使用正则表达式:

string test = "(test)"; 
string word = Regex.Match(test, @"\((\w+)\)").Groups[1].Value;
Console.WriteLine(word);

也许是正则表达式?我认为这行得通……

\(([a-z]+?)\)

我最近一直在使用和滥用c# 9，甚至在一些可疑的场景中，我也忍不住要加入span…只是为了好玩，以下是上述答案的变体:

var input = "User name (sales)";
var txtSpan = input.AsSpan();
var startPoint = txtSpan.IndexOf('(') + 1;
var length = txtSpan.LastIndexOf(')') - startPoint;
var output = txtSpan.Slice(startPoint, length);

对于OP的特定场景，它产生正确的输出。 (就我个人而言，我会使用其他人发布的RegEx。在上述解决方案崩溃的情况下，更容易解决更棘手的情况)。

我为自己的项目做了一个更好的版本(作为扩展方法):

//Note: This only captures the first occurrence, but 
//can be easily modified to scan across the text (I'd prefer Slicing a Span)  
public static string ExtractFromBetweenChars(this string txt, char openChar, char closeChar)
{
    ReadOnlySpan<char> span = txt.AsSpan();
    int firstCharPos = span.IndexOf(openChar);
    int lastCharPos = -1;

    if (firstCharPos != -1) 
    { 
        for (int n = firstCharPos + 1; n < span.Length; n++)
        {
            if (span[n] == openChar) firstCharPos = n; //This allows the opening char position to change
            if (span[n] == closeChar) lastCharPos = n;
            if (lastCharPos > firstCharPos) break;
            //This would correctly extract "sales" from this [contrived]
            //example: "just (a (name (sales) )))(test"
        }
        return span.Slice(firstCharPos + 1, lastCharPos - firstCharPos - 1).ToString();
    }
    return "";
}

正则表达式可能是这里最好的工具。如果你不熟悉它们，我建议你安装Expresso -一个很棒的小正则表达式工具。

喜欢的东西:

Regex regex = new Regex("\\((?<TextInsideBrackets>\\w+)\\)");
string incomingValue = "Username (sales)";
string insideBrackets = null;
Match match = regex.Match(incomingValue);
if(match.Success)
{
    insideBrackets = match.Groups["TextInsideBrackets"].Value;
}

input.Remove(input.IndexOf(')')).Substring(input.IndexOf('(') + 1);

使用正则表达式:

string test = "(test)"; 
string word = Regex.Match(test, @"\((\w+)\)").Groups[1].Value;
Console.WriteLine(word);