我有以下内容…

chrome.extension.sendRequest({
  req: "getDocument",
  docu: pagedoc,
  name: 'name'
}, function(response){
  var efjs = response.reply;
});

调用下面的..

case "getBrowserForDocumentAttribute":
  alert("ZOMG HERE");
  sendResponse({
    reply: getBrowserForDocumentAttribute(request.docu,request.name)
  });
  break;

然而,我的代码从未达到“ZOMG HERE”,而是在运行chrome.extension.sendRequest时抛出以下错误

 Uncaught TypeError: Converting circular structure to JSON
 chromeHidden.JSON.stringify
 chrome.Port.postMessage
 chrome.initExtension.chrome.extension.sendRequest
 suggestQuery

有人知道是什么引起的吗?


当前回答

我在这里遇到了一个不同的问题,我从html元素中获取值到对象数组,在一个字段中,我不正确地分配值,这导致了这个异常。 错误表达式:obj.firstname=$("txFirstName") 正确表达式:obj.firstname=$("txFirstName").val()

其他回答

我在NodeJS上是这样解决这个问题的:

var util = require('util');

// Our circular object
var obj = {foo: {bar: null}, a:{a:{a:{a:{a:{a:{a:{hi: 'Yo!'}}}}}}}};
obj.foo.bar = obj;

// Generate almost valid JS object definition code (typeof string)
var str = util.inspect(b, {depth: null});

// Fix code to the valid state (in this example it is not required, but my object was huge and complex, and I needed this for my case)
str = str
    .replace(/<Buffer[ \w\.]+>/ig, '"buffer"')
    .replace(/\[Function]/ig, 'function(){}')
    .replace(/\[Circular]/ig, '"Circular"')
    .replace(/\{ \[Function: ([\w]+)]/ig, '{ $1: function $1 () {},')
    .replace(/\[Function: ([\w]+)]/ig, 'function $1(){}')
    .replace(/(\w+): ([\w :]+GMT\+[\w \(\)]+),/ig, '$1: new Date("$2"),')
    .replace(/(\S+): ,/ig, '$1: null,');

// Create function to eval stringifyed code
var foo = new Function('return ' + str + ';');

// And have fun
console.log(JSON.stringify(foo(), null, 4));

根据zainengineer的回答…另一种方法是对对象进行深度复制,去掉循环引用并对结果进行字符串化。

function cleanStringify(object) { if (object && typeof object === 'object') { object = copyWithoutCircularReferences([object], object); } return JSON.stringify(object); function copyWithoutCircularReferences(references, object) { var cleanObject = {}; Object.keys(object).forEach(function(key) { var value = object[key]; if (value && typeof value === 'object') { if (references.indexOf(value) < 0) { references.push(value); cleanObject[key] = copyWithoutCircularReferences(references, value); references.pop(); } else { cleanObject[key] = '###_Circular_###'; } } else if (typeof value !== 'function') { cleanObject[key] = value; } }); return cleanObject; } } // Example var a = { name: "a" }; var b = { name: "b" }; b.a = a; a.b = b; console.log(cleanStringify(a)); console.log(cleanStringify(b));

你可能做过类似的事情

<Button onClick={fetchSuggestions}>

未能意识到您已将“事件对象”传递给该函数

如果你不想传递任何东西,只需发送一个空字符串

<Button onClick={() => fetchSuggestions()}>
  const fetchSuggestions = async (propsSession) => {
    const {
      error,
      hasNextDoc,
      suggestions: moreSuggestions,
    } = await fetcher(`/admin/fetchSuggestion`, {
      initialRequest: !!propsSession,
      session: propsSession || session,
    });
  }

在我的情况下,我使用React Native,并尝试调试

console.log(JSON.stringify(object))

得到了错误:

TypeError: Converting circular structure to JSON

似乎我可以通过使用简单的方法将对象记录到控制台:

console.log(object)

在我的例子中,它是在一些代码更改后留在单元测试中的flush()。

之前

it('something should be...', () => {
// do tests
flush();
}

it('something should be...', () => {
// do tests
}