用Python打印XML的最佳方法(或各种方法)是什么?


当前回答

使用etree。缩进和etree.tostring

import lxml.etree as etree

root = etree.fromstring('<html><head></head><body><h1>Welcome</h1></body></html>')
etree.indent(root, space="  ")
xml_string = etree.tostring(root, pretty_print=True).decode()
print(xml_string)

输出

<html>
  <head/>
  <body>
    <h1>Welcome</h1>
  </body>
</html>

删除名称空间和前缀

import lxml.etree as etree


def dump_xml(element):
    for item in element.getiterator():
        item.tag = etree.QName(item).localname

    etree.cleanup_namespaces(element)
    etree.indent(element, space="  ")
    result = etree.tostring(element, pretty_print=True).decode()
    return result


root = etree.fromstring('<cs:document xmlns:cs="http://blabla.com"><name>hello world</name></cs:document>')
xml_string = dump_xml(root)
print(xml_string)

输出

<document>
  <name>hello world</name>
</document>

其他回答

LXML是最近更新的,包含一个漂亮的打印函数

import lxml.etree as etree

x = etree.parse("filename")
print etree.tostring(x, pretty_print=True)

查看lxml教程: http://lxml.de/tutorial.html

下面是我解决难看的文本节点问题的解决方案。

uglyXml = doc.toprettyxml(indent='  ')

text_re = re.compile('>\n\s+([^<>\s].*?)\n\s+</', re.DOTALL)    
prettyXml = text_re.sub('>\g<1></', uglyXml)

print prettyXml

上面的代码将产生:

<?xml version="1.0" ?>
<issues>
  <issue>
    <id>1</id>
    <title>Add Visual Studio 2005 and 2008 solution files</title>
    <details>We need Visual Studio 2005/2008 project files for Windows.</details>
  </issue>
</issues>

而不是这样:

<?xml version="1.0" ?>
<issues>
  <issue>
    <id>
      1
    </id>
    <title>
      Add Visual Studio 2005 and 2008 solution files
    </title>
    <details>
      We need Visual Studio 2005/2008 project files for Windows.
    </details>
  </issue>
</issues>

免责声明:可能有一些限制。

我用几行代码解决了这个问题,打开文件,通过它并添加缩进,然后再次保存它。我使用的是小的xml文件,不想添加依赖项,也不想为用户安装更多的库。总之,这是我最后得出的结论:

    f = open(file_name,'r')
    xml = f.read()
    f.close()

    #Removing old indendations
    raw_xml = ''        
    for line in xml:
        raw_xml += line

    xml = raw_xml

    new_xml = ''
    indent = '    '
    deepness = 0

    for i in range((len(xml))):

        new_xml += xml[i]   
        if(i<len(xml)-3):

            simpleSplit = xml[i:(i+2)] == '><'
            advancSplit = xml[i:(i+3)] == '></'        
            end = xml[i:(i+2)] == '/>'    
            start = xml[i] == '<'

            if(advancSplit):
                deepness += -1
                new_xml += '\n' + indent*deepness
                simpleSplit = False
                deepness += -1
            if(simpleSplit):
                new_xml += '\n' + indent*deepness
            if(start):
                deepness += 1
            if(end):
                deepness += -1

    f = open(file_name,'w')
    f.write(new_xml)
    f.close()

这对我来说很有用,也许有人会用到它:)

如果你有xmllint,你可以生成一个子进程并使用它。xmllint——format <file>将其输入的XML漂亮地打印到标准输出。

注意,这个方法使用了python之外的程序,这使得它有点像黑客。

def pretty_print_xml(xml):
    proc = subprocess.Popen(
        ['xmllint', '--format', '/dev/stdin'],
        stdin=subprocess.PIPE,
        stdout=subprocess.PIPE,
    )
    (output, error_output) = proc.communicate(xml);
    return output

print(pretty_print_xml(data))

我遇到了这个问题,我是这样解决的:

def write_xml_file (self, file, xml_root_element, xml_declaration=False, pretty_print=False, encoding='unicode', indent='\t'):
    pretty_printed_xml = etree.tostring(xml_root_element, xml_declaration=xml_declaration, pretty_print=pretty_print, encoding=encoding)
    if pretty_print: pretty_printed_xml = pretty_printed_xml.replace('  ', indent)
    file.write(pretty_printed_xml)

在我的代码中,这个方法是这样调用的:

try:
    with open(file_path, 'w') as file:
        file.write('<?xml version="1.0" encoding="utf-8" ?>')

        # create some xml content using etree ...

        xml_parser = XMLParser()
        xml_parser.write_xml_file(file, xml_root, xml_declaration=False, pretty_print=True, encoding='unicode', indent='\t')

except IOError:
    print("Error while writing in log file!")

这只是因为etree默认使用两个空格来缩进,我发现这不是很强调缩进,因此不漂亮。我找不到任何树的设置或任何函数的参数来改变标准树缩进。我喜欢使用etree的简单性,但这真的让我很恼火。