如何使用python smtplib发送电子邮件到多个收件人?

经过大量的搜索，我无法找到如何使用smtplib。发送邮件到多个收件人。问题是每次发送邮件时，邮件标题似乎包含多个地址，但实际上只有第一个收件人会收到电子邮件。

问题似乎出在邮件上。Message模块期望与smtplb .sendmail()函数不同的内容。

简而言之，要发送给多个收件人，您应该将标题设置为一串以逗号分隔的电子邮件地址。sendmail()参数to_addr应该是一个电子邮件地址列表。

from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
import smtplib

msg = MIMEMultipart()
msg["Subject"] = "Example"
msg["From"] = "me@example.com"
msg["To"] = "malcom@example.com,reynolds@example.com,firefly@example.com"
msg["Cc"] = "serenity@example.com,inara@example.com"
body = MIMEText("example email body")
msg.attach(body)
smtp = smtplib.SMTP("mailhost.example.com", 25)
smtp.sendmail(msg["From"], msg["To"].split(",") + msg["Cc"].split(","), msg.as_string())
smtp.quit()

当前回答

这真的很管用，我花了很多时间尝试多种变体。

import smtplib
from email.mime.text import MIMEText

s = smtplib.SMTP('smtp.uk.xensource.com')
s.set_debuglevel(1)
msg = MIMEText("""body""")
sender = 'me@example.com'
recipients = ['john.doe@example.com', 'john.smith@example.co.uk']
msg['Subject'] = "subject line"
msg['From'] = sender
msg['To'] = ", ".join(recipients)
s.sendmail(sender, recipients, msg.as_string())

2012-09-14 10:44:00

其他回答

实际上问题在于SMTP。发送邮件和电子邮件。MIMEText需要两个不同的东西。

电子邮件。MIMEText为电子邮件正文设置了“To:”标头。它仅用于向另一端的人显示结果，并且像所有电子邮件标题一样，必须是单个字符串。(请注意，它实际上不必与实际接收消息的人有任何关系。)

SMTP。另一方面，sendmail为SMTP协议设置消息的“信封”。它需要一个Python字符串列表，每个字符串都有一个地址。

所以，你需要做的就是将收到的两个回复结合起来。将msg['To']设置为单个字符串，但将原始列表传递给sendmail:

emails = ['a.com','b.com', 'c.com']
msg['To'] = ', '.join( emails ) 
....
s.sendmail( msg['From'], emails, msg.as_string())

2018-05-14 07:17:19

我尝试了下面的方法，效果很好:)

rec_list =  ['first@example.com', 'second@example.com']
rec =  ', '.join(rec_list)

msg['To'] = rec

send_out = smtplib.SMTP('localhost')
send_out.sendmail(me, rec_list, msg.as_string())

2017-11-24 03:57:42

对于那些希望只发送一个“to”报头的消息，下面的代码可以解决这个问题。确保你的接收者变量是一个字符串列表。

# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = title
msg['From'] = f'support@{config("domain_base")}'
msg['To'] =  "me"
message_content += f"""
    <br /><br />
    Regards,<br />
    Company Name<br />
    The {config("domain_base")} team
"""
body = MIMEText(message_content, 'html')
msg.attach(body)

try:
    smtpObj = smtplib.SMTP('localhost')
    for r in receivers:
        del msg['To']
        msg['To'] =  r #"Customer /n" + r
        smtpObj.sendmail(f"support@{config('domain_base')}", r, msg.as_string())
    smtpObj.quit()      
    return {"message": "Successfully sent email"}
except smtplib.SMTPException:
    return {"message": "Error: unable to send email"}

2022-07-28 10:01:05

这对我很管用。

import smtplib
from email.mime.text import MIMEText

s = smtplib.SMTP('smtp.uk.xensource.com')
s.set_debuglevel(1)
msg = MIMEText("""body""")
sender = 'me@example.com'
recipients = 'john.doe@example.com,john.smith@example.co.uk'
msg['Subject'] = "subject line"
msg['From'] = sender
msg['To'] = recipients
s.sendmail(sender, recipients.split(','), msg.as_string())

2016-07-07 07:37:19

您可以在将收件人电子邮件写入文本文件时尝试此操作

from email.mime.text import MIMEText
from email.header import Header
import smtplib

f =  open('emails.txt', 'r').readlines()
for n in f:
     emails = n.rstrip()
server = smtplib.SMTP('smtp.uk.xensource.com')
server.ehlo()
server.starttls()
body = "Test Email"
subject = "Test"
from = "me@example.com"
to = emails
msg = MIMEText(body,'plain','utf-8')
msg['Subject'] = Header(subject, 'utf-8')
msg['From'] =  Header(from, 'utf-8')
msg['To'] = Header(to, 'utf-8')
text = msg.as_string()
try:
   server.send(from, emails, text)
   print('Message Sent Succesfully')
except:
   print('There Was An Error While Sending The Message')

2018-05-07 10:51:57

如何使用python smtplib发送电子邮件到多个收件人?

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