我需要做什么才能使Windows窗体应用程序能够在系统托盘中运行?

不是一个可以最小化到托盘的应用程序,而是一个只存在于托盘中的应用程序

一个图标 一个工具提示,和 一个“右键”菜单。


当前回答

在。net 6中,我必须像这样工作我的类的核心:

private NotifyIcon trayIcon;
private ContextMenuStrip contextMenu1;
private ToolStripMenuItem menuItem1;

public MyCustomApplicationContext()
{
    contextMenu1 = new System.Windows.Forms.ContextMenuStrip();
    menuItem1 = new System.Windows.Forms.ToolStripMenuItem();
    this.menuItem1.Text = "E&xit";
    this.menuItem1.Click += new System.EventHandler(Exit);
    this.contextMenu1.Items.AddRange(
            new System.Windows.Forms.ToolStripMenuItem[] {this.menuItem1 });
    trayIcon = new NotifyIcon(){Icon = Resources.AppIcon, ContextMenuStrip = this.contextMenu1, Visible = true };            

}

其他回答

我将接受的答案改编为。net Core,使用推荐的替换已弃用类:

腰椎->腰椎 ->工具箱

Program.cs

namespace TrayOnlyWinFormsDemo
{
    internal static class Program
    {
        [STAThread]
        static void Main()
        {
            ApplicationConfiguration.Initialize();
            Application.Run(new MyCustomApplicationContext());
        }
    }
}

MyCustomApplicationContext.cs

using TrayOnlyWinFormsDemo.Properties;  // Needed for Resources.AppIcon

namespace TrayOnlyWinFormsDemo
{
    public class MyCustomApplicationContext : ApplicationContext
    {
        private NotifyIcon trayIcon;

        public MyCustomApplicationContext()
        {
            trayIcon = new NotifyIcon()
            {
                Icon = Resources.AppIcon,
                ContextMenuStrip = new ContextMenuStrip()
                {
                    Items = { new ToolStripMenuItem("Exit", null, Exit) }
                },
                Visible = true
            };
        }

        void Exit(object? sender, EventArgs e)
        {
            trayIcon.Visible = false;
            Application.Exit();
        }
    }
}

Create a new Windows Application with the wizard. Delete Form1 from the code. Remove the code in Program.cs starting up the Form1. Use the NotifyIcon class to create your system tray icon (assign an icon to it). Add a contextmenu to it. Or react to NotifyIcon's mouseclick and differenciate between Right and Left click, setting your contextmenu and showing it for which ever button (right/left) was pressed. Application.Run() to keep the app running with Application.Exit() to quit. Or a bool bRunning = true; while(bRunning){Application.DoEvents(); Thread.Sleep(10);}. Then set bRunning = false; to exit the app.

据我所知,您仍然必须使用表单编写应用程序,但在表单上没有控件,并且永远不会将其设置为可见。使用NotifyIcon(可以在这里找到它的MSDN示例)来编写应用程序。

简单的添加

this.WindowState = FormWindowState.Minimized;
this.ShowInTaskbar = false;

到你的表单对象。 你只会在系统托盘上看到一个图标。

下面是我如何用Visual Studio 2010, .NET 4做到的

Create a Windows Forms Application, set 'Make single instance application' in properties Add a ContextMenuStrip Add some entries to the context menu strip, double click on them to get the handlers, for example, 'exit' (double click) -> handler -> me.Close() Add a NotifyIcon, in the designer set contextMenuStrip to the one you just created, pick an icon (you can find some in the VisualStudio folder under 'common7...') Set properties for the form in the designer: FormBorderStyle:none, ShowIcon:false, ShowInTaskbar:false, Opacity:0%, WindowState:Minimized Add Me.Visible=false at the end of Form1_Load, this will hide the icon when using Ctrl + Tab Run and adjust as needed.