我想执行以下命令:
./a.out 1
./a.out 2
./a.out 3
./a.out 4
.
.
. and so on
如何写这个东西作为一个循环在Makefile?
我想执行以下命令:
./a.out 1
./a.out 2
./a.out 3
./a.out 4
.
.
. and so on
如何写这个东西作为一个循环在Makefile?
当前回答
尽管GNUmake表工具包有一个真正的while循环(不管这在GNUmake编程中意味着什么,它有两个或三个执行阶段),如果需要的是一个迭代列表,有一个简单的解决方案,即interval。为了好玩,我们把数字也转换成十六进制:
include gmtt/gmtt.mk
# generate a list of 20 numbers, starting at 3 with an increment of 5
NUMBER_LIST := $(call interval,3,20,5)
# convert the numbers in hexadecimal (0x0 as first operand forces arithmetic result to hex) and strip '0x'
NUMBER_LIST_IN_HEX := $(foreach n,$(NUMBER_LIST),$(call lstrip,$(call add,0x0,$(n)),0x))
# finally create the filenames with a simple patsubst
FILE_LIST := $(patsubst %,./a%.out,$(NUMBER_LIST_IN_HEX))
$(info $(FILE_LIST))
输出:
./a3.out ./a8.out ./ad.out ./a12.out ./a17.out ./a1c.out ./a21.out ./a26.out ./a2b.out ./a30.out ./a35.out ./a3a.out ./a3f.out ./a44.out ./a49.out ./a4e.out ./a53.out ./a58.out ./a5d.out ./a62.out
其他回答
#I have a bunch of files that follow the naming convention
#soxfile1 soxfile1.o soxfile1.sh soxfile1.ini soxfile1.txt soxfile1.err
#soxfile2 soxfile2.o soxfile2.sh soxfile2.ini soxfile2.txt soxfile2.err
#sox... .... ..... .... .... ....
#in the makefile, only select the soxfile1.. soxfile2... to install dir
#My GNU makefile solution follows:
tgt=/usr/local/bin/ #need to use sudo
tgt2=/backup/myapplication/ #regular backup
install:
for var in $$(ls -f sox* | grep -v '\.' ) ; \
do \
sudo cp -f $$var ${TGT} ; \
cp -f $$var ${TGT2} ; \
done
#The ls command selects all the soxfile* including the *.something
#The grep command rejects names with a dot in it, leaving
#My desired executable files in a list.
一个简单的、独立于shell/平台的纯宏解决方案是…
# GNU make (`gmake`) compatible; ref: <https://www.gnu.org/software/make/manual>
define EOL
$()
endef
%sequence = $(if $(word ${1},${2}),$(wordlist 1,${1},${2}),$(call %sequence,${1},${2} $(words _ ${2})))
.PHONY: target
target:
$(foreach i,$(call %sequence,10),./a.out ${i}${EOL})
如果您正在使用GNU make,您可以尝试一下
NUMBERS = 1 2 3 4 doit: $(foreach var,$(NUMBERS),./a.out $(var);)
哪个将生成并执行
./a.out 1; ./a.out 2; ./a.out 3; ./a.out 4;
这个答案,就像@Vroomfondel的答案一样,旨在以优雅的方式规避循环问题。
我的想法是让make生成循环本身作为一个导入的makefile,就像这样:
include Loop.mk
Loop.mk:Loop.sh
Loop.sh > $@
shell脚本可以像你喜欢的那样高级,但可以是一个最小的工作示例
#!/bin/bash
LoopTargets=""
NoTargest=5
for Target in `seq $NoTargest` ; do
File="target_${Target}.dat"
echo $File:data_script.sh
echo $'\t'./data_script.ss $Target
LoopTargets="$LoopTargets $File"
done
echo;echo;echo LoopTargets:=$LoopTargets
生成文件
target_1.dat:data_script.sh
./data_script.ss 1
target_2.dat:data_script.sh
./data_script.ss 2
target_3.dat:data_script.sh
./data_script.ss 3
target_4.dat:data_script.sh
./data_script.ss 4
target_5.dat:data_script.sh
./data_script.ss 5
LoopTargets:= target_1.dat target_2.dat target_3.dat target_4.dat target_5.dat
这样做的好处是make本身可以跟踪已经生成的文件以及需要(重新)生成的文件。同样,这也允许make使用-j标志进行并行化。
为了跨平台支持,让命令分隔符(用于在同一行上执行多个命令)成为可配置的。
例如,如果你在Windows平台上使用MinGW,命令分隔符是&:
NUMBERS = 1 2 3 4
CMDSEP = &
doit:
$(foreach number,$(NUMBERS),./a.out $(number) $(CMDSEP))
这将在一行中执行连接的命令:
./a.out 1 & ./a.out 2 & ./a.out 3 & ./a.out 4 &
正如前面提到的,在*nix平台上使用CMDSEP =;