您可以这样使用：

## declare an array variable
declare -a arr=("element1" "element2" "element3")

## now loop through the above array
for i in "${arr[@]}"
do
   echo "$i"
   # or do whatever with individual element of the array
done

# You can access them using echo "${arr[0]}", "${arr[1]}" also

也适用于多行数组声明

declare -a arr=("element1" 
                "element2" "element3"
                "element4"
                )

listOfNames="db_one db_two db_three"
for databaseName in $listOfNames
do
  echo $databaseName
done

或者只是

for databaseName in db_one db_two db_three
do
  echo $databaseName
done

这些答案中没有一个包含计数器。。。

#!/bin/bash
## declare an array variable
declare -a array=("one" "two" "three")

# get length of an array
arraylength=${#array[@]}

# use for loop to read all values and indexes
for (( i=0; i<${arraylength}; i++ ));
do
  echo "index: $i, value: ${array[$i]}"
done

输出：

index: 0, value: one
index: 1, value: two
index: 2, value: three

如果您使用的是Korn shell，则有“set-A databaseName”，否则有“declare-A databaseName”

要在所有外壳上编写脚本，

 set -A databaseName=("db1" "db2" ....) ||
        declare -a databaseName=("db1" "db2" ....)
# now loop 
for dbname in "${arr[@]}"
do
   echo "$dbname"  # or whatever

done

它应该在所有外壳上工作。

试试这个。它正在运行和测试。

for k in "${array[@]}"
do
    echo $k
done

# For accessing with the echo command: echo ${array[0]}, ${array[1]}

每个Bash脚本/会话的可能第一行：

say() { for line in "${@}" ; do printf "%s\n" "${line}" ; done ; }

使用例如：

$ aa=( 7 -4 -e ) ; say "${aa[@]}"
7
-4
-e

可以考虑：echo在此处将-e解释为选项