我需要做什么才能使Windows窗体应用程序能够在系统托盘中运行?
不是一个可以最小化到托盘的应用程序,而是一个只存在于托盘中的应用程序
一个图标 一个工具提示,和 一个“右键”菜单。
我需要做什么才能使Windows窗体应用程序能够在系统托盘中运行?
不是一个可以最小化到托盘的应用程序,而是一个只存在于托盘中的应用程序
一个图标 一个工具提示,和 一个“右键”菜单。
当前回答
这是一个非常友好的框架通知区域应用程序…将NotificationIcon添加到基本表单并将自动生成的代码更改为下面的代码就足够了:
public partial class Form1 : Form
{
private bool hidden = false;
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
this.ShowInTaskbar = false;
//this.WindowState = FormWindowState.Minimized;
this.Hide();
hidden = true;
}
private void notifyIcon1_Click(object sender, EventArgs e)
{
if (hidden) // this.WindowState == FormWindowState.Minimized)
{
// this.WindowState = FormWindowState.Normal;
this.Show();
hidden = false;
}
else
{
// this.WindowState = FormWindowState.Minimized;
this.Hide();
hidden = true;
}
}
}
其他回答
Create a new Windows Application with the wizard. Delete Form1 from the code. Remove the code in Program.cs starting up the Form1. Use the NotifyIcon class to create your system tray icon (assign an icon to it). Add a contextmenu to it. Or react to NotifyIcon's mouseclick and differenciate between Right and Left click, setting your contextmenu and showing it for which ever button (right/left) was pressed. Application.Run() to keep the app running with Application.Exit() to quit. Or a bool bRunning = true; while(bRunning){Application.DoEvents(); Thread.Sleep(10);}. Then set bRunning = false; to exit the app.
代码项目文章创建任务托盘应用程序给出了创建只存在于系统托盘中的应用程序的非常简单的解释和示例。
基本上改变应用程序。运行中(新Form1 ());来启动一个继承自ApplicationContext的类,并让该类的构造函数初始化一个NotifyIcon
static class Program
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new MyCustomApplicationContext());
}
}
public class MyCustomApplicationContext : ApplicationContext
{
private NotifyIcon trayIcon;
public MyCustomApplicationContext ()
{
// Initialize Tray Icon
trayIcon = new NotifyIcon()
{
Icon = Resources.AppIcon,
ContextMenu = new ContextMenu(new MenuItem[] {
new MenuItem("Exit", Exit)
}),
Visible = true
};
}
void Exit(object sender, EventArgs e)
{
// Hide tray icon, otherwise it will remain shown until user mouses over it
trayIcon.Visible = false;
Application.Exit();
}
}
据我所知,您仍然必须使用表单编写应用程序,但在表单上没有控件,并且永远不会将其设置为可见。使用NotifyIcon(可以在这里找到它的MSDN示例)来编写应用程序。
这是一个非常友好的框架通知区域应用程序…将NotificationIcon添加到基本表单并将自动生成的代码更改为下面的代码就足够了:
public partial class Form1 : Form
{
private bool hidden = false;
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
this.ShowInTaskbar = false;
//this.WindowState = FormWindowState.Minimized;
this.Hide();
hidden = true;
}
private void notifyIcon1_Click(object sender, EventArgs e)
{
if (hidden) // this.WindowState == FormWindowState.Minimized)
{
// this.WindowState = FormWindowState.Normal;
this.Show();
hidden = false;
}
else
{
// this.WindowState = FormWindowState.Minimized;
this.Hide();
hidden = true;
}
}
}
简单的添加
this.WindowState = FormWindowState.Minimized;
this.ShowInTaskbar = false;
到你的表单对象。 你只会在系统托盘上看到一个图标。