java有一个静态方法U.formatJson(json)。 支持5种格式类型:2,3,4，制表符和压缩。生活的例子

import com.github.underscore.U;

import static com.github.underscore.Json.JsonStringBuilder.Step.TABS;
import static com.github.underscore.Json.JsonStringBuilder.Step.TWO_SPACES;

public class MyClass {

    public static void main(String args[]) {
        String json = "{\"Price\": {"
        + "    \"LineItems\": {"
        + "        \"LineItem\": {"
        + "            \"UnitOfMeasure\": \"EACH\", \"Quantity\": 2, \"ItemID\": \"ItemID\""
        + "        }"
        + "    },"
        + "    \"Currency\": \"USD\","
        + "    \"EnterpriseCode\": \"EnterpriseCode\""
        + "}}";
        System.out.println(U.formatJson(json, TWO_SPACES)); 
        System.out.println(U.formatJson(json, TABS)); 
    }
}

输出:

{
  "Price": {
    "LineItems": {
      "LineItem": {
        "UnitOfMeasure": "EACH",
        "Quantity": 2,
        "ItemID": "ItemID"
      }
    },
    "Currency": "USD",
    "EnterpriseCode": "EnterpriseCode"
  }
}
{
    "Price": {
        "LineItems": {
            "LineItem": {
                "UnitOfMeasure": "EACH",
                "Quantity": 2,
                "ItemID": "ItemID"
            }
        },
        "Currency": "USD",
        "EnterpriseCode": "EnterpriseCode"
    }
}

我用的是org。Json内置方法来漂亮地打印数据。

import org.json.JSONObject;
JSONObject json = new JSONObject(jsonString); // Convert text to object
System.out.println(json.toString(4)); // Print it with specified indentation

JSON中每个定义的字段顺序是随机的。具体的顺序取决于解析器的实现。

你可以像下面这样使用Gson

Gson gson = new GsonBuilder().setPrettyPrinting().create();
String jsonString = gson.toJson(object);

从post JSON漂亮打印使用Gson

或者，你可以像下面这样使用Jackson

ObjectMapper mapper = new ObjectMapper();
String perttyStr = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(object);

漂亮的Java JSON打印(Jackson)

希望这对你有所帮助!

谷歌的GSON可以很好地做到这一点:

Gson gson = new GsonBuilder().setPrettyPrinting().create();
JsonParser jp = new JsonParser();
JsonElement je = jp.parse(uglyJsonString);
String prettyJsonString = gson.toJson(je);

或者因为现在推荐使用来自JsonParser的静态解析方法，你也可以使用这个代替:

Gson gson = new GsonBuilder().setPrettyPrinting().create();
JsonElement je = JsonParser.parseString​(uglyJsonString);
String prettyJsonString = gson.toJson(je);

下面是导入语句:

import com.google.gson.*;

这是Gradle的依赖项:

implementation 'com.google.code.gson:gson:2.8.7'

遵循JSON-P 1.0规范(JSR-353)，对于给定的JsonStructure (JsonObject或JsonArray)，一个更当前的解决方案可能是这样的:

import java.io.StringWriter;
import java.util.HashMap;
import java.util.Map;

import javax.json.Json;
import javax.json.JsonStructure;
import javax.json.JsonWriter;
import javax.json.JsonWriterFactory;
import javax.json.stream.JsonGenerator;

public class PrettyJson {

    private static JsonWriterFactory FACTORY_INSTANCE;

    public static String toString(final JsonStructure status) {

        final StringWriter stringWriter = new StringWriter();

        final JsonWriter jsonWriter = getPrettyJsonWriterFactory()
                .createWriter(stringWriter);

        jsonWriter.write(status);
        jsonWriter.close();

        return stringWriter.toString();
    }

    private static JsonWriterFactory getPrettyJsonWriterFactory() {
        if (null == FACTORY_INSTANCE) {
            final Map<String, Object> properties = new HashMap<>(1);
            properties.put(JsonGenerator.PRETTY_PRINTING, true);
            FACTORY_INSTANCE = Json.createWriterFactory(properties);
        }
        return FACTORY_INSTANCE;
    }

}

与杰克逊(com.fasterxml.jackson.databind):

ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(jsonObject))

如何启用漂亮的JSON打印输出(Jackson)

我知道这已经在答案中，但我想在这里单独写它，因为很可能您已经将Jackson作为依赖项，因此您需要的只是额外的一行代码