是否有办法确定当前设备的屏幕大小的类别,如小,正常,大,xlarge?

不是密度,而是屏幕尺寸。


当前回答

下面的代码充实了上面的答案,将屏幕大小显示为Toast。

//Determine screen size
if ((getResources().getConfiguration().screenLayout & Configuration.SCREENLAYOUT_SIZE_MASK) == Configuration.SCREENLAYOUT_SIZE_LARGE) {
    Toast.makeText(this, "Large screen", Toast.LENGTH_LONG).show();
}
else if ((getResources().getConfiguration().screenLayout & Configuration.SCREENLAYOUT_SIZE_MASK) == Configuration.SCREENLAYOUT_SIZE_NORMAL) {
    Toast.makeText(this, "Normal sized screen", Toast.LENGTH_LONG).show();
}
else if ((getResources().getConfiguration().screenLayout & Configuration.SCREENLAYOUT_SIZE_MASK) == Configuration.SCREENLAYOUT_SIZE_SMALL) {
    Toast.makeText(this, "Small sized screen", Toast.LENGTH_LONG).show();
}
else {
    Toast.makeText(this, "Screen size is neither large, normal or small", Toast.LENGTH_LONG).show();
}

下面的代码将屏幕密度显示为Toast。

//Determine density
DisplayMetrics metrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(metrics);
int density = metrics.densityDpi;

if (density == DisplayMetrics.DENSITY_HIGH) {
    Toast.makeText(this, "DENSITY_HIGH... Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}
else if (density == DisplayMetrics.DENSITY_MEDIUM) {
    Toast.makeText(this, "DENSITY_MEDIUM... Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}
else if (density == DisplayMetrics.DENSITY_LOW) {
    Toast.makeText(this, "DENSITY_LOW... Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}
else {
    Toast.makeText(this, "Density is neither HIGH, MEDIUM OR LOW.  Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}

其他回答

您可以使用配置。screenLayout位掩码。

例子:

if ((getResources().getConfiguration().screenLayout & 
    Configuration.SCREENLAYOUT_SIZE_MASK) == 
        Configuration.SCREENLAYOUT_SIZE_LARGE) {
    // on a large screen device ...

}

下面的代码充实了上面的答案,将屏幕大小显示为Toast。

//Determine screen size
if ((getResources().getConfiguration().screenLayout & Configuration.SCREENLAYOUT_SIZE_MASK) == Configuration.SCREENLAYOUT_SIZE_LARGE) {
    Toast.makeText(this, "Large screen", Toast.LENGTH_LONG).show();
}
else if ((getResources().getConfiguration().screenLayout & Configuration.SCREENLAYOUT_SIZE_MASK) == Configuration.SCREENLAYOUT_SIZE_NORMAL) {
    Toast.makeText(this, "Normal sized screen", Toast.LENGTH_LONG).show();
}
else if ((getResources().getConfiguration().screenLayout & Configuration.SCREENLAYOUT_SIZE_MASK) == Configuration.SCREENLAYOUT_SIZE_SMALL) {
    Toast.makeText(this, "Small sized screen", Toast.LENGTH_LONG).show();
}
else {
    Toast.makeText(this, "Screen size is neither large, normal or small", Toast.LENGTH_LONG).show();
}

下面的代码将屏幕密度显示为Toast。

//Determine density
DisplayMetrics metrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(metrics);
int density = metrics.densityDpi;

if (density == DisplayMetrics.DENSITY_HIGH) {
    Toast.makeText(this, "DENSITY_HIGH... Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}
else if (density == DisplayMetrics.DENSITY_MEDIUM) {
    Toast.makeText(this, "DENSITY_MEDIUM... Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}
else if (density == DisplayMetrics.DENSITY_LOW) {
    Toast.makeText(this, "DENSITY_LOW... Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}
else {
    Toast.makeText(this, "Density is neither HIGH, MEDIUM OR LOW.  Density is " + String.valueOf(density), Toast.LENGTH_LONG).show();
}

感谢上面的回答,这对我帮助很大:-)但对于那些(像我一样)被迫仍然支持Android 1.5的人,我们可以使用java反射来向后兼容:

Configuration conf = getResources().getConfiguration();
int screenLayout = 1; // application default behavior
try {
    Field field = conf.getClass().getDeclaredField("screenLayout");
    screenLayout = field.getInt(conf);
} catch (Exception e) {
    // NoSuchFieldException or related stuff
}
// Configuration.SCREENLAYOUT_SIZE_MASK == 15
int screenType = screenLayout & 15;
// Configuration.SCREENLAYOUT_SIZE_SMALL == 1
// Configuration.SCREENLAYOUT_SIZE_NORMAL == 2
// Configuration.SCREENLAYOUT_SIZE_LARGE == 3
// Configuration.SCREENLAYOUT_SIZE_XLARGE == 4
if (screenType == 1) {
    ...
} else if (screenType == 2) {
    ...
} else if (screenType == 3) {
    ...
} else if (screenType == 4) {
    ...
} else { // undefined
    ...
}

Jeff Gilfelt对静态助手方法的回答是:

private static String getSizeName(Context context) {
    int screenLayout = context.getResources().getConfiguration().screenLayout;
    screenLayout &= Configuration.SCREENLAYOUT_SIZE_MASK;

    switch (screenLayout) {
    case Configuration.SCREENLAYOUT_SIZE_SMALL:
        return "small";
    case Configuration.SCREENLAYOUT_SIZE_NORMAL:
        return "normal";
    case Configuration.SCREENLAYOUT_SIZE_LARGE:
        return "large";
    case 4: // Configuration.SCREENLAYOUT_SIZE_XLARGE is API >= 9
        return "xlarge";
    default:
        return "undefined";
    }
}

难道不能使用字符串资源和枚举来做到这一点吗?您可以定义一个字符串资源,该资源具有屏幕大小的名称,例如SMALL、MEDIUM或LARGE。然后,您可以使用string资源的值来创建枚举的实例。

Define an Enum in your code for the different screen sizes you care about. public Enum ScreenSize { SMALL, MEDIUM, LARGE,; } Define a string resource, say screensize, whose value will be either SMALL, MEDIUM, or LARGE. <string name="screensize">MEDIUM</string> Put a copy of screensize in a string resource in each dimension you care about. For example, <string name="screensize">MEDIUM</string> would go in values-sw600dp/strings.xml and values-medium/strings.xml and <string name="screensize">LARGE</string> would go in sw720dp/strings.xml and values-large/strings.xml. In code, write ScreenSize size = ScreenSize.valueOf(getReources().getString(R.string.screensize);