sort(function(a, b) {
   return $(a).text().toUpperCase().localeCompare($(b).text().toUpperCase());
})
$.each(listitems, function(idx, itm) { mylist.append(itm); });

来自本页:http://www.onemoretake.com/2009/02/25/sorting-elements-with-jquery/

以上代码将使用id 'myUL'对无序列表进行排序。

或者你也可以使用TinySort这样的插件。https://github.com/Sjeiti/TinySort

$(".list li").sort(asc_sort).appendTo('.list');
//$("#debug").text("Output:");
// accending sort
function asc_sort(a, b){
    return ($(b).text()) < ($(a).text()) ? 1 : -1;    
}

// decending sort
function dec_sort(a, b){
    return ($(b).text()) > ($(a).text()) ? 1 : -1;    
}

现场演示:http://jsbin.com/eculis/876/edit

@SolutionYogi的答案很有魅力，但似乎使用$。这两种方法都不如直接添加列表来得直接和有效:

var mylist = $('#list');
var listitems = mylist.children('li').get();

listitems.sort(function(a, b) {
   return $(a).text().toUpperCase().localeCompare($(b).text().toUpperCase());
})

mylist.empty().append(listitems);

小提琴

改进基于Jeetendra Chauhan的回答

$('ul.menu').each(function(){
    $(this).children('li').sort((a,b)=>a.innerText.localeCompare(b.innerText)).appendTo(this);
});

为什么我认为这是一个进步:

using each to support running on more than one ul using children('li') instead of ('ul li') is important because we only want to process direct children and not descendants using the arrow function (a,b)=> just looks better (IE not supported) using vanilla innerText instead of $(a).text() for speed improvement using vanilla localeCompare improves speed in case of equal elements (rare in real life usage) using appendTo(this) instead of using another selector will make sure that even if the selector catches more than one ul still nothing breaks

你不需要jQuery来做这个…

function sortUnorderedList(ul, sortDescending) {
  if(typeof ul == "string")
    ul = document.getElementById(ul);

  // Idiot-proof, remove if you want
  if(!ul) {
    alert("The UL object is null!");
    return;
  }

  // Get the list items and setup an array for sorting
  var lis = ul.getElementsByTagName("LI");
  var vals = [];

  // Populate the array
  for(var i = 0, l = lis.length; i < l; i++)
    vals.push(lis[i].innerHTML);

  // Sort it
  vals.sort();

  // Sometimes you gotta DESC
  if(sortDescending)
    vals.reverse();

  // Change the list on the page
  for(var i = 0, l = lis.length; i < l; i++)
    lis[i].innerHTML = vals[i];
}

易于使用…

sortUnorderedList("ID_OF_LIST");

现场演示→

为了使这个工作在包括Chrome在内的所有浏览器中工作，你需要使sort()的回调函数返回-1、0或1。

参见http://inderpreetsingh.com/2010/12/01/chromes-javascript-sort-array-function-is-different-yet-proper/

function sortUL(selector) {
    $(selector).children("li").sort(function(a, b) {
        var upA = $(a).text().toUpperCase();
        var upB = $(b).text().toUpperCase();
        return (upA < upB) ? -1 : (upA > upB) ? 1 : 0;
    }).appendTo(selector);
}
sortUL("ul.mylist");