难道不能使用字符串资源和枚举来做到这一点吗?您可以定义一个字符串资源，该资源具有屏幕大小的名称，例如SMALL、MEDIUM或LARGE。然后，您可以使用string资源的值来创建枚举的实例。

Define an Enum in your code for the different screen sizes you care about. public Enum ScreenSize { SMALL, MEDIUM, LARGE,; } Define a string resource, say screensize, whose value will be either SMALL, MEDIUM, or LARGE. <string name="screensize">MEDIUM</string> Put a copy of screensize in a string resource in each dimension you care about. For example, <string name="screensize">MEDIUM</string> would go in values-sw600dp/strings.xml and values-medium/strings.xml and <string name="screensize">LARGE</string> would go in sw720dp/strings.xml and values-large/strings.xml. In code, write ScreenSize size = ScreenSize.valueOf(getReources().getString(R.string.screensize);

private String getDeviceDensity() {
    int density = mContext.getResources().getDisplayMetrics().densityDpi;
    switch (density)
    {
        case DisplayMetrics.DENSITY_MEDIUM:
            return "MDPI";
        case DisplayMetrics.DENSITY_HIGH:
            return "HDPI";
        case DisplayMetrics.DENSITY_LOW:
            return "LDPI";
        case DisplayMetrics.DENSITY_XHIGH:
            return "XHDPI";
        case DisplayMetrics.DENSITY_TV:
            return "TV";
        case DisplayMetrics.DENSITY_XXHIGH:
            return "XXHDPI";
        case DisplayMetrics.DENSITY_XXXHIGH:
            return "XXXHDPI";
        default:
            return "Unknown";
    }
}

试试这个函数isLayoutSizeAtLeast(int screenSize)

检查小屏幕，至少320x426 dp及以上 .getConfiguration getresource () () .isLayoutSizeAtLeast (Configuration.SCREENLAYOUT_SIZE_SMALL);

检查正常屏幕，至少320x470 dp及以上 .getConfiguration getresource () () .isLayoutSizeAtLeast (Configuration.SCREENLAYOUT_SIZE_NORMAL);

检查大屏幕，至少480x640 dp及以上 .getConfiguration getresource () () .isLayoutSizeAtLeast (Configuration.SCREENLAYOUT_SIZE_LARGE);

检查超大屏幕，至少720x960 dp及以上 .getConfiguration getresource () () .isLayoutSizeAtLeast (Configuration.SCREENLAYOUT_SIZE_XLARGE);

在2018年，如果你需要Jeff在Kotlin中的回答，下面是:

  private fun determineScreenSize(): String {
    // Thanks to https://stackoverflow.com/a/5016350/2563009.
    val screenLayout = resources.configuration.screenLayout
    return when {
      screenLayout and Configuration.SCREENLAYOUT_SIZE_MASK == Configuration.SCREENLAYOUT_SIZE_SMALL -> "Small"
      screenLayout and Configuration.SCREENLAYOUT_SIZE_MASK == Configuration.SCREENLAYOUT_SIZE_NORMAL -> "Normal"
      screenLayout and Configuration.SCREENLAYOUT_SIZE_MASK == Configuration.SCREENLAYOUT_SIZE_LARGE -> "Large"
      screenLayout and Configuration.SCREENLAYOUT_SIZE_MASK == Configuration.SCREENLAYOUT_SIZE_XLARGE -> "Xlarge"
      screenLayout and Configuration.SCREENLAYOUT_SIZE_MASK == Configuration.SCREENLAYOUT_SIZE_UNDEFINED -> "Undefined"
      else -> error("Unknown screenLayout: $screenLayout")
    }
  }

Jeff Gilfelt对静态助手方法的回答是:

private static String getSizeName(Context context) {
    int screenLayout = context.getResources().getConfiguration().screenLayout;
    screenLayout &= Configuration.SCREENLAYOUT_SIZE_MASK;

    switch (screenLayout) {
    case Configuration.SCREENLAYOUT_SIZE_SMALL:
        return "small";
    case Configuration.SCREENLAYOUT_SIZE_NORMAL:
        return "normal";
    case Configuration.SCREENLAYOUT_SIZE_LARGE:
        return "large";
    case 4: // Configuration.SCREENLAYOUT_SIZE_XLARGE is API >= 9
        return "xlarge";
    default:
        return "undefined";
    }
}

您可以使用配置。screenLayout位掩码。

例子:

if ((getResources().getConfiguration().screenLayout & 
    Configuration.SCREENLAYOUT_SIZE_MASK) == 
        Configuration.SCREENLAYOUT_SIZE_LARGE) {
    // on a large screen device ...

}