@user110902发布的这个基于jquery的回答对我很有用。然而，我对它进行了一些改进，以防止@B_N的评论中提到的缺陷:当你按Shift时，它无法检测到CapsLock:

$('#example').keypress(function(e) { 
    var s = String.fromCharCode( e.which );
    if (( s.toUpperCase() === s && s.toLowerCase() !== s && !e.shiftKey )
    ||  ( s.toLowerCase() === s && s.toUpperCase() !== s && e.shiftKey )) {
        alert('caps is on');
    }
});

像这样，即使按下Shift，它也会工作。

试试这个简单的代码，容易理解

这是脚本

 <script language="Javascript">
function capLock(e){
 kc = e.keyCode?e.keyCode:e.which;
 sk = e.shiftKey?e.shiftKey:((kc == 16)?true:false);
 if(((kc >= 65 && kc <= 90) && !sk)||((kc >= 97 && kc <= 122) && sk))
  document.getElementById('divMayus').style.visibility = 'visible';
 else
   document.getElementById('divMayus').style.visibility = 'hidden';
}
</script>

还有Html

<input type="password" name="txtPassword" onkeypress="capLock(event)" />
 <div id="divMayus" style="visibility:hidden">Caps Lock is on.</div> 

有一个更简单的检测caps-lock的解决方案:

function isCapsLockOn(event) {
    var s = String.fromCharCode(event.which);
    if (s.toUpperCase() === s && s.toLowerCase() !== s && !event.shiftKey) {
        return true;
    }
}

所以我找到了这个页面，并不是很喜欢我找到的解决方案，所以我想出了一个，并把它提供给你们所有人。对我来说，只有当我输入字母时，大写锁才重要。这段代码为我解决了问题。它快速和简单，给你一个辣椒变量引用，只要你需要它。

let capsIsOn=false; let capsChecked=false; let capsCheck=(e)=>{ let letter=e.key; if(letter.length===1 && letter.match(/[A-Za-z]/)){ if(letter!==letter.toLowerCase()){ capsIsOn=true; console.log('caps is on'); }else{ console.log('caps is off'); } capsChecked=true; window.removeEventListener("keyup",capsCheck); }else{ console.log("not a letter, not capsCheck was performed"); } } window.addEventListener("keyup",capsCheck); window.addEventListener("keyup",(e)=>{ if(capsChecked && e.keyCode===20){ capsIsOn=!capsIsOn; } });

反应

onKeyPress(event) { 
        let self = this;
        self.setState({
            capsLock: isCapsLockOn(self, event)
        });
    }

    onKeyUp(event) { 
        let self = this;
        let key = event.key;
        if( key === 'Shift') {
            self.shift = false;
        }
    }

    <div>
     <input name={this.props.name} onKeyDown={(e)=>this.onKeyPress(e)} onKeyUp={(e)=>this.onKeyUp(e)} onChange={this.props.onChange}/>
                {this.capsLockAlert()}
</div>

function isCapsLockOn(component, event) {
        let key = event.key;
        let keyCode = event.keyCode;

        component.lastKeyPressed = key;

        if( key === 'Shift') {
            component.shift = true;
        } 

        if (key === 'CapsLock') {
            let newCapsLockState = !component.state.capsLock;
            component.caps = newCapsLockState;
            return newCapsLockState;
        } else {
            if ((component.lastKeyPressed !== 'Shift' && (key === key.toUpperCase() && (keyCode >= 65 && keyCode <= 90)) && !component.shift) || component.caps ) {
                component.caps = true;
                return true;
            } else {
                component.caps = false;
                return false;
            }
        }
    }

还有另一个版本，清晰而简单，处理移位的capsLock，并且不受ascii限制，我认为:

document.onkeypress = function (e)
{
    e = e || window.event;
    if (e.charCode === 0 || e.ctrlKey || document.onkeypress.punctuation.indexOf(e.charCode) >= 0)
        return;
    var s = String.fromCharCode(e.charCode); // or e.keyCode for compatibility, but then have to handle MORE non-character keys
    var s2 = e.shiftKey ? s.toUpperCase() : s.toLowerCase();
    var capsLockOn = (s2 !== s);
    document.getElementById('capslockWarning').style.display = capsLockOn ? '' : 'none';
}
document.onkeypress.punctuation = [33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,91,92,93,94,95,96,123,124,125,126];

编辑:意义上的capsLockOn被逆转，多，固定。

编辑#2:在进一步检查之后，我做了一些更改，不幸的是，代码更详细了一些，但它可以适当地处理更多的操作。

Using e.charCode instead of e.keyCode and checking for 0 values skips a lot of non-character keypresses, without coding anything specific to a given language or charset. From my understanding, it's slightly less compatible, so older, non-mainstream, or mobile browsers may not behave as this code expects, but it's worth it, for my situation anyway. Checking against a list of known punctuation codes prevents them from being seen as false negatives, since they're not affected by caps lock. Without this, the caps lock indicator gets hidden when you type any of those punctuation characters. By specifying an excluded set, rather than an included one, it should be more compatible with extended characters. This is the ugliest, special-casiest bit, and there's some chance that non-Western languages have different enough punctuation and/or punctuation codes to be a problem, but again it's worth it IMO, at least for my situation.