我想创建一个使用互联网的应用程序,我试图创建一个功能,检查连接是否可用,如果它不是,去到一个活动,有一个重试按钮和解释。

附件是我的代码到目前为止,但我得到的错误语法错误,插入“}”来完成MethodBody。

现在我已经把这些放在试图让它工作,但到目前为止没有运气…任何帮助都将不胜感激。

public class TheEvoStikLeagueActivity extends Activity {
    private final int SPLASH_DISPLAY_LENGHT = 3000;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle icicle) {
        super.onCreate(icicle);
        setContentView(R.layout.main);

        private boolean checkInternetConnection() {
            ConnectivityManager conMgr = (ConnectivityManager) getSystemService (Context.CONNECTIVITY_SERVICE);
            // ARE WE CONNECTED TO THE NET
            if (conMgr.getActiveNetworkInfo() != null
                    && conMgr.getActiveNetworkInfo().isAvailable()
                    && conMgr.getActiveNetworkInfo().isConnected()) {

                return true;

                /* New Handler to start the Menu-Activity
                 * and close this Splash-Screen after some seconds.*/
                new Handler().postDelayed(new Runnable() {
                    public void run() {
                        /* Create an Intent that will start the Menu-Activity. */
                        Intent mainIntent = new Intent(TheEvoStikLeagueActivity.this, IntroActivity.class);
                        TheEvoStikLeagueActivity.this.startActivity(mainIntent);
                        TheEvoStikLeagueActivity.this.finish();
                    }
                }, SPLASH_DISPLAY_LENGHT);
            } else {
                return false;

                Intent connectionIntent = new Intent(TheEvoStikLeagueActivity.this, HomeActivity.class);
                TheEvoStikLeagueActivity.this.startActivity(connectionIntent);
                TheEvoStikLeagueActivity.this.finish();
            }
        }
    }

当前回答

public boolean checkInternetConnection(Context context) {
    ConnectivityManager connectivity = (ConnectivityManager) context
        .getSystemService(Context.CONNECTIVITY_SERVICE);
    if (connectivity == null) {
        return false;
    } else {
        NetworkInfo[] info = connectivity.getAllNetworkInfo();
        if (info != null) {
            for (int i = 0; i < info.length; i++){
                if (info[i].getState()==NetworkInfo.State.CONNECTED){
                    return true;
                }
            }
        }
    }
    return false;
}

其他回答

你不能在另一个方法中创建一个方法,将私有布尔checkInternetConnection(){方法移出onCreate

你可以简单地ping一个像谷歌这样的在线网站:

public boolean isConnected() throws InterruptedException, IOException {
    String command = "ping -c 1 google.com";
    return Runtime.getRuntime().exec(command).waitFor() == 0;
}

这个方法检查手机是否连接到互联网,如果连接则返回true:

private boolean isNetworkConnected() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

    return cm.getActiveNetworkInfo() != null && cm.getActiveNetworkInfo().isConnected();
}

在清单,

<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

编辑: 这个方法实际上是检查设备是否连接到互联网(有可能它连接到网络但没有连接到互联网)。

public boolean isInternetAvailable() {
    try {
        InetAddress ipAddr = InetAddress.getByName("google.com"); 
        //You can replace it with your name
            return !ipAddr.equals("");

        } catch (Exception e) {
            return false;
    }
}
public boolean checkInternetConnection(Context context) {
    ConnectivityManager connectivity = (ConnectivityManager) context
        .getSystemService(Context.CONNECTIVITY_SERVICE);
    if (connectivity == null) {
        return false;
    } else {
        NetworkInfo[] info = connectivity.getAllNetworkInfo();
        if (info != null) {
            for (int i = 0; i < info.length; i++){
                if (info[i].getState()==NetworkInfo.State.CONNECTED){
                    return true;
                }
            }
        }
    }
    return false;
}

我的问题是IsInternetAvailable答案没有测试蜂窝网络,而只是在连接wifi的情况下。这个答案适用于wifi和移动数据:

如何检查网络连接在WIFI和3G(数据计划)移动启用或禁用?