我想知道，如果有人知道一种方法，以删除显示在appBar在颤振应用程序，当你使用Navigator。pushNamed转到另一个页面。我不希望它出现在这个结果页面上的原因是它来自导航，我希望用户使用注销按钮，这样会话就可以重新开始。
当前回答
SliverAppBar ( automaticallyImplyLeading:假的,}
其他回答
//如果你想隐藏后退按钮使用下面的代码
class SecondScreen extends StatelessWidget {
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text('Remove Back Button'),
//hide back button
automaticallyImplyLeading: false,
),
body: Center(
child: Container(),
),
);
}
}
//如果你想隐藏后退按钮并停止弹出动作，使用下面的代码
class SecondScreen extends StatelessWidget {
@override
Widget build(BuildContext context) {
return new WillPopScope(
onWillPop: () async => false,
child: Scaffold(
appBar: AppBar(
title: Text("Second Screen"),
//For hide back button
automaticallyImplyLeading: false,
),
body: Center(
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
crossAxisAlignment: CrossAxisAlignment.center,
children: <Widget>[
RaisedButton(
child: Text('Back'),
onPressed: () {
Navigator.pop(context);
},
),
],
)
),
),
);
}
只是让它透明，没有行动，而现在
AppBar(
leading: IconButton(
icon: Icon(
Icons.arrow_back,
color: Colors.white.withOpacity(0),
),
onPressed: () {},
),
我认为解决办法如下
你实际上可以:
Don't want to display that ugly back button ( :] ), and thus go for : AppBar(...,automaticallyImplyLeading: false,...); Don't want the user to go back - replacing current view - and thus go for: Navigator.pushReplacementNamed(## your routename here ##); Don't want the user to go back - replacing a certain view back in the stack - and thus use: Navigator.pushNamedAndRemoveUntil(## your routename here ##, f(Route<dynamic>)→bool); where f is a function returning truewhen meeting the last view you want to keep in the stack (right before the new one); Don't want the user to go back - EVER - emptying completely the navigator stack with: Navigator.pushNamedAndRemoveUntil(context, ## your routename here ##, (_) => false);
在AppBar中删除后退按钮的一个简单方法是将automcallyimplyleading设置为false。
appBar: AppBar(
title: Text("App Bar without Back Button"),
automaticallyImplyLeading: false,
),
SliverAppBar ( automaticallyImplyLeading:假的,}
