我想创建一个使用互联网的应用程序,我试图创建一个功能,检查连接是否可用,如果它不是,去到一个活动,有一个重试按钮和解释。

附件是我的代码到目前为止,但我得到的错误语法错误,插入“}”来完成MethodBody。

现在我已经把这些放在试图让它工作,但到目前为止没有运气…任何帮助都将不胜感激。

public class TheEvoStikLeagueActivity extends Activity {
    private final int SPLASH_DISPLAY_LENGHT = 3000;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle icicle) {
        super.onCreate(icicle);
        setContentView(R.layout.main);

        private boolean checkInternetConnection() {
            ConnectivityManager conMgr = (ConnectivityManager) getSystemService (Context.CONNECTIVITY_SERVICE);
            // ARE WE CONNECTED TO THE NET
            if (conMgr.getActiveNetworkInfo() != null
                    && conMgr.getActiveNetworkInfo().isAvailable()
                    && conMgr.getActiveNetworkInfo().isConnected()) {

                return true;

                /* New Handler to start the Menu-Activity
                 * and close this Splash-Screen after some seconds.*/
                new Handler().postDelayed(new Runnable() {
                    public void run() {
                        /* Create an Intent that will start the Menu-Activity. */
                        Intent mainIntent = new Intent(TheEvoStikLeagueActivity.this, IntroActivity.class);
                        TheEvoStikLeagueActivity.this.startActivity(mainIntent);
                        TheEvoStikLeagueActivity.this.finish();
                    }
                }, SPLASH_DISPLAY_LENGHT);
            } else {
                return false;

                Intent connectionIntent = new Intent(TheEvoStikLeagueActivity.this, HomeActivity.class);
                TheEvoStikLeagueActivity.this.startActivity(connectionIntent);
                TheEvoStikLeagueActivity.this.finish();
            }
        }
    }

当前回答

你可以简单地ping一个像谷歌这样的在线网站:

public boolean isConnected() throws InterruptedException, IOException {
    String command = "ping -c 1 google.com";
    return Runtime.getRuntime().exec(command).waitFor() == 0;
}

其他回答

接受的答案的EDIT显示了如何检查internet上的某些内容是否可以到达。我不得不等了很长时间才得到答案,但事实并非如此(使用的是没有互联网连接的wifi)。不幸的是InetAddress。getByName没有超时参数,所以下面的代码围绕它工作:

private boolean internetConnectionAvailable(int timeOut) {
    InetAddress inetAddress = null;
    try {
        Future<InetAddress> future = Executors.newSingleThreadExecutor().submit(new Callable<InetAddress>() {
            @Override
            public InetAddress call() {
                try {
                    return InetAddress.getByName("google.com");
                } catch (UnknownHostException e) {
                    return null;
                }
            }
        });
        inetAddress = future.get(timeOut, TimeUnit.MILLISECONDS);
        future.cancel(true);
    } catch (InterruptedException e) {
    } catch (ExecutionException e) {
    } catch (TimeoutException e) {
    } 
    return inetAddress!=null && !inetAddress.equals("");
}

你不能在另一个方法中创建一个方法,将私有布尔checkInternetConnection(){方法移出onCreate

试试下面的代码:

public static boolean isNetworkAvailable(Context context) {
        boolean outcome = false;

        if (context != null) {
            ConnectivityManager cm = (ConnectivityManager) context
                    .getSystemService(Context.CONNECTIVITY_SERVICE);

            NetworkInfo[] networkInfos = cm.getAllNetworkInfo();

            for (NetworkInfo tempNetworkInfo : networkInfos) {


                /**
                 * Can also check if the user is in roaming
                 */
                if (tempNetworkInfo.isConnected()) {
                    outcome = true;
                    break;
                }
            }
        }

        return outcome;
    }

我的问题是IsInternetAvailable答案没有测试蜂窝网络,而只是在连接wifi的情况下。这个答案适用于wifi和移动数据:

如何检查网络连接在WIFI和3G(数据计划)移动启用或禁用?

使用此代码检查网络连接

ConnectivityManager connectivityManager = (ConnectivityManager) ctx
                .getSystemService(Context.CONNECTIVITY_SERVICE);
        if ((connectivityManager
                .getNetworkInfo(ConnectivityManager.TYPE_MOBILE) != null && connectivityManager
                .getNetworkInfo(ConnectivityManager.TYPE_MOBILE).getState() == NetworkInfo.State.CONNECTED)
                || (connectivityManager
                        .getNetworkInfo(ConnectivityManager.TYPE_WIFI) != null && connectivityManager
                        .getNetworkInfo(ConnectivityManager.TYPE_WIFI)
                        .getState() == NetworkInfo.State.CONNECTED)) {
            return true;
        } else {
            return false;
        }