我有以下内容…
chrome.extension.sendRequest({
req: "getDocument",
docu: pagedoc,
name: 'name'
}, function(response){
var efjs = response.reply;
});
调用下面的..
case "getBrowserForDocumentAttribute":
alert("ZOMG HERE");
sendResponse({
reply: getBrowserForDocumentAttribute(request.docu,request.name)
});
break;
然而，我的代码从未达到“ZOMG HERE”，而是在运行chrome.extension.sendRequest时抛出以下错误
Uncaught TypeError: Converting circular structure to JSON
chromeHidden.JSON.stringify
chrome.Port.postMessage
chrome.initExtension.chrome.extension.sendRequest
suggestQuery
有人知道是什么引起的吗?
根据MDN: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#issue_with_json.stringify_when_serializing_circular_references
它是一个循环json，不能直接转换。
解决方案1:
https://www.npmjs.com/package/flatted
// ESM
import {parse, stringify, toJSON, fromJSON} from 'flatted';
// CJS
const {parse, stringify, toJSON, fromJSON} = require('flatted');
const a = [{}];
a[0].a = a;
a.push(a);
stringify(a); // [["1","0"],{"a":"0"}]
解决方案2:(同样通过MDN)
https://github.com/douglascrockford/JSON-js
一种方法是从主对象中剥离对象和函数。并对更简单的形式进行stringalize
function simpleStringify (object){
// stringify an object, avoiding circular structures
// https://stackoverflow.com/a/31557814
var simpleObject = {};
for (var prop in object ){
if (!object.hasOwnProperty(prop)){
continue;
}
if (typeof(object[prop]) == 'object'){
continue;
}
if (typeof(object[prop]) == 'function'){
continue;
}
simpleObject[prop] = object[prop];
}
return JSON.stringify(simpleObject); // returns cleaned up JSON
};
如果你使用node js使用inspect()(参考文档)
import {inspect} from "util";
console.log(inspect(object));
根据zainengineer的回答…另一种方法是对对象进行深度复制，去掉循环引用并对结果进行字符串化。
function cleanStringify(object) {
if (object && typeof object === 'object') {
object = copyWithoutCircularReferences([object], object);
}
return JSON.stringify(object);
function copyWithoutCircularReferences(references, object) {
var cleanObject = {};
Object.keys(object).forEach(function(key) {
var value = object[key];
if (value && typeof value === 'object') {
if (references.indexOf(value) < 0) {
references.push(value);
cleanObject[key] = copyWithoutCircularReferences(references, value);
references.pop();
} else {
cleanObject[key] = '###_Circular_###';
}
} else if (typeof value !== 'function') {
cleanObject[key] = value;
}
});
return cleanObject;
}
}
// Example
var a = {
name: "a"
};
var b = {
name: "b"
};
b.a = a;
a.b = b;
console.log(cleanStringify(a));
console.log(cleanStringify(b));
你可能做过类似的事情
<Button onClick={fetchSuggestions}>
未能意识到您已将“事件对象”传递给该函数
如果你不想传递任何东西，只需发送一个空字符串
<Button onClick={() => fetchSuggestions()}>
const fetchSuggestions = async (propsSession) => {
const {
error,
hasNextDoc,
suggestions: moreSuggestions,
} = await fetcher(`/admin/fetchSuggestion`, {
initialRequest: !!propsSession,
session: propsSession || session,
});
}
